{"id":223374,"date":"2025-06-01T13:49:50","date_gmt":"2025-06-01T13:49:50","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=223374"},"modified":"2025-06-01T13:49:52","modified_gmt":"2025-06-01T13:49:52","slug":"the-most-prominent-line-in-the-spectrum-of-mercury-is-at-253-652-nm","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/01\/the-most-prominent-line-in-the-spectrum-of-mercury-is-at-253-652-nm\/","title":{"rendered":"The most prominent line in the spectrum of mercury is at 253.652 nm"},"content":{"rendered":"\n<p>The most prominent line in the spectrum of mercury is at 253.652 nm. Other lines are located at 365.01 nm, 404.65 nm, 435.83 nm, and 1013.97 nm. (4 points) (a) Which of these lines are located within the visible spectrum? What color are they? Which of these lines represents the most energetic light? What is the frequency of the most prominent line? Use the equation \u00e2\u201a\u00ac = Av (c &#8211; speed of light; V = frequency, A &#8211; wavelength). Check the units before plugging in the numbers to the equation. Spectral Distribution of a Low-Pressure Mercury Lamp used wavelength calibration 10&#8242; 0 10 ? L 10 &#8221; 200 300 400 Wavelength (nm) 500 600<br>The most prominent line in the spectrum of mercury is at 253.652 nm. Other lines are located at 365.01 nm, 404.65 nm, 435.83 nm, and 1013.97 nm. (4 points) (a) Which of these lines are located within the visible spectrum? What color are they? Which of these lines represents the most energetic light? What is the frequency of the most prominent line? Use the equation \u00e2\u201a\u00ac = Av (c &#8211; speed of light; V = frequency, A &#8211; wavelength). Check the units before plugging in the numbers to the equation. Spectral Distribution of a Low-Pressure Mercury Lamp used wavelength calibration 10&#8242; 0 10 ? L 10 &#8221; 200 300 400 Wavelength (nm) 500 6<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To answer the question thoroughly, let\u2019s break it down into four parts:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Given Wavelengths:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>253.652 nm (most prominent line)<\/li>\n\n\n\n<li>365.01 nm<\/li>\n\n\n\n<li>404.65 nm<\/li>\n\n\n\n<li>435.83 nm<\/li>\n\n\n\n<li>1013.97 nm<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(a) Which lines are in the visible spectrum? What color are they?<\/strong><\/h3>\n\n\n\n<p>The <strong>visible spectrum<\/strong> ranges approximately from <strong>380 nm to 750 nm<\/strong>.<\/p>\n\n\n\n<p><strong>Within the visible range:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>365.01 nm<\/strong>: <em>Just outside<\/em> visible range (near UV)<\/li>\n\n\n\n<li><strong>404.65 nm<\/strong>: <em>Visible<\/em>, <strong>violet<\/strong><\/li>\n\n\n\n<li><strong>435.83 nm<\/strong>: <em>Visible<\/em>, <strong>blue<\/strong><\/li>\n\n\n\n<li><strong>1013.97 nm<\/strong>: <em>Infrared<\/em>, <strong>not visible<\/strong><\/li>\n\n\n\n<li><strong>253.652 nm<\/strong>: <em>Ultraviolet<\/em>, <strong>not visible<\/strong><\/li>\n<\/ul>\n\n\n\n<p>\u2705 <strong>Visible lines and colors:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>404.65 nm<\/strong> \u2192 Violet<\/li>\n\n\n\n<li><strong>435.83 nm<\/strong> \u2192 Blue<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(b) Which line represents the most energetic light?<\/strong><\/h3>\n\n\n\n<p>The energy of a photon is inversely proportional to its wavelength: E=h\u22c5\u03bd=h\u22c5c\u03bbE = h \\cdot \\nu = \\frac{h \\cdot c}{\\lambda}<\/p>\n\n\n\n<p>So, <strong>shorter wavelength = higher energy<\/strong>.<\/p>\n\n\n\n<p>Among the given wavelengths, the <strong>shortest<\/strong> is <strong>253.652 nm<\/strong>, meaning it is the <strong>most energetic light<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>(c) What is the frequency of the most prominent line (253.652 nm)?<\/strong><\/h3>\n\n\n\n<p>Use the equation: c=\u03bb\u22c5\u03bd\u21d2\u03bd=c\u03bbc = \\lambda \\cdot \\nu \\Rightarrow \\nu = \\frac{c}{\\lambda}<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>c=3.00\u00d7108\u2009m\/sc = 3.00 \\times 10^8 \\, \\text{m\/s}<\/li>\n\n\n\n<li>\u03bb=253.652\u2009nm=253.652\u00d710\u22129\u2009m\\lambda = 253.652 \\, \\text{nm} = 253.652 \\times 10^{-9} \\, \\text{m}<\/li>\n<\/ul>\n\n\n\n<p>\u03bd=3.00\u00d7108253.652\u00d710\u22129\u22481.182\u00d71015\u2009Hz\\nu = \\frac{3.00 \\times 10^8}{253.652 \\times 10^{-9}} \\approx 1.182 \\times 10^{15} \\, \\text{Hz}<\/p>\n\n\n\n<p>\u2705 <strong>Frequency of 253.652 nm line:<\/strong> 1.182\u00d71015\u2009Hz\\boxed{1.182 \\times 10^{15} \\, \\text{Hz}}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong> Explanation:<\/strong><\/h3>\n\n\n\n<p>Mercury emits light at specific wavelengths due to electronic transitions between energy levels. These discrete spectral lines include ultraviolet (UV), visible, and infrared (IR) radiation. Among the provided wavelengths\u2014253.652 nm, 365.01 nm, 404.65 nm, 435.83 nm, and 1013.97 nm\u2014only 404.65 nm and 435.83 nm fall within the <strong>visible spectrum<\/strong>, which ranges from approximately <strong>380 to 750 nm<\/strong>. The 404.65 nm line corresponds to <strong>violet<\/strong>, while the 435.83 nm line corresponds to <strong>blue<\/strong>. The 365.01 nm line lies just outside the visible range in the <strong>near-UV<\/strong> region. The 253.652 nm line, though the most prominent and intense emission of mercury, lies in the <strong>ultraviolet region<\/strong>, invisible to the human eye. The 1013.97 nm line lies in the <strong>infrared region<\/strong>.<\/p>\n\n\n\n<p>The <strong>most energetic light<\/strong> corresponds to the <strong>shortest wavelength<\/strong>. According to the equation E=h\u22c5\u03bd=h\u22c5c\u03bbE = h \\cdot \\nu = \\frac{h \\cdot c}{\\lambda}, energy is inversely proportional to wavelength. Thus, the 253.652 nm line has the <strong>highest energy<\/strong> among those listed. To determine its frequency, we use \u03bd=c\u03bb\\nu = \\frac{c}{\\lambda}, where cc is the speed of light (3.00 \u00d7 10\u2078 m\/s) and \u03bb\\lambda is converted to meters. Substituting, we find the frequency of the 253.652 nm line to be approximately <strong>1.182 \u00d7 10\u00b9\u2075 Hz<\/strong>. This high frequency and energy make it ideal for applications like <strong>germicidal lamps<\/strong> and <strong>UV spectroscopy<\/strong>, despite being invisible to the naked eye.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-14.jpeg\" alt=\"\" class=\"wp-image-223375\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The most prominent line in the spectrum of mercury is at 253.652 nm. Other lines are located at 365.01 nm, 404.65 nm, 435.83 nm, and 1013.97 nm. (4 points) (a) Which of these lines are located within the visible spectrum? What color are they? Which of these lines represents the most energetic light? What is [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-223374","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223374","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=223374"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223374\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=223374"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=223374"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=223374"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}