{"id":224297,"date":"2025-06-02T20:33:46","date_gmt":"2025-06-02T20:33:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=224297"},"modified":"2025-06-02T20:33:48","modified_gmt":"2025-06-02T20:33:48","slug":"deducing-the-ions-in-a-binary-ionic-compound-complete-the-table-below-by-writing-the-symbols-for-the-ionic-cation-and-anion-compound","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/02\/deducing-the-ions-in-a-binary-ionic-compound-complete-the-table-below-by-writing-the-symbols-for-the-ionic-cation-and-anion-compound\/","title":{"rendered":"Deducing the ions in a binary ionic compound Complete the table below by writing the symbols for the ionic cation and anion compound"},"content":{"rendered":"\n<p>Deducing the ions in a binary ionic compound Complete the table below by writing the symbols for the ionic cation and anion compound. | Compound | Ionic Cation | Ionic Anion | |&#8212;&#8212;&#8212;-|&#8212;&#8212;&#8212;&#8212;&#8211;|&#8212;&#8212;&#8212;&#8212;-| | NaCl | Na | Cl | | FeF2 | Fe | F | | FeCl2 | Fe | Cl | | AgBr | Ag | Br | | Cr2O3 | Cr | O |<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-50.png\" alt=\"\" class=\"wp-image-224298\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here is the corrected version of the table based on the proper ionic charges of the elements involved:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Ionic Compound<\/th><th>Cation<\/th><th>Anion<\/th><\/tr><\/thead><tbody><tr><td>NaCl<\/td><td>Na\u207a<\/td><td>Cl\u207b<\/td><\/tr><tr><td>FeF\u2083<\/td><td>Fe\u00b3\u207a<\/td><td>F\u207b<\/td><\/tr><tr><td>FeI\u2082<\/td><td>Fe\u00b2\u207a<\/td><td>I\u207b<\/td><\/tr><tr><td>AgBr<\/td><td>Ag\u207a<\/td><td>Br\u207b<\/td><\/tr><tr><td>CrO\u2082<\/td><td>Cr\u2074\u207a<\/td><td>O\u00b2\u207b<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>In binary ionic compounds, the overall charge must be neutral, which means the total positive charge from the cations must balance the total negative charge from the anions. To deduce the charges of ions in compounds, we use the known charges of common ions and simple arithmetic.<\/p>\n\n\n\n<p><strong>1. NaCl:<\/strong> Sodium (Na) is an alkali metal in Group 1, always forming a +1 ion (Na\u207a). Chlorine (Cl) is a halogen in Group 17, forming a \u22121 ion (Cl\u207b). One Na\u207a and one Cl\u207b combine to form NaCl, a neutral compound.<\/p>\n\n\n\n<p><strong>2. FeF\u2083:<\/strong> Fluoride (F\u207b) has a \u22121 charge. Since there are 3 fluoride ions, the total negative charge is \u22123. To balance it, iron (Fe) must be +3 (Fe\u00b3\u207a).<\/p>\n\n\n\n<p><strong>3. FeI\u2082:<\/strong> Iodide (I\u207b) also carries a \u22121 charge. Two I\u207b ions make \u22122 total, so iron must be Fe\u00b2\u207a to balance the charge.<\/p>\n\n\n\n<p><strong>4. AgBr:<\/strong> Silver (Ag) typically forms a +1 ion (Ag\u207a), and bromide (Br\u207b) is \u22121. They combine in a 1:1 ratio to form a neutral compound.<\/p>\n\n\n\n<p><strong>5. CrO\u2082:<\/strong> Oxygen (O) has a \u22122 charge (O\u00b2\u207b). Two O\u00b2\u207b ions give a total of \u22124. To balance this, chromium (Cr) must be +4 (Cr\u2074\u207a). Thus, CrO\u2082 contains Cr\u2074\u207a and O\u00b2\u207b ions.<\/p>\n\n\n\n<p>Understanding how to deduce ionic charges from the formula is essential for correctly writing chemical formulas and predicting chemical reactions. This involves knowledge of periodic trends and oxidation states, especially for transition metals like Fe and Cr, which can exhibit multiple possible charges.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-28.jpeg\" alt=\"\" class=\"wp-image-224299\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Deducing the ions in a binary ionic compound Complete the table below by writing the symbols for the ionic cation and anion compound. | Compound | Ionic Cation | Ionic Anion | |&#8212;&#8212;&#8212;-|&#8212;&#8212;&#8212;&#8212;&#8211;|&#8212;&#8212;&#8212;&#8212;-| | NaCl | Na | Cl | | FeF2 | Fe | F | | FeCl2 | Fe | Cl | | [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-224297","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224297","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=224297"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224297\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=224297"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=224297"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=224297"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}