{"id":223762,"date":"2025-06-02T10:22:20","date_gmt":"2025-06-02T10:22:20","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=223762"},"modified":"2025-06-02T10:22:23","modified_gmt":"2025-06-02T10:22:23","slug":"what-is-the-khp-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/02\/what-is-the-khp-2\/","title":{"rendered":"What is the KHP"},"content":{"rendered":"\n<p>Question 3 0.4 pts What is the KHP: NaOH mole ratio for the reaction between sodium hydroxide and potassium hydrogen phthalate, according to the balanced chemical equation? (fill in each blank with the appropriate integer value) Question 4 mol KHP : mol NaOH 1 pts A student removes 10.00 mL of 0.558M KHP solution and titrates it with a sodium hydroxide solution of unknown concentration. If 13.46mL of NaOH was used to reach the endpoint, what is the concentration of the NaOH solution in units of Molarity? (Be prepared to submit your complete set of calculations.) Type only the numerical portion of your answer in the box below. Your answer will be in units of Molarity (M). Report your answer to 3 significant figures.<br>Question 3 0.4 pts What is the KHP: NaOH mole ratio for the reaction between sodium hydroxide and potassium hydrogen phthalate, according to the balanced chemical equation? (fill in each blank with the appropriate integer value) Question 4 mol KHP : mol NaOH 1 pts A student removes 10.00 mL of 0.558M KHP solution and titrates it with a sodium hydroxide solution of unknown concentration. If 13.46mL of NaOH was used to reach the endpoint, what is the concentration of the NaOH solution in units of Molarity? (Be prepared to submit your complete set of calculations.) Type only the numerical portion of your answer in the box below. Your answer will be in units of Molarity (M). Report your answer to 3 significant figures.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct answers<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>KHP : NaOH mole ratio \u2014 1 : 1<\/strong><\/li>\n\n\n\n<li><strong>[NaOH] \u2014 0.415 M<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Why the ratio is 1 : 1<\/h3>\n\n\n\n<p>Potassium hydrogen phthalate (usually abbreviated KHP) has the formula <strong>KHC\u2088H\u2084O\u2084<\/strong>. It is a monoprotic acid; the single acidic hydrogen (the \u201cH\u201d in KHP) can donate one proton. When titrated with sodium hydroxide, that proton is neutralised: KHC8H4O4\u2005\u200a(aq)+NaOH\u2005\u200a(aq)\u2005\u200a\u27f6\u2005\u200aKNaC8H4O4\u2005\u200a(aq)+H2O\u2005\u200a(l)\\text{KHC}_8\\text{H}_4\\text{O}_4\\;(aq) + \\text{NaOH}\\;(aq) \\;\\longrightarrow\\; \\text{KNaC}_8\\text{H}_4\\text{O}_4\\;(aq) + \\text{H}_2\\text{O}\\;(l)<\/p>\n\n\n\n<p>Because only <strong>one<\/strong> OH\u207b ion is required per KHP molecule, the balanced chemical equation shows a <strong>1-to-1 stoichiometric relationship<\/strong> between moles of KHP and moles of NaOH. This is why the mole ratio is <strong>1 mol KHP : 1 mol NaOH<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Determining the NaOH concentration<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Moles of KHP used<\/strong><\/li>\n<\/ol>\n\n\n\n<p>nKHP=M\u00d7V=0.558\u2005\u200amol&nbsp;L\u22121\u00d70.01000\u2005\u200aL=5.58\u00d710\u22123\u2005\u200amoln_{\\text{KHP}} = M \\times V = 0.558\\;\\text{mol L}^{-1} \\times 0.01000\\;\\text{L} = 5.58 \\times 10^{-3}\\;\\text{mol}<\/p>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Moles of NaOH required<\/strong><br>With the 1 : 1 ratio, the same number of moles of NaOH react:<\/li>\n<\/ol>\n\n\n\n<p>nNaOH=nKHP=5.58\u00d710\u22123\u2005\u200amoln_{\\text{NaOH}} = n_{\\text{KHP}} = 5.58 \\times 10^{-3}\\;\\text{mol}<\/p>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong>Volume of NaOH delivered<\/strong><\/li>\n<\/ol>\n\n\n\n<p>VNaOH=13.46\u2005\u200amL=0.01346\u2005\u200aLV_{\\text{NaOH}} = 13.46\\;\\text{mL} = 0.01346\\;\\text{L}<\/p>\n\n\n\n<ol start=\"4\" class=\"wp-block-list\">\n<li><strong>Concentration of NaOH<\/strong><\/li>\n<\/ol>\n\n\n\n<p>[NaOH]=nNaOHVNaOH=5.58\u00d710\u22123\u2005\u200amol0.01346\u2005\u200aL=0.41456\u2005\u200amol&nbsp;L\u22121[\\text{NaOH}] = \\frac{n_{\\text{NaOH}}}{V_{\\text{NaOH}}} = \\frac{5.58 \\times 10^{-3}\\;\\text{mol}}{0.01346\\;\\text{L}} = 0.41456\\;\\text{mol L}^{-1}<\/p>\n\n\n\n<p>Rounded to three significant figures, the molarity is <strong>0.415 M<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Key points to remember<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>KHP is monoprotic<\/strong>, so its titration with any strong base is always 1 : 1.<\/li>\n\n\n\n<li>Convert all volumes to <strong>litres<\/strong> before multiplying or dividing by molarity.\n<ul class=\"wp-block-list\">\n<li>Keep an extra digit during intermediate calculations; round only at the final step to maintain accuracy. This practice ensured the reported 0.415 M value is reliable to three significant figures.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-9.jpeg\" alt=\"\" class=\"wp-image-223764\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Question 3 0.4 pts What is the KHP: NaOH mole ratio for the reaction between sodium hydroxide and potassium hydrogen phthalate, according to the balanced chemical equation? (fill in each blank with the appropriate integer value) Question 4 mol KHP : mol NaOH 1 pts A student removes 10.00 mL of 0.558M KHP solution and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-223762","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223762","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=223762"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223762\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=223762"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=223762"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=223762"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}