{"id":222409,"date":"2025-05-31T10:13:56","date_gmt":"2025-05-31T10:13:56","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=222409"},"modified":"2025-05-31T10:13:58","modified_gmt":"2025-05-31T10:13:58","slug":"draw-the-major-organic-product-formed-in-the-following-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/05\/31\/draw-the-major-organic-product-formed-in-the-following-reaction\/","title":{"rendered":"Draw the major organic product formed in the following reaction"},"content":{"rendered":"\n

Draw the major organic product formed in the following reaction<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Correct Answer:<\/strong><\/h3>\n\n\n\n

The major organic product of the given reaction is:<\/p>\n\n\n\n

2-methyl-2-butene<\/strong><\/p>\n\n\n\n

\"2-methyl-2-butene<\/figure>\n\n\n\n
\n\n\n\n

Explanation (Approximately 300 words):<\/strong><\/h3>\n\n\n\n

The starting compound is 2-bromo-2-methylbutane<\/strong>, and it is treated with ethoxide ion (C\u2082H\u2085O\u207b)<\/strong> in ethanol (C\u2082H\u2085OH)<\/strong>. This setup strongly suggests an E2 elimination reaction<\/strong>.<\/p>\n\n\n\n

In E2 reactions:<\/p>\n\n\n\n

    \n
  • A strong base (like ethoxide) abstracts a \u03b2-hydrogen (a hydrogen on the carbon adjacent to the one bearing the leaving group).<\/li>\n\n\n\n
  • Simultaneously, the leaving group (bromine in this case) leaves, forming a double bond.<\/li>\n<\/ul>\n\n\n\n

    Step-by-step Breakdown:<\/strong><\/h4>\n\n\n\n
      \n
    1. Structure of the substrate:<\/strong>
      The molecule is 2-bromo-2-methylbutane. The central carbon (C2) is bonded to:\n
        \n
      • A bromine atom (leaving group),<\/li>\n\n\n\n
      • A methyl group,<\/li>\n\n\n\n
      • An ethyl group,<\/li>\n\n\n\n
      • Another methyl group.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Identification of \u03b2-hydrogens:<\/strong>
        The \u03b2-hydrogens are on the adjacent carbon atoms to C2:\n
          \n
        • The carbon on the ethyl side (C3) has hydrogens available for elimination.<\/li>\n\n\n\n
        • The methyl groups do not have \u03b2-hydrogens that would lead to stable alkenes.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • Major product prediction using Zaitsev’s Rule:<\/strong>
          Zaitsev’s Rule states that in elimination reactions, the more substituted (more stable) alkene will be the major product.\n
            \n
          • Elimination of a \u03b2-hydrogen from C3 results in the formation of 2-methyl-2-butene<\/strong>, a more substituted alkene<\/strong> (disubstituted).<\/li>\n\n\n\n
          • Elimination from the other \u03b2-position would give 2-methyl-1-butene<\/strong> (less substituted), which is the minor product.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
          • Conclusion:<\/strong>
            The major organic product formed is 2-methyl-2-butene<\/strong>, resulting from the E2 elimination of H from C3 and Br from C2, forming a double bond between C2 and C3.<\/li>\n<\/ol>\n\n\n\n

            This reaction is a textbook example of a base-promoted E2 elimination leading to an alkene as the major organic product.<\/p>\n\n\n\n

            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

            Draw the major organic product formed in the following reaction The Correct Answer and Explanation is: Correct Answer: The major organic product of the given reaction is: 2-methyl-2-butene Explanation (Approximately 300 words): The starting compound is 2-bromo-2-methylbutane, and it is treated with ethoxide ion (C\u2082H\u2085O\u207b) in ethanol (C\u2082H\u2085OH). This setup strongly suggests an E2 elimination […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-222409","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222409","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=222409"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222409\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=222409"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=222409"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=222409"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}