{"id":224919,"date":"2025-06-03T16:09:23","date_gmt":"2025-06-03T16:09:23","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=224919"},"modified":"2025-06-03T16:09:25","modified_gmt":"2025-06-03T16:09:25","slug":"complete-the-table-below-by-writing-the-symbols-for-the-cation-and-anion-that-make-up-each-ionic-compound-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/03\/complete-the-table-below-by-writing-the-symbols-for-the-cation-and-anion-that-make-up-each-ionic-compound-2\/","title":{"rendered":"Complete the table below by writing the symbols for the cation and anion that make up each ionic compound"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">Deducing the ions in a polyatomic ionic compound from its empir... Complete the table below by writing the symbols for the cation and anion that make up each ionic compound. TI ionic compound NaCl V(NO3)2&nbsp;VCl5&nbsp;NH4I Mn2O3&nbsp;cation anion Na+Cl\u2212V5+Cl\u2212NH4+I\u2212<\/pre>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-80.png\" alt=\"\" class=\"wp-image-224920\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><br><br>I\u2212<\/p>\n\n\n\n<p>Let&#8217;s complete the missing entries in the table from the image and explain the reasoning behind each.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Completed Table:<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th><strong>Ionic Compound<\/strong><\/th><th><strong>Cation<\/strong><\/th><th><strong>Anion<\/strong><\/th><\/tr><\/thead><tbody><tr><td>NaCl<\/td><td>Na\u207a<\/td><td>Cl\u207b<\/td><\/tr><tr><td>V(NO\u2083)\u2082<\/td><td>V\u00b3\u207a<\/td><td>NO\u2083\u207b<\/td><\/tr><tr><td>VCl\u2085<\/td><td>V\u2075\u207a<\/td><td>Cl\u207b<\/td><\/tr><tr><td>NH\u2084I<\/td><td>NH\u2084\u207a<\/td><td>I\u207b<\/td><\/tr><tr><td>Mn\u2082O\u2083<\/td><td>Mn\u00b3\u207a<\/td><td>O\u00b2\u207b<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>To deduce the ions in a polyatomic ionic compound, we need to understand the rules of ionic bonding and oxidation states. Ionic compounds consist of positively charged ions (cations) and negatively charged ions (anions) combined in ratios that result in an overall neutral compound.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>NaCl<\/strong>: Sodium (Na) is an alkali metal and forms a +1 cation (Na\u207a). Chloride (Cl) is a halogen and forms a -1 anion (Cl\u207b). Their 1:1 ratio balances the charges.<\/li>\n\n\n\n<li><strong>V(NO\u2083)\u2082<\/strong>: The nitrate ion (NO\u2083\u207b) is a polyatomic ion with a -1 charge. There are two nitrate ions, contributing a total of -2 charge. Therefore, the vanadium (V) must have a +3 charge to balance it (V\u00b3\u207a).<\/li>\n\n\n\n<li><strong>VCl\u2085<\/strong>: There are five chloride ions (Cl\u207b), each with a -1 charge, totaling -5. To balance this, vanadium must have a +5 charge (V\u2075\u207a).<\/li>\n\n\n\n<li><strong>NH\u2084I<\/strong>: Ammonium (NH\u2084\u207a) is a common polyatomic cation with a +1 charge. Iodide (I\u207b) is a halogen anion with a -1 charge. Their charges cancel out in a 1:1 ratio.<\/li>\n\n\n\n<li><strong>Mn\u2082O\u2083<\/strong>: Oxygen (O) forms a -2 anion (O\u00b2\u207b). Three oxide ions give a total of -6 charge. To balance this, two manganese (Mn) ions must contribute +6 total, so each Mn is +3 (Mn\u00b3\u207a).<\/li>\n<\/ol>\n\n\n\n<p>Understanding these principles allows us to systematically determine the correct cations and anions in any given compound using the total charge balance and known ion charges.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-137.jpeg\" alt=\"\" class=\"wp-image-224921\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Deducing the ions in a polyatomic ionic compound from its empir&#8230; Complete the table below by writing the symbols for the cation and anion that make up each ionic compound. TI ionic compound NaCl V(NO3)2&nbsp;VCl5&nbsp;NH4I Mn2O3&nbsp;cation anion Na+Cl\u2212V5+Cl\u2212NH4+I\u2212 The Correct Answer and Explanation is: I\u2212 Let&#8217;s complete the missing entries in the table from the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-224919","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224919","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=224919"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/224919\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=224919"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=224919"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=224919"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}