{"id":222309,"date":"2025-05-31T08:28:08","date_gmt":"2025-05-31T08:28:08","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=222309"},"modified":"2025-05-31T08:28:10","modified_gmt":"2025-05-31T08:28:10","slug":"ch1202-3000-2000-1000-4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/31\/ch1202-3000-2000-1000-4\/","title":{"rendered":"CH1202 3000 2000 1000 4."},"content":{"rendered":"\n

1E. CH1202 3000 2000 1000 4. PUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU 2.0 3. Wwwpo W Stand Wh Ards In Their Teatro LL 100 For Each Do The Following: Calculate The Index Of Hydrogen Deficiency (IHD), Label Each Spectra As The TYPE Of Spectra It Is, Label The Significant Peaks In Each Spectra, Determine The Structure And Draw A Box Around It.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is<\/mark><\/strong>:<\/p>\n\n\n\n

To solve this structure elucidation problem, we’ll go through each step using the molecular formula C\u2088H\u2081\u2082O\u2082<\/strong> and analyze the provided IR, \u00b9H NMR, and mass spectra.<\/p>\n\n\n\n

\n\n\n\n

1. Index of Hydrogen Deficiency (IHD):<\/strong><\/h3>\n\n\n\n

Formula:<\/strong> IHD=2C+2\u2212H2=2(8)+2\u2212122=62=3\\text{IHD} = \\frac{2C + 2 – H}{2} = \\frac{2(8) + 2 – 12}{2} = \\frac{6}{2} = 3<\/p>\n\n\n\n

IHD = 3<\/strong>, suggesting combinations of rings and\/or double bonds (e.g., one ring and two double bonds, or one aromatic ring).<\/p>\n\n\n\n

\n\n\n\n

2. Spectra Identification:<\/strong><\/h3>\n\n\n\n

Top: Infrared (IR) Spectrum<\/strong><\/h4>\n\n\n\n
    \n
  • Broad peak near 3400 cm\u207b\u00b9<\/strong>: O\u2013H stretch (likely alcohol)<\/li>\n\n\n\n
  • Sharp peak near 1700 cm\u207b\u00b9<\/strong>: C=O stretch (carbonyl)<\/li>\n\n\n\n
  • Peaks near 1200 cm\u207b\u00b9<\/strong>: C\u2013O stretch<\/li>\n<\/ul>\n\n\n\n

    Conclusion:<\/strong> The compound contains both an alcohol and a carbonyl<\/strong> group, likely a carboxylic acid or ester.<\/p>\n\n\n\n

    \n\n\n\n

    Middle: \u00b9H NMR Spectrum<\/strong><\/h4>\n\n\n\n

    Key peaks:<\/p>\n\n\n\n

      \n
    • ~4.1 ppm (quartet)<\/strong>: \u2013CH\u2082\u2013 near an electronegative atom (likely O)<\/li>\n\n\n\n
    • ~1.2 ppm (triplet)<\/strong>: \u2013CH\u2083 group next to \u2013CH\u2082\u2013 (suggests ethyl group)<\/li>\n\n\n\n
    • ~2.0 ppm (singlet)<\/strong>: CH\u2083\u2013CO\u2013 (methyl ketone or ester)<\/li>\n\n\n\n
    • ~7.2 ppm (multiplet)<\/strong>: Aromatic protons (4H, monosubstituted benzene ring)<\/li>\n<\/ul>\n\n\n\n

      Conclusion:<\/strong> Signals are consistent with:<\/p>\n\n\n\n

        \n
      • Ethyl ester group (triplet\/quartet)<\/li>\n\n\n\n
      • Aromatic ring with 4H (suggesting a disubstituted benzene)<\/li>\n\n\n\n
      • Possibly para-disubstituted<\/li>\n<\/ul>\n\n\n\n
        \n\n\n\n

        Bottom: Mass Spectrum<\/strong><\/h4>\n\n\n\n
          \n
        • Base peak at m\/z = 105<\/strong>: Benzoyl fragment (C\u2086H\u2085\u2013CO\u207a)<\/li>\n\n\n\n
        • Molecular ion peak (M\u207a) at m\/z = 140<\/strong>, matches C\u2088H\u2081\u2082O\u2082<\/strong><\/li>\n<\/ul>\n\n\n\n
          \n\n\n\n

          3. Proposed Structure:<\/strong><\/h3>\n\n\n\n

          Ethyl 4-hydroxybenzoate<\/strong><\/p>\n\n\n\n

            \n
          • Benzene ring with OH at para position to an ester<\/li>\n\n\n\n
          • Explains IHD (aromatic ring = 4, minus symmetry)<\/li>\n\n\n\n
          • IR: C=O and O\u2013H<\/li>\n\n\n\n
          • NMR: Aromatic 4H, ethyl group, OH (broad singlet)<\/li>\n<\/ul>\n\n\n\n
            \n\n\n\n

            \u2705 Final Answer:<\/h3>\n\n\n\n

            Structure: Ethyl 4-hydroxybenzoate<\/strong><\/p>\n\n\n\n

            (Structure would include a benzene ring with a hydroxyl group at the para position and an ethyl ester at the opposite para position)<\/p>\n\n\n\n

            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

            1E. CH1202 3000 2000 1000 4. PUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU 2.0 3. Wwwpo W Stand Wh Ards In Their Teatro LL 100 For Each Do The Following: Calculate The Index Of Hydrogen Deficiency (IHD), Label Each Spectra As The TYPE Of Spectra It Is, Label The Significant Peaks In Each Spectra, Determine The Structure And Draw A Box […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-222309","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222309","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=222309"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222309\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=222309"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=222309"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=222309"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}