{"id":221357,"date":"2025-05-29T12:34:39","date_gmt":"2025-05-29T12:34:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221357"},"modified":"2025-05-29T12:34:41","modified_gmt":"2025-05-29T12:34:41","slug":"what-are-the-molecular-weight-and-the-equivalent-weight-of-h3po4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/29\/what-are-the-molecular-weight-and-the-equivalent-weight-of-h3po4\/","title":{"rendered":"What are the molecular weight and the equivalent weight of h3PO4"},"content":{"rendered":"\n<p>What are the molecular weight and the equivalent weight of h3PO4<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molecular Weight of H\u2083PO\u2084 (Phosphoric Acid)<\/strong>: 97.99 g\/mol<\/li>\n\n\n\n<li><strong>Equivalent Weight of H\u2083PO\u2084<\/strong>: 32.66 g\/equiv (for one acidic hydrogen)<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p><strong>Phosphoric acid (H\u2083PO\u2084)<\/strong> is a triprotic acid, meaning it has <strong>three ionizable hydrogen atoms<\/strong>. To understand its molecular and equivalent weights, we need to break down its chemical composition and acidic properties.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. Molecular Weight:<\/strong><\/h4>\n\n\n\n<p>The <strong>molecular weight<\/strong> is the sum of the atomic weights of all atoms in a molecule. For H\u2083PO\u2084:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Hydrogen (H): 1.008 \u00d7 3 = 3.024<\/li>\n\n\n\n<li>Phosphorus (P): 30.97 \u00d7 1 = 30.97<\/li>\n\n\n\n<li>Oxygen (O): 16.00 \u00d7 4 = 64.00<\/li>\n<\/ul>\n\n\n\n<p><strong>Total molecular weight<\/strong> = 3.024 + 30.97 + 64.00 = <strong>97.994 g\/mol<\/strong>, often rounded to <strong>97.99 g\/mol<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. Equivalent Weight:<\/strong><\/h4>\n\n\n\n<p>The <strong>equivalent weight<\/strong> of an acid is defined as: Equivalent&nbsp;weight=Molecular&nbsp;weightBasicity\\text{Equivalent weight} = \\frac{\\text{Molecular weight}}{\\text{Basicity}}<\/p>\n\n\n\n<p><strong>Basicity<\/strong> is the number of replaceable hydrogen ions (H\u207a) an acid can donate in a reaction. For H\u2083PO\u2084:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>It is <strong>triprotic<\/strong> (basicity = 3), so it can donate up to three protons.<\/li>\n\n\n\n<li>Depending on the reaction or the stage of neutralization, the equivalent weight can change.\n<ul class=\"wp-block-list\">\n<li>For full neutralization (donating all 3 H\u207a): 97.993=32.66\u00a0g\/equiv\\frac{97.99}{3} = 32.66 \\text{ g\/equiv}<\/li>\n\n\n\n<li>For donating only one H\u207a (e.g., in reactions with weak bases), the equivalent weight is the <strong>same as the molecular weight<\/strong>, i.e., 97.99 g\/equiv.<img decoding=\"async\" src=\"file:\/\/\/C:\/Users\/Administrator\/Pictures\/learnexams%20banner7.jpeg\"><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p><strong>Typically<\/strong>, in titration or stoichiometry problems, the equivalent weight is calculated based on <strong>full neutralization<\/strong> unless otherwise specified. Hence, the <strong>equivalent weight of H\u2083PO\u2084 is 32.66 g\/equiv<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molecular weight<\/strong>: 97.99 g\/mol<\/li>\n\n\n\n<li><strong>Equivalent weight<\/strong> (full neutralization): 32.66 g\/equiv<br>Understanding these values is critical in chemistry for calculations involving titration, stoichiometry, and reaction balancing.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner7-99.jpeg\" alt=\"\" class=\"wp-image-221358\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What are the molecular weight and the equivalent weight of h3PO4 The Correct Answer and Explanation is: Correct Answer: Explanation Phosphoric acid (H\u2083PO\u2084) is a triprotic acid, meaning it has three ionizable hydrogen atoms. To understand its molecular and equivalent weights, we need to break down its chemical composition and acidic properties. 1. Molecular Weight: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221357","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221357","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221357"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221357\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221357"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221357"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221357"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}