{"id":221763,"date":"2025-05-30T13:56:09","date_gmt":"2025-05-30T13:56:09","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221763"},"modified":"2025-05-30T13:56:11","modified_gmt":"2025-05-30T13:56:11","slug":"draw-the-lewis-structure-of-the","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/30\/draw-the-lewis-structure-of-the\/","title":{"rendered":"Draw the Lewis structure of the"},"content":{"rendered":"\n<p>Draw the Lewis structure of the 1:1 adduct that forms in the Lewis acid-base reaction between antimony tribromide (SbBr3) and bromide ion (Br-). Explicitly draw all H atoms. Include all valence lone pairs in your answer. Do not include charges in your answer. They will not be considered in the grading. In cases where there is more than one answer, just draw one.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Structure of the 1:1 Adduct of SbBr\u2083 and Br\u207b:<\/h3>\n\n\n\n<p>Here is the correct Lewis structure:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>             ..\n             :\n     Br:   Br\u2014Sb\u2014Br\n             |\n            Br\n             :\n             ..\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>Sb<\/strong> (antimony) atom is at the center, bonded to <strong>four<\/strong> bromine atoms.<\/li>\n\n\n\n<li>Three of the Br atoms are from the original <strong>SbBr\u2083<\/strong> molecule.<\/li>\n\n\n\n<li>One Br\u207b acts as a <strong>Lewis base<\/strong>, donating a lone pair to Sb.<\/li>\n\n\n\n<li>All Br atoms have <strong>three lone pairs<\/strong> of electrons shown as pairs of dots (: or ..).<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>The reaction involves a <strong>Lewis acid-base interaction<\/strong>. A <strong>Lewis acid<\/strong> is an electron pair acceptor, while a <strong>Lewis base<\/strong> is an electron pair donor.<\/p>\n\n\n\n<p><strong>Antimony tribromide (SbBr\u2083)<\/strong> has a trigonal pyramidal geometry and an incomplete octet (only six valence electrons around Sb in bonding). This makes it <strong>electron-deficient<\/strong> and allows it to act as a Lewis acid. The central Sb atom has an empty 5p orbital that can accept an electron pair.<\/p>\n\n\n\n<p>The <strong>bromide ion (Br\u207b)<\/strong> has a full octet and carries a lone pair on its valence shell, making it a strong <strong>Lewis base<\/strong>.<\/p>\n\n\n\n<p>When Br\u207b donates its lone pair to SbBr\u2083, it forms a coordinate covalent (dative) bond. The result is a <strong>tetrahedral<\/strong> adduct, where Sb is now surrounded by <strong>four Br atoms<\/strong> \u2014 the original three plus the donated Br\u207b. This gives antimony a complete octet (8 electrons: 4 bonding pairs = 8 electrons).<\/p>\n\n\n\n<p>In the Lewis structure:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each Br has <strong>three lone pairs<\/strong>.<\/li>\n\n\n\n<li>The added Br\u207b binds to Sb using one of its lone pairs.<\/li>\n\n\n\n<li>The structure doesn&#8217;t include formal charges because they aren&#8217;t required here.<\/li>\n<\/ul>\n\n\n\n<p>This adduct is stabilized because the central Sb atom achieves a stable octet configuration through the donation from the bromide ion. This behavior is typical of <strong>Group 15 halides<\/strong>, which often form such adducts with halide ions or other Lewis bases.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner4-129.jpeg\" alt=\"\" class=\"wp-image-221764\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Lewis structure of the 1:1 adduct that forms in the Lewis acid-base reaction between antimony tribromide (SbBr3) and bromide ion (Br-). Explicitly draw all H atoms. Include all valence lone pairs in your answer. Do not include charges in your answer. They will not be considered in the grading. In cases where there [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221763","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221763","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221763"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221763\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221763"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221763"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221763"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}