{"id":222020,"date":"2025-05-30T19:50:48","date_gmt":"2025-05-30T19:50:48","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=222020"},"modified":"2025-05-30T19:50:50","modified_gmt":"2025-05-30T19:50:50","slug":"assign-the-correct-oxidation-number-of-the-individual-atom-in-the-compound-or-ion-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/30\/assign-the-correct-oxidation-number-of-the-individual-atom-in-the-compound-or-ion-below\/","title":{"rendered":"Assign the correct oxidation number of the individual atom in the compound or ion below."},"content":{"rendered":"\n<p>DIRECTIONS: Assign the correct oxidation number of the individual atom in the compound or ion below. ANSWER IT ALL BELOW.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>S in S8<\/li>\n\n\n\n<li>Cl in CaCl2<\/li>\n\n\n\n<li>I in IO3<\/li>\n\n\n\n<li>C in HCO3<\/li>\n\n\n\n<li>S in FE2(SO2)3<\/li>\n\n\n\n<li>S in SO42-<\/li>\n\n\n\n<li>S in Na2SO4<\/li>\n\n\n\n<li>As in K3AsO4<\/li>\n\n\n\n<li>Cr in Cr2O72-<\/li>\n\n\n\n<li>N in NH4+<\/li>\n<\/ol>\n\n\n\n<p>NOT A GRADED QUESTION. IT IS A RESEARCH QUESTION.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the <strong>oxidation numbers<\/strong> for each specified atom, along with a 300-word explanation:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Answers:<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>S in S\u2088<\/strong>: <strong>0<\/strong><\/li>\n\n\n\n<li><strong>Cl in CaCl\u2082<\/strong>: <strong>\u20131<\/strong><\/li>\n\n\n\n<li><strong>I in IO\u2083\u207b<\/strong>: <strong>+5<\/strong><\/li>\n\n\n\n<li><strong>C in HCO\u2083\u207b<\/strong>: <strong>+4<\/strong><\/li>\n\n\n\n<li><strong>S in Fe\u2082(SO\u2082)\u2083<\/strong>: <strong>+4<\/strong><\/li>\n\n\n\n<li><strong>S in SO\u2084\u00b2\u207b<\/strong>: <strong>+6<\/strong><\/li>\n\n\n\n<li><strong>S in Na\u2082SO\u2084<\/strong>: <strong>+6<\/strong><\/li>\n\n\n\n<li><strong>As in K\u2083AsO\u2084<\/strong>: <strong>+5<\/strong><\/li>\n\n\n\n<li><strong>Cr in Cr\u2082O\u2087\u00b2\u207b<\/strong>: <strong>+6<\/strong><\/li>\n\n\n\n<li><strong>N in NH\u2084\u207a<\/strong>: <strong>\u20133<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>Oxidation numbers help keep track of electrons in chemical reactions, especially redox (oxidation-reduction) reactions. They are assigned based on a set of standard rules:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Pure elements<\/strong>, like <strong>S in S\u2088<\/strong>, have oxidation numbers of <strong>0<\/strong>.<\/li>\n\n\n\n<li>In <strong>ionic compounds<\/strong> like <strong>CaCl\u2082<\/strong>, calcium (a Group 2 metal) is <strong>+2<\/strong>, and each Cl is <strong>\u20131<\/strong>.<\/li>\n\n\n\n<li>In <strong>polyatomic ions<\/strong>, we assign known oxidation numbers first (e.g., O is usually <strong>\u20132<\/strong>) and solve for the unknown:\n<ul class=\"wp-block-list\">\n<li>For <strong>IO\u2083\u207b<\/strong>, 3(\u20132) + x = \u20131 \u2192 x = <strong>+5<\/strong> for I.<\/li>\n\n\n\n<li>In <strong>HCO\u2083\u207b<\/strong>, H is <strong>+1<\/strong>, O is <strong>\u20132<\/strong>, and solving gives C as <strong>+4<\/strong>.<\/li>\n\n\n\n<li>For <strong>SO\u2082\u00b2\u207b<\/strong> in <strong>Fe\u2082(SO\u2082)\u2083<\/strong>, assume O is <strong>\u20132<\/strong>, giving S as <strong>+4<\/strong>.<\/li>\n\n\n\n<li><strong>SO\u2084\u00b2\u207b<\/strong> has S as <strong>+6<\/strong> because 4(\u20132) + x = \u20132 \u2192 x = +6.<\/li>\n\n\n\n<li>In <strong>Na\u2082SO\u2084<\/strong>, Na is <strong>+1<\/strong>, and since there are two Na\u207a, the SO\u2084\u00b2\u207b must balance as \u20132, confirming S is still <strong>+6<\/strong>.<\/li>\n\n\n\n<li>In <strong>K\u2083AsO\u2084<\/strong>, K is <strong>+1<\/strong>, and O is <strong>\u20132<\/strong>; solving gives As = <strong>+5<\/strong>.<\/li>\n\n\n\n<li><strong>Cr\u2082O\u2087\u00b2\u207b<\/strong> has total charge \u20132; 7 O = \u201314, so 2Cr must be +12 \u2192 Cr = <strong>+6<\/strong>.<\/li>\n\n\n\n<li>In <strong>NH\u2084\u207a<\/strong>, H is +1; 4(+1) + x = +1 \u2192 x = <strong>\u20133<\/strong> for N.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Understanding oxidation states helps chemists identify electron flow, predict reactions, and balance redox equations efficiently.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/05\/learnexams-banner4-157.jpeg\" alt=\"\" class=\"wp-image-222021\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>DIRECTIONS: Assign the correct oxidation number of the individual atom in the compound or ion below. ANSWER IT ALL BELOW. NOT A GRADED QUESTION. IT IS A RESEARCH QUESTION. The Correct Answer and Explanation is: Here are the oxidation numbers for each specified atom, along with a 300-word explanation: Answers: Explanation Oxidation numbers help keep [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-222020","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222020","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=222020"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222020\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=222020"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=222020"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=222020"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}