{"id":224051,"date":"2025-06-02T16:33:49","date_gmt":"2025-06-02T16:33:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=224051"},"modified":"2025-06-02T16:33:51","modified_gmt":"2025-06-02T16:33:51","slug":"the-molecular-geometry-of-the-chbr3-molecule-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/02\/the-molecular-geometry-of-the-chbr3-molecule-is\/","title":{"rendered":"The molecular geometry of the CHBr3 molecule is"},"content":{"rendered":"\n<p>The molecular geometry of the CHBr3 molecule is Explain and the molecule is A trigonal pyramidal, polar B) tetrahedral, nonpolar seesaw nonpolar D) tetrahedral, polar E) seesaw polar<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct choice: D) tetrahedral, polar<\/strong><\/p>\n\n\n\n<p><strong>Explanation<\/strong><br>Bromoform, CHBr\u2083, contains a central carbon atom that forms four \u03c3-bonds: one to hydrogen and one to each of three bromine atoms. Carbon supplies four valence electrons, and each X\u2013C bond uses one electron pair, leaving <strong>no lone pairs on the central atom<\/strong>. Under Valence-Shell Electron-Pair Repulsion (VSEPR) theory, four regions of electron density arrange themselves as far apart as possible, giving an <strong>electron-pair geometry that is tetrahedral with ideal 109.5 \u00b0 angles<\/strong>. Because there are no lone pairs to distort the shape, the <strong>molecular geometry is also tetrahedral<\/strong>.<\/p>\n\n\n\n<p>Whether a tetrahedral molecule is polar hinges on how its individual bond dipoles combine. Each <strong>C\u2013Br bond is polar<\/strong> (bromine electronegativity \u03c7 \u2248 2.96 &gt; carbon \u03c7 \u2248 2.55), with its dipole pointing from carbon toward bromine. By contrast, the <strong>C\u2013H bond is weakly polar in the opposite direction<\/strong> (carbon \u03c7 &gt; hydrogen \u03c7 \u2248 2.20), so its dipole points from hydrogen toward carbon.<\/p>\n\n\n\n<p>If all four substituents were identical, the tetrahedron\u2019s dipoles would cancel perfectly and the molecule would be non-polar, as in CCl\u2084. In CHBr\u2083, however, <strong>three identical C\u2013Br vectors lie at the corners of a trigonal pyramid, while the single C\u2013H vector occupies the fourth vertex<\/strong>. Adding the three equal C\u2013Br dipoles yields a resultant vector pointing roughly opposite the C\u2013H dipole, but the magnitude of each C\u2013Br dipole is larger than that of C\u2013H. Consequently, the vectors <strong>do not cancel completely<\/strong>, leaving a measurable molecular dipole (experimentally \u2248 1.25 D).<\/p>\n\n\n\n<p>This residual charge separation classifies CHBr\u2083 as a <strong>polar molecule<\/strong>. Its polarity helps explain several physical properties: a higher boiling point (150 \u00b0C) than non-polar hydrocarbons of similar molar mass, appreciable solubility in moderately polar organic solvents, and immiscibility with water. All observations are fully consistent with option <strong>D) tetrahedral, polar<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-151.jpeg\" alt=\"\" class=\"wp-image-224052\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The molecular geometry of the CHBr3 molecule is Explain and the molecule is A trigonal pyramidal, polar B) tetrahedral, nonpolar seesaw nonpolar D) tetrahedral, polar E) seesaw polar The Correct Answer and Explanation is: Correct choice: D) tetrahedral, polar ExplanationBromoform, CHBr\u2083, contains a central carbon atom that forms four \u03c3-bonds: one to hydrogen and one [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-224051","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224051","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=224051"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224051\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=224051"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=224051"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=224051"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}