{"id":221993,"date":"2025-05-30T19:21:45","date_gmt":"2025-05-30T19:21:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=221993"},"modified":"2025-05-30T19:21:47","modified_gmt":"2025-05-30T19:21:47","slug":"determine-the-number-of-electron-groups-around-the-central-atom-for-each-of-the-following-molecules","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/30\/determine-the-number-of-electron-groups-around-the-central-atom-for-each-of-the-following-molecules\/","title":{"rendered":"Determine the number of electron groups around the central atom for each of the following molecules."},"content":{"rendered":"\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/image-548-1024x561.png\" alt=\"\" class=\"wp-image-221994\"\/><\/figure>\n\n\n\n<p><img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/cdn\/qimg\/60d7631b-cc3e-4b87-8579-de78acb4fc43.png\">Determine the number of electron groups around the central atom for each of the following molecules. Part C CS\u00e2\u201a\u201a Express your answer as an integer. n = Submit Part D [\u00ce\u00ab\u00ce\u00a0 \u00ce\u2018\u00ce\u00a3\u00ce\u00a6 n = CH4 Express your answer as an integer. Request Answer IVE \u00ce\u2018\u00ce\u00a3\u00ce\u00a6 Submit Request Answer ? ?<br><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answers:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Part C (CS\u2082):<\/strong> n = <strong>2<\/strong><\/li>\n\n\n\n<li><strong>Part D (CH\u2084):<\/strong> n = <strong>4<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In chemistry, <strong>electron groups<\/strong> around the central atom refer to regions where electrons are found \u2014 either as bonding pairs (single, double, or triple bonds all count as <em>one<\/em> electron group each) or as lone (non-bonding) pairs. The concept is essential for predicting molecular geometry using <strong>VSEPR theory<\/strong> (Valence Shell Electron Pair Repulsion theory).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Part C: <strong>CS\u2082 (Carbon Disulfide)<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">Lewis Structure:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central atom is <strong>carbon<\/strong>.<\/li>\n\n\n\n<li>Each sulfur atom forms a <strong>double bond<\/strong> with the central carbon, giving a structure of S=C=S.<\/li>\n\n\n\n<li>Carbon has no lone pairs.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Electron Group Count:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each double bond (C=S) counts as <strong>one electron group<\/strong>.<\/li>\n\n\n\n<li>Total: <strong>2 double bonds<\/strong> \u2192 <strong>2 electron groups<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Molecular Geometry:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>With 2 electron groups, the shape is <strong>linear<\/strong>.<\/li>\n\n\n\n<li>Bond angle: approximately <strong>180\u00b0<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Summary:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Electron groups:<\/strong> 2<\/li>\n\n\n\n<li><strong>Reason:<\/strong> Two double bonds from carbon to sulfur, each counted as one group.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Part D: <strong>CH\u2084 (Methane)<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">Lewis Structure:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central atom is <strong>carbon<\/strong>.<\/li>\n\n\n\n<li>It forms <strong>four single bonds<\/strong> with four hydrogen atoms.<\/li>\n\n\n\n<li>Carbon has no lone pairs.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Electron Group Count:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each single bond counts as <strong>one electron group<\/strong>.<\/li>\n\n\n\n<li>Total: <strong>4 single bonds<\/strong> \u2192 <strong>4 electron groups<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Molecular Geometry:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>With 4 electron groups, the shape is <strong>tetrahedral<\/strong>.<\/li>\n\n\n\n<li>Bond angle: approximately <strong>109.5\u00b0<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Summary:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Electron groups:<\/strong> 4<\/li>\n\n\n\n<li><strong>Reason:<\/strong> Four bonding pairs (single bonds) around the central carbon atom.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>Understanding electron group counts helps in predicting <strong>molecular shape<\/strong>, <strong>bond angles<\/strong>, and <strong>polarity<\/strong> \u2014 all fundamental concepts in molecular geometry and bonding theory<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner4-153.jpeg\" alt=\"\" class=\"wp-image-221995\"\/><\/figure>\n\n\n\n<p>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Determine the number of electron groups around the central atom for each of the following molecules. Part C CS\u00e2\u201a\u201a Express your answer as an integer. n = Submit Part D [\u00ce\u00ab\u00ce\u00a0 \u00ce\u2018\u00ce\u00a3\u00ce\u00a6 n = CH4 Express your answer as an integer. Request Answer IVE \u00ce\u2018\u00ce\u00a3\u00ce\u00a6 Submit Request Answer ? ? The Correct Answer and Explanation [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-221993","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221993","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=221993"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/221993\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=221993"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=221993"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=221993"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}