{"id":221514,"date":"2025-05-29T18:19:22","date_gmt":"2025-05-29T18:19:22","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221514"},"modified":"2025-05-29T18:19:24","modified_gmt":"2025-05-29T18:19:24","slug":"calculate-the-mass-percent-of-water-in-nicl26h2o","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/29\/calculate-the-mass-percent-of-water-in-nicl26h2o\/","title":{"rendered":"\u00a0Calculate the mass percent of water in NiCl2:6H2O"},"content":{"rendered":"\n<p>&nbsp;Calculate the mass percent of water in NiCl2:6H2O. 8. Calculate the mass of water present in 4.50 g of Ba(OH)2 2H2O. 9. Name this compound, Ca(NO3)2:4H20<br><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 1: Mass percent of water in NiCl\u2082\u00b76H\u2082O<\/strong><\/h3>\n\n\n\n<p>First, calculate the molar mass of each component:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ni: 58.69 g\/mol<\/li>\n\n\n\n<li>Cl\u2082: 2 \u00d7 35.45 = 70.90 g\/mol<\/li>\n\n\n\n<li>H\u2082O: 6 \u00d7 (2.02 + 16.00) = 6 \u00d7 18.02 = <strong>108.12 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>Total molar mass<\/strong> = 58.69 + 70.90 + 108.12 = <strong>237.71 g\/mol<\/strong><br><strong>Mass percent of water<\/strong> = (108.12 \/ 237.71) \u00d7 100% = <strong>45.5%<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 2: Mass of water in 4.50 g of Ba(OH)\u2082\u00b72H\u2082O<\/strong><\/h3>\n\n\n\n<p>Calculate the molar mass:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ba: 137.33 g\/mol<\/li>\n\n\n\n<li>O\u2082H\u2082: 2 \u00d7 (16.00 + 1.01) = 34.02 g\/mol<\/li>\n\n\n\n<li>H\u2082O: 2 \u00d7 18.02 = <strong>36.04 g\/mol<\/strong><br><strong>Total molar mass<\/strong> = 137.33 + 34.02 + 36.04 = <strong>207.39 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Mass percent of water = (36.04 \/ 207.39) \u00d7 100% = <strong>17.38%<\/strong><br>Mass of water in 4.50 g = 4.50 \u00d7 0.1738 = <strong>0.782 g<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 3: Name of Ca(NO\u2083)\u2082\u00b74H\u2082O<\/strong><\/h3>\n\n\n\n<p>This is <strong>calcium nitrate tetrahydrate<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong> Explanation<\/strong><\/h3>\n\n\n\n<p>Hydrated compounds are salts that contain water molecules in their crystal structure. This water is known as &#8220;water of hydration.&#8221; The notation for these compounds often uses a dot to separate the salt from the water, such as in NiCl\u2082\u00b76H\u2082O. This means six water molecules are associated with each formula unit of nickel(II) chloride.<\/p>\n\n\n\n<p>To find the <strong>mass percent of water<\/strong>, we calculate the mass of the water portion and divide it by the total molar mass of the hydrate. For NiCl\u2082\u00b76H\u2082O, water makes up 108.12 grams of its total 237.71 g\/mol molar mass, giving a mass percent of 45.5%. This is useful in stoichiometry and chemical preparation where precise water content matters.<\/p>\n\n\n\n<p>Next, to determine the <strong>mass of water in a sample<\/strong>, such as 4.50 g of Ba(OH)\u2082\u00b72H\u2082O, we first compute the percent composition of water (17.38%). Multiplying this by the sample mass gives us 0.782 g of water in 4.50 g of the compound.<\/p>\n\n\n\n<p>Finally, <strong>naming hydrated compounds<\/strong> follows standard IUPAC rules: the ionic compound is named first (e.g., calcium nitrate), followed by a prefix indicating the number of water molecules (e.g., &#8220;tetrahydrate&#8221; for four). Therefore, Ca(NO\u2083)\u2082\u00b74H\u2082O is named <strong>calcium nitrate tetrahydrate<\/strong>.<\/p>\n\n\n\n<p>Understanding hydrates is crucial in chemistry, especially in laboratory analysis and industrial applications where accurate water content affects both chemical behavior and product quality.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner4-110.jpeg\" alt=\"\" class=\"wp-image-221515\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>&nbsp;Calculate the mass percent of water in NiCl2:6H2O. 8. Calculate the mass of water present in 4.50 g of Ba(OH)2 2H2O. 9. Name this compound, Ca(NO3)2:4H20 The Correct Answer and Explanation is: Question 1: Mass percent of water in NiCl\u2082\u00b76H\u2082O First, calculate the molar mass of each component: Total molar mass = 58.69 + 70.90 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221514","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221514","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221514"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221514\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221514"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221514"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221514"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}