{"id":224379,"date":"2025-06-03T04:57:30","date_gmt":"2025-06-03T04:57:30","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=224379"},"modified":"2025-06-03T04:57:32","modified_gmt":"2025-06-03T04:57:32","slug":"if-josh-has-5-different-pairs-of-socks-and-4-different-pairs-of-shoes","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/03\/if-josh-has-5-different-pairs-of-socks-and-4-different-pairs-of-shoes\/","title":{"rendered":"If Josh has 5 different pairs of socks and 4 different pairs of shoes"},"content":{"rendered":"\n<p>If Josh has 5 different pairs of socks and 4 different pairs of shoes, how many different combinations could he wear? 08 O 10 20 18 25<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find the number of different combinations Josh can wear, we need to multiply the number of <strong>sock combinations<\/strong> by the number of <strong>shoe combinations<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-step solution:<\/h3>\n\n\n\n<p>Josh has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>5 different <strong>pairs<\/strong> of socks<\/li>\n\n\n\n<li>4 different <strong>pairs<\/strong> of shoes<\/li>\n<\/ul>\n\n\n\n<p>Since we&#8217;re talking about <strong>pairs<\/strong>, each combination refers to <strong>one complete pair of socks<\/strong> and <strong>one complete pair of shoes<\/strong>. He chooses <strong>1 pair of socks<\/strong> from 5, and <strong>1 pair of shoes<\/strong> from 4.<\/p>\n\n\n\n<p>Using the <strong>Fundamental Principle of Counting<\/strong>, the total number of combinations is: Total&nbsp;combinations=Number&nbsp;of&nbsp;sock&nbsp;pairs\u00d7Number&nbsp;of&nbsp;shoe&nbsp;pairs=5\u00d74=20\\text{Total combinations} = \\text{Number of sock pairs} \\times \\text{Number of shoe pairs} = 5 \\times 4 = 20<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Correct Answer: <strong>20<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>This type of problem is a classic example of a <strong>combinatorics<\/strong> question, where we are asked to find the total number of <strong>outfit combinations<\/strong> Josh can make using different articles of clothing. The key here is understanding that we are combining <strong>independent choices<\/strong>: socks and shoes. Each pair of socks can be matched with <strong>any<\/strong> pair of shoes, regardless of their style, color, or type.<\/p>\n\n\n\n<p>Let\u2019s visualize:<br>Suppose the sock pairs are labeled S\u2081, S\u2082, S\u2083, S\u2084, S\u2085, and the shoe pairs are labeled H\u2081, H\u2082, H\u2083, H\u2084.<br>If Josh wears S\u2081, he has 4 options for shoes: H\u2081, H\u2082, H\u2083, H\u2084.<br>The same goes for S\u2082 through S\u2085. That\u2019s 4 shoe options for each of the 5 sock options.<br>So, we calculate: 5&nbsp;(sock&nbsp;pairs)\u00d74&nbsp;(shoe&nbsp;pairs)=20&nbsp;combinations5 \\text{ (sock pairs)} \\times 4 \\text{ (shoe pairs)} = 20 \\text{ combinations}<\/p>\n\n\n\n<p>This approach follows the <strong>multiplication principle<\/strong>, which states that if one event can happen in <em>m<\/em> ways and another independent event can happen in <em>n<\/em> ways, then the two events together can occur in <em>m \u00d7 n<\/em> ways.<\/p>\n\n\n\n<p>This is a foundational principle in mathematics that helps us calculate possibilities without listing every single combination manually.<\/p>\n\n\n\n<p>So, with 5 sock choices and 4 shoe choices, Josh has <strong>20 different ways<\/strong> to dress his feet!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-101.jpeg\" alt=\"\" class=\"wp-image-224380\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>If Josh has 5 different pairs of socks and 4 different pairs of shoes, how many different combinations could he wear? 08 O 10 20 18 25 The Correct Answer and Explanation is: To find the number of different combinations Josh can wear, we need to multiply the number of sock combinations by the number [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-224379","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224379","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=224379"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224379\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=224379"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=224379"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=224379"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}