{"id":223312,"date":"2025-06-01T12:51:34","date_gmt":"2025-06-01T12:51:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=223312"},"modified":"2025-06-01T12:51:36","modified_gmt":"2025-06-01T12:51:36","slug":"which-two-molecules-are-compounds","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/01\/which-two-molecules-are-compounds\/","title":{"rendered":"Which two molecules are compounds"},"content":{"rendered":"\n<p>Which two molecules are compounds? NaHCO3 O3 Cl2 C8H18<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The two molecules that are compounds are <strong>NaHCO\u2083 (sodium bicarbonate)<\/strong> and <strong>C\u2088H\u2081\u2088 (octane)<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine which of these molecules are <strong>compounds<\/strong>, we need to understand the difference between <strong>elements<\/strong> and <strong>compounds<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Element<\/strong>: A substance made of only one type of atom. It cannot be broken down into simpler substances by chemical means. Examples: O\u2083 (ozone) and Cl\u2082 (chlorine gas), both made of only oxygen and chlorine atoms respectively.<\/li>\n\n\n\n<li><strong>Compound<\/strong>: A substance formed when two or more <strong>different<\/strong> elements are chemically bonded together in fixed proportions. Examples: NaHCO\u2083 and C\u2088H\u2081\u2088.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Analysis of Each Substance:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>NaHCO\u2083 (Sodium bicarbonate)<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Composed of four <strong>different<\/strong> elements: sodium (Na), hydrogen (H), carbon (C), and oxygen (O).<\/li>\n\n\n\n<li>These atoms are chemically combined in a fixed ratio.<\/li>\n\n\n\n<li>Therefore, <strong>NaHCO\u2083 is a compound<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>O\u2083 (Ozone)<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Made entirely of <strong>oxygen<\/strong> atoms.<\/li>\n\n\n\n<li>Though it has three atoms, all are the <strong>same element<\/strong>, so it is <strong>not a compound<\/strong>; it&#8217;s an <strong>elemental molecule<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Cl\u2082 (Chlorine gas)<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Composed of two chlorine atoms.<\/li>\n\n\n\n<li>Since both atoms are the <strong>same element<\/strong>, Cl\u2082 is <strong>not a compound<\/strong>, but a <strong>diatomic element<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>C\u2088H\u2081\u2088 (Octane)<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Made up of two different elements: carbon (C) and hydrogen (H).<\/li>\n\n\n\n<li>Chemically bonded in a fixed ratio (8 carbon atoms to 18 hydrogen atoms).<\/li>\n\n\n\n<li>Therefore, <strong>C\u2088H\u2081\u2088 is a compound<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The two compounds are:<\/p>\n\n\n\n<p>\u2705 <strong>NaHCO\u2083 (sodium bicarbonate)<\/strong><br>\u2705 <strong>C\u2088H\u2081\u2088 (octane)<\/strong><\/p>\n\n\n\n<p>O\u2083 and Cl\u2082 are <strong>not compounds<\/strong>; they are <strong>elemental molecules<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-62.jpeg\" alt=\"\" class=\"wp-image-223313\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which two molecules are compounds? NaHCO3 O3 Cl2 C8H18 The Correct Answer and Explanation is: The two molecules that are compounds are NaHCO\u2083 (sodium bicarbonate) and C\u2088H\u2081\u2088 (octane). Explanation: To determine which of these molecules are compounds, we need to understand the difference between elements and compounds: Analysis of Each Substance: Conclusion: The two compounds [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-223312","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223312","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=223312"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223312\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=223312"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=223312"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=223312"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}