{"id":223774,"date":"2025-06-02T10:36:32","date_gmt":"2025-06-02T10:36:32","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=223774"},"modified":"2025-06-02T10:36:34","modified_gmt":"2025-06-02T10:36:34","slug":"vsepr-theory","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/02\/vsepr-theory\/","title":{"rendered":"VSEPR theory"},"content":{"rendered":"\n<p>VSEPR theory? Seesaw B. T-shaped Bent or V-shaped D, Trigonal planar Tetrahedral<br>Question 2 What is the molecular geometry of IBr3 according to the VSEPR theory? Seesaw B. T-shaped Bent or V-shaped D, Trigonal planar Tetrahedra<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-18.png\" alt=\"\" class=\"wp-image-223775\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is: <strong>B. T-shaped<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the molecular geometry of <strong>IBr\u2083<\/strong> using <strong>VSEPR (Valence Shell Electron Pair Repulsion) theory<\/strong>, follow these steps:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Determine the number of valence electrons<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Iodine (I)<\/strong> is in group 17, so it has <strong>7 valence electrons<\/strong>.<\/li>\n\n\n\n<li>Each <strong>bromine (Br)<\/strong> also has <strong>7 valence electrons<\/strong>, and there are <strong>3 Br atoms<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>However, for geometry, we focus on the central atom\u2014Iodine.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Bonding and lone pairs on iodine<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Iodine forms <strong>three single bonds<\/strong> with each Br atom, using 3 of its 7 valence electrons.<\/li>\n\n\n\n<li>This leaves <strong>4 electrons<\/strong>, or <strong>2 lone pairs<\/strong> (since each lone pair consists of 2 electrons).<\/li>\n<\/ul>\n\n\n\n<p>So iodine in IBr\u2083 has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>3 bonding pairs<\/strong> (Br atoms),<\/li>\n\n\n\n<li><strong>2 lone pairs<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>This results in a total of <strong>5 regions of electron density<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 3: Use VSEPR to predict shape<\/h4>\n\n\n\n<p>With <strong>5 electron regions<\/strong>, the <strong>electron geometry<\/strong> is <strong>trigonal bipyramidal<\/strong>. However, lone pairs occupy equatorial positions to minimize repulsion.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The 3 Br atoms occupy two axial and one equatorial position.<\/li>\n\n\n\n<li>The 2 lone pairs occupy the remaining equatorial positions.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Step 4: Determine the molecular geometry<\/h4>\n\n\n\n<p>When a molecule has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>3 bonding pairs,<\/li>\n\n\n\n<li>2 lone pairs,<\/li>\n\n\n\n<li>in a trigonal bipyramidal electron geometry,<\/li>\n<\/ul>\n\n\n\n<p>The <strong>molecular geometry<\/strong> is <strong>T-shaped<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Conclusion:<\/h4>\n\n\n\n<p>The lone pairs distort the ideal shape, and the three bonded atoms form a T-shaped structure. Hence, according to VSEPR theory, the molecular geometry of <strong>IBr\u2083<\/strong> is <strong>T-shaped<\/strong>.<\/p>\n\n\n\n<p>\u2705 <strong>Correct answer: B. T-shaped<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-21.jpeg\" alt=\"\" class=\"wp-image-223776\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>VSEPR theory? Seesaw B. T-shaped Bent or V-shaped D, Trigonal planar TetrahedralQuestion 2 What is the molecular geometry of IBr3 according to the VSEPR theory? Seesaw B. T-shaped Bent or V-shaped D, Trigonal planar Tetrahedra The Correct Answer and Explanation is: The correct answer is: B. T-shaped Explanation: To determine the molecular geometry of IBr\u2083 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-223774","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223774","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=223774"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/223774\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=223774"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=223774"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=223774"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}