{"id":223547,"date":"2025-06-02T03:55:19","date_gmt":"2025-06-02T03:55:19","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=223547"},"modified":"2025-06-02T03:55:21","modified_gmt":"2025-06-02T03:55:21","slug":"draw-the-lewis-structure-for-acetamide-ch3conh2-an-organic-compound-and-determine-the-geometry-about-each-interior-atom","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/02\/draw-the-lewis-structure-for-acetamide-ch3conh2-an-organic-compound-and-determine-the-geometry-about-each-interior-atom\/","title":{"rendered":"Draw the Lewis structure for acetamide (CH3CONH2), an organic compound, and determine the geometry about each interior atom"},"content":{"rendered":"\n<p>Draw the Lewis structure for acetamide (CH3CONH2), an organic compound, and determine the geometry about each interior atom. Experiments show that the geometry about the nitrogen atom in acetamide is nearly planar. Which resonance structure can account for the planar geometry about the nitrogen atom?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Answer:<\/strong><\/p>\n\n\n\n<p>The Lewis structure for <strong>acetamide (CH\u2083CONH\u2082)<\/strong> is as follows:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>       H\n       |\nH\u2083C\u2014C\u2014N\n     || \\\n     O   H\n<\/code><\/pre>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Structure Breakdown:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>methyl group (CH\u2083)<\/strong> is bonded to the carbonyl carbon.<\/li>\n\n\n\n<li>The <strong>carbonyl group (C=O)<\/strong> involves a double bond between carbon and oxygen.<\/li>\n\n\n\n<li>The <strong>amide group (NH\u2082)<\/strong> is bonded to the carbonyl carbon and has two hydrogen atoms attached to nitrogen.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Geometry:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Carbonyl carbon (C=O)<\/strong>: This carbon is <strong>sp\u00b2 hybridized<\/strong>, resulting in a <strong>trigonal planar geometry<\/strong> (~120\u00b0 bond angles).<\/li>\n\n\n\n<li><strong>Nitrogen (NH\u2082)<\/strong>: Despite typically forming a pyramidal geometry (sp\u00b3 hybridization), in acetamide, nitrogen is also <strong>nearly planar<\/strong>, suggesting <strong>sp\u00b2 hybridization<\/strong>.<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong>: Double bonded to carbon with two lone pairs, it also adopts a <strong>trigonal planar<\/strong> arrangement (sp\u00b2 hybridized).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation of Planar Geometry Around Nitrogen:<\/h3>\n\n\n\n<p>Experimental evidence indicates the nitrogen atom in acetamide is nearly planar, which is not typical for nitrogen with three sigma bonds and one lone pair (normally tetrahedral). This deviation can be explained by <strong>resonance<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Key Resonance Structure:<\/h4>\n\n\n\n<p>A significant resonance form of acetamide shows <strong>delocalization of the nitrogen lone pair<\/strong> into the carbonyl \u03c0-system, creating a <strong>partial double bond<\/strong> between nitrogen and carbon:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>       H\n       |\nH\u2083C\u2014C=N\u207a\u2014H\n     |   |\n     O\u207b  H\n<\/code><\/pre>\n\n\n\n<p>This resonance form contributes to:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Planar Geometry<\/strong>: Delocalization of the lone pair requires the nitrogen to use an <strong>unhybridized p-orbital<\/strong>, aligning with the p-orbitals of the C=O group, leading to a <strong>planar sp\u00b2 hybridized nitrogen<\/strong>.<\/li>\n\n\n\n<li><strong>Bond Lengths<\/strong>: The C\u2013N bond is shorter than a typical C\u2013N single bond, reflecting <strong>partial double-bond character<\/strong>.<\/li>\n\n\n\n<li><strong>Stabilization<\/strong>: Resonance delocalization increases stability and explains the amide&#8217;s rigidity and reduced basicity.<\/li>\n<\/ol>\n\n\n\n<p>In conclusion, the <strong>resonance structure with delocalized nitrogen lone pair and partial C=N and C\u2013O\u207b character<\/strong> accounts for the planar geometry around nitrogen in acetamide.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-94.jpeg\" alt=\"\" class=\"wp-image-223548\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Lewis structure for acetamide (CH3CONH2), an organic compound, and determine the geometry about each interior atom. Experiments show that the geometry about the nitrogen atom in acetamide is nearly planar. Which resonance structure can account for the planar geometry about the nitrogen atom? The Correct Answer and Explanation is: Answer: The Lewis structure [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-223547","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223547","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=223547"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223547\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=223547"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=223547"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=223547"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}