{"id":223305,"date":"2025-06-01T12:42:51","date_gmt":"2025-06-01T12:42:51","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=223305"},"modified":"2025-06-01T12:42:53","modified_gmt":"2025-06-01T12:42:53","slug":"acetophenone-p-methoxy-infrared-spectrum-0-8-0-6-l04-d2-3000","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/01\/acetophenone-p-methoxy-infrared-spectrum-0-8-0-6-l04-d2-3000\/","title":{"rendered":"Acetophenone, p-methoxy INFRARED SPECTRUM 0.8 0.6 L04 D2 3000"},"content":{"rendered":"\n<p>Acetophenone, p-methoxy INFRARED SPECTRUM 0.8 0.6 L04 D2 3000<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answer:<\/strong><\/h3>\n\n\n\n<p><strong>The key peaks to identify in the IR spectrum of <em>p<\/em>-methoxyacetophenone are:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Aromatic C\u2013H stretches<\/strong>: Around <strong>3000\u20133100 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>Alkyl C\u2013H stretches<\/strong> (from CH\u2083 and CH\u2082): Around <strong>2850\u20132960 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>C=O stretch (ketone)<\/strong>: <strong>~1680\u20131725 cm\u207b\u00b9<\/strong> (strong, sharp peak)<\/li>\n\n\n\n<li><strong>Aromatic ring stretches (C=C)<\/strong>: <strong>~1450\u20131600 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>C\u2013O stretch (ether, from the methoxy group)<\/strong>: <strong>~1240\u20131275 cm\u207b\u00b9<\/strong><\/li>\n\n\n\n<li><strong>Aromatic out-of-plane C\u2013H bending<\/strong>: <strong>~700\u2013900 cm\u207b\u00b9<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p><strong><em>p<\/em>-Methoxyacetophenone<\/strong> is a substituted aromatic ketone. The molecule has three significant functional groups: an aromatic ring, a methoxy (-OCH\u2083) group para to the ketone, and an acetyl group (-COCH\u2083) attached to the ring. Its IR spectrum provides insight into the presence and environment of these functional groups.<\/p>\n\n\n\n<p>The <strong>carbonyl (C=O) stretch<\/strong>, typically strong and sharp, appears in the range of <strong>1680\u20131725 cm\u207b\u00b9<\/strong>. In <em>p<\/em>-methoxyacetophenone, this appears around <strong>1690\u20131705 cm\u207b\u00b9<\/strong>, slightly lower due to resonance from the aromatic ring and the electron-donating methoxy group.<\/p>\n\n\n\n<p>The <strong>aromatic C=C stretching vibrations<\/strong> appear as medium intensity bands in the <strong>1450\u20131600 cm\u207b\u00b9<\/strong> region. These peaks indicate the presence of an aromatic ring.<\/p>\n\n\n\n<p>The <strong>C\u2013H stretches<\/strong> in the <strong>3000\u20133100 cm\u207b\u00b9<\/strong> region correspond to the aromatic hydrogen atoms. Additionally, the <strong>alkyl C\u2013H stretches<\/strong> from the methyl and methylene groups show up around <strong>2850\u20132960 cm\u207b\u00b9<\/strong>.<\/p>\n\n\n\n<p>A distinguishing feature of <em>p<\/em>-methoxyacetophenone is the <strong>C\u2013O stretch<\/strong> from the <strong>methoxy (-OCH\u2083)<\/strong> group, which appears around <strong>1240\u20131275 cm\u207b\u00b9<\/strong>. This region helps confirm the presence of the ether linkage.<\/p>\n\n\n\n<p>Finally, the <strong>out-of-plane C\u2013H bending<\/strong> in the <strong>700\u2013900 cm\u207b\u00b9<\/strong> region provides information on the substitution pattern on the aromatic ring. For <em>para<\/em>-substitution, you typically observe a strong single band near <strong>825\u2013860 cm\u207b\u00b9<\/strong>.<\/p>\n\n\n\n<p>By analyzing these characteristic peaks, one can confidently identify the presence and structure of <em>p<\/em>-methoxyacetophenone using its IR spectrum.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-38.jpeg\" alt=\"\" class=\"wp-image-223306\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Acetophenone, p-methoxy INFRARED SPECTRUM 0.8 0.6 L04 D2 3000 The Correct Answer and Explanation is: Correct Answer: The key peaks to identify in the IR spectrum of p-methoxyacetophenone are: Explanation p-Methoxyacetophenone is a substituted aromatic ketone. The molecule has three significant functional groups: an aromatic ring, a methoxy (-OCH\u2083) group para to the ketone, and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-223305","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223305","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=223305"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223305\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=223305"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=223305"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=223305"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}