{"id":221953,"date":"2025-05-30T18:21:13","date_gmt":"2025-05-30T18:21:13","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221953"},"modified":"2025-05-30T18:21:15","modified_gmt":"2025-05-30T18:21:15","slug":"sodium-bromide-nabrs-a-strong-electrolyte-express-your-answer-as-a-chemical-equation-including-phases","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/30\/sodium-bromide-nabrs-a-strong-electrolyte-express-your-answer-as-a-chemical-equation-including-phases\/","title":{"rendered":"Sodium bromide, NaBr(s), a strong electrolyte Express your answer as a chemical equation including phases."},"content":{"rendered":"\n<p>sodium bromide, NaBr(s), a strong electrolyte Express your answer as a chemical equation including phases. Provide a balanced equation for the tydration of each of the tollowing compounds. Part B lactio acid, HC<\/p>\n\n\n\n<p>3<\/p>\n\n\n\n<p>?<\/p>\n\n\n\n<p>H<\/p>\n\n\n\n<p>5<\/p>\n\n\n\n<p>?<\/p>\n\n\n\n<p>O(O (a), a weak electrolyte Express your answer as a chemical equation including phases. A chomical reaction does not occur for this quevian &#8211; Partc Express yout answet as a chemical<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/image-547.png\" alt=\"\" class=\"wp-image-221954\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Part A: Sodium bromide, NaBr(s), a strong electrolyte<\/strong><\/h3>\n\n\n\n<p><strong>Balanced equation:<\/strong> NaBr(s)\u2192H2ONa+(aq)+Br\u2212(aq)\\text{NaBr}(s) \\xrightarrow{H_2O} \\text{Na}^+(aq) + \\text{Br}^-(aq)<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>Sodium bromide is a strong electrolyte, which means it completely dissociates into its constituent ions when dissolved in water. When solid NaBr is added to water, it dissociates into sodium ions (Na\u207a) and bromide ions (Br\u207b). These ions become surrounded by water molecules in a process known as hydration. The (aq) symbol indicates that the ions are in aqueous solution, i.e., surrounded by water molecules. No molecular NaBr remains in solution.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Part B: Lactic acid, HC\u2083H\u2085O\u2083(aq), a weak electrolyte<\/strong><\/h3>\n\n\n\n<p><strong>Balanced equation:<\/strong> HC3H5O3(aq)\u21ccH+(aq)+C3H5O3\u2212(aq)\\text{HC}_3\\text{H}_5\\text{O}_3(aq) \\rightleftharpoons \\text{H}^+(aq) + \\text{C}_3\\text{H}_5\\text{O}_3^-(aq)<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>Lactic acid is a <strong>weak electrolyte<\/strong>, meaning it only partially ionizes in water. When lactic acid dissolves, only some molecules donate a proton (H\u207a), forming lactate ions (C\u2083H\u2085O\u2083\u207b). The majority of the lactic acid remains as intact molecules. The equilibrium arrow (\u21cc) shows that this is a reversible reaction and does not go to completion. This partial ionization is typical of weak acids in aqueous solution.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Part C: Dextrose (D-glucose), C\u2086H\u2081\u2082O\u2086(s), a nonelectrolyte<\/strong><\/h3>\n\n\n\n<p><strong>Balanced equation:<\/strong> C6H12O6(s)\u2192H2OC6H12O6(aq)\\text{C}_6\\text{H}_{12}\\text{O}_6(s) \\xrightarrow{H_2O} \\text{C}_6\\text{H}_{12}\\text{O}_6(aq)<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>Dextrose (glucose) is a <strong>nonelectrolyte<\/strong>, which means it does <strong>not<\/strong> dissociate into ions in water. When dextrose dissolves, the solid C\u2086H\u2081\u2082O\u2086 simply disperses into individual molecules that are surrounded by water molecules (hydrated), but no ions are formed. Thus, the formula remains the same before and after dissolution\u2014just the phase changes from solid to aqueous. No chemical reaction occurs.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Summary (Key Points for Understanding):<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Strong electrolytes<\/strong> dissociate completely (e.g., NaBr).<\/li>\n\n\n\n<li><strong>Weak electrolytes<\/strong> dissociate partially and reach equilibrium (e.g., lactic acid).<\/li>\n\n\n\n<li><strong>Nonelectrolytes<\/strong> dissolve without ionizing (e.g., glucose).<\/li>\n\n\n\n<li><strong>Hydration<\/strong> refers to the process of water molecules surrounding ions or molecules in solution.<\/li>\n\n\n\n<li>These hydration equations are essential for understanding electrical conductivity in solutions and acid\/base behavior.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner5-147.jpeg\" alt=\"\" class=\"wp-image-221955\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>sodium bromide, NaBr(s), a strong electrolyte Express your answer as a chemical equation including phases. Provide a balanced equation for the tydration of each of the tollowing compounds. Part B lactio acid, HC 3 ? H 5 ? O(O (a), a weak electrolyte Express your answer as a chemical equation including phases. A chomical reaction [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221953","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221953","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221953"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221953\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221953"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221953"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221953"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}