{"id":224055,"date":"2025-06-02T16:39:53","date_gmt":"2025-06-02T16:39:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=224055"},"modified":"2025-06-02T16:39:55","modified_gmt":"2025-06-02T16:39:55","slug":"predict-the-organic-products-in-any-order","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/02\/predict-the-organic-products-in-any-order\/","title":{"rendered":"Predict the organic products, in any order"},"content":{"rendered":"\n<p>Predict the organic products, in any order, when the alkene shown is subjected to ozonolysis with reductive work-up. Draw product 1. Draw product 2.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The alkene shown in the image is <strong>1-pentene<\/strong>, with the structure:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>CH3-CH2-CH2-CH=CH2\n<\/code><\/pre>\n\n\n\n<p>When this alkene undergoes <strong>ozonolysis with reductive work-up<\/strong> (typically using reagents like O\u2083 followed by Zn\/H\u2082O or dimethyl sulfide (DMS)), the double bond is cleaved and each carbon of the former double bond becomes the carbon of a carbonyl compound\u2014specifically, an aldehyde if no further oxidation occurs.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Predicted Products:<\/strong><\/h3>\n\n\n\n<p>The double bond in 1-pentene is between <strong>C-4 and C-5<\/strong> in the chain. Breaking this double bond yields two fragments:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Butanal<\/strong> (CH\u2083CH\u2082CH\u2082CHO)<\/li>\n\n\n\n<li><strong>Formaldehyde<\/strong> (HCHO)<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Structures:<\/strong><\/h3>\n\n\n\n<p><strong>Product 1: Butanal<\/strong><br>A four-carbon aldehyde with the formula <strong>CH\u2083CH\u2082CH\u2082CHO<\/strong><\/p>\n\n\n\n<p><strong>Product 2: Formaldehyde<\/strong><br>A one-carbon aldehyde with the formula <strong>HCHO<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p><strong>Ozonolysis<\/strong> is an oxidative cleavage reaction in which the carbon-carbon double bond of an alkene is broken and replaced with two carbonyl-containing fragments. In the presence of <strong>reductive work-up<\/strong> (such as zinc with water or dimethyl sulfide), the reaction yields <strong>aldehydes and\/or ketones<\/strong> instead of carboxylic acids.<\/p>\n\n\n\n<p>The compound shown is <strong>1-pentene<\/strong>, an unbranched five-carbon alkene with a terminal double bond. Its structure is:<\/p>\n\n\n\n<p><strong>CH\u2083\u2013CH\u2082\u2013CH\u2082\u2013CH=CH\u2082<\/strong><\/p>\n\n\n\n<p>During ozonolysis, ozone (O\u2083) adds to the double bond forming a molozonide intermediate, which rearranges to a more stable ozonide. The ozonide is then cleaved during the reductive work-up, resulting in two carbonyl products. Each carbon of the original double bond becomes the carbon of a carbonyl group.<\/p>\n\n\n\n<p>For 1-pentene, the double bond lies between the fourth and fifth carbons. Cleavage of this double bond splits the molecule into:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A four-carbon fragment (CH\u2083\u2013CH\u2082\u2013CH\u2082\u2013) attached to the double-bonded carbon, which becomes <strong>butanal (CH\u2083CH\u2082CH\u2082CHO)<\/strong>.<\/li>\n\n\n\n<li>A one-carbon fragment from the terminal carbon of the double bond, which becomes <strong>formaldehyde (HCHO)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>These are the two organic products. Under <strong>oxidative work-up<\/strong> (e.g., H\u2082O\u2082), the aldehydes could further oxidize to carboxylic acids, but that is not the case here because the question specifies <strong>reductive work-up<\/strong>.<\/p>\n\n\n\n<p>Thus, the final products are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Butanal<\/strong><\/li>\n\n\n\n<li><strong>Formaldehyde<\/strong><\/li>\n<\/ul>\n\n\n\n<p>These are the organic products formed from the ozonolysis of 1-pentene under reductive conditions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-19.jpeg\" alt=\"\" class=\"wp-image-224056\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Predict the organic products, in any order, when the alkene shown is subjected to ozonolysis with reductive work-up. Draw product 1. Draw product 2. The Correct Answer and Explanation is: The alkene shown in the image is 1-pentene, with the structure: When this alkene undergoes ozonolysis with reductive work-up (typically using reagents like O\u2083 followed [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-224055","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224055","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=224055"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224055\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=224055"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=224055"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=224055"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}