{"id":222928,"date":"2025-06-01T05:58:07","date_gmt":"2025-06-01T05:58:07","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=222928"},"modified":"2025-06-01T05:58:11","modified_gmt":"2025-06-01T05:58:11","slug":"what-is-the-molar-mass-of-bre","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/01\/what-is-the-molar-mass-of-bre\/","title":{"rendered":"What Is the molar mass of Bre"},"content":{"rendered":"\n<p>What Is the molar mass of Bre ? The atomic mass of bromine is 79.90 g\/mol. 0 159.81 g\/mol 0 253.80 g\/mol 79.904 g\/mol 0 2.11 * 10 22 g\/mol 229.64 gmol<br>What Is the molar mass of Bre ? The atomic mass of bromine is 79.90 g\/mol. 0 159.81 g\/mol 0 253.80 g\/mol 79.904 g\/mol 0 2.11 * 10 22 g\/mol 229.64 gmol<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is: <strong>159.81 g\/mol<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the <strong>molar mass of Br\u2082 (bromine gas)<\/strong>, we must understand what the formula <strong>Br\u2082<\/strong> represents and how molar mass is calculated.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understanding Br\u2082<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The symbol <strong>Br<\/strong> stands for <strong>bromine<\/strong>, a halogen element.<\/li>\n\n\n\n<li>In nature, bromine exists as a <strong>diatomic molecule<\/strong>, which means two bromine atoms bond together to form a stable molecule: <strong>Br\u2082<\/strong>.<\/li>\n\n\n\n<li>This is similar to other diatomic elements like H\u2082, O\u2082, N\u2082, F\u2082, Cl\u2082, I\u2082.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Atomic Mass of Bromine<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>atomic mass<\/strong> of a single bromine atom is given as <strong>79.90 g\/mol<\/strong>. This is the mass of <strong>one mole of Br atoms<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculating the Molar Mass of Br\u2082<\/h3>\n\n\n\n<p>Since Br\u2082 contains <strong>two<\/strong> bromine atoms: Molar&nbsp;mass&nbsp;of&nbsp;Br2=2\u00d7atomic&nbsp;mass&nbsp;of&nbsp;Br=2\u00d779.90\u2009g\/mol=159.80\u2009g\/mol\\text{Molar mass of Br}_2 = 2 \\times \\text{atomic mass of Br} = 2 \\times 79.90 \\, \\text{g\/mol} = 159.80 \\, \\text{g\/mol}<\/p>\n\n\n\n<p>Given the closest option: <strong>159.81 g\/mol<\/strong> is the correct answer. The small rounding difference is acceptable due to rounding conventions in atomic mass tables.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Why Other Answers Are Incorrect<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>253.80 g\/mol<\/strong>: Too high; maybe confused with a heavier diatomic or triatomic molecule.<\/li>\n\n\n\n<li><strong>79.904 g\/mol<\/strong>: Close to the atomic mass of a single Br atom, not Br\u2082.<\/li>\n\n\n\n<li><strong>2.11 \u00d7 10\u00b2\u00b2 g\/mol<\/strong>: Not a reasonable molar mass. This seems like a conversion from number of atoms, not appropriate for molar mass.<\/li>\n\n\n\n<li><strong>229.64 g\/mol<\/strong>: Not a multiple of bromine\u2019s atomic mass; likely an error or miscalculation.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>Br\u2082 is a diatomic molecule of bromine, and since each Br atom has a mass of ~79.90 g\/mol, the molar mass of Br\u2082 is <strong>159.81 g\/mol<\/strong>. This value is important in stoichiometric calculations involving bromine gas.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-13.jpeg\" alt=\"\" class=\"wp-image-222929\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What Is the molar mass of Bre ? The atomic mass of bromine is 79.90 g\/mol. 0 159.81 g\/mol 0 253.80 g\/mol 79.904 g\/mol 0 2.11 * 10 22 g\/mol 229.64 gmolWhat Is the molar mass of Bre ? The atomic mass of bromine is 79.90 g\/mol. 0 159.81 g\/mol 0 253.80 g\/mol 79.904 g\/mol [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-222928","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222928","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=222928"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/222928\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=222928"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=222928"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=222928"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}