{"id":225129,"date":"2025-06-03T20:31:24","date_gmt":"2025-06-03T20:31:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=225129"},"modified":"2025-06-03T20:31:26","modified_gmt":"2025-06-03T20:31:26","slug":"draw-the-skeletal-line-bond-structure-of-n-cyclohexyl-3-hexanamine","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/03\/draw-the-skeletal-line-bond-structure-of-n-cyclohexyl-3-hexanamine\/","title":{"rendered":"Draw the skeletal (line-bond) structure of N-cyclohexyl-3-hexanamine."},"content":{"rendered":"\n<p>Draw the skeletal (line-bond) structure of N-cyclohexyl-3-hexanamine.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Skeletal (Line-Bond) Structure of N-cyclohexyl-3-hexanamine<\/h3>\n\n\n\n<p>Here&#8217;s the <strong>skeletal structure<\/strong> (described in text since drawing is not possible directly in text):<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>           NH\n            |\nCH3-CH2-CH-CH2-CH2-CH3\n            |\n        Cyclohexyl ring\n<\/code><\/pre>\n\n\n\n<p>Or more precisely, in skeletal (line-bond) format:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>        ______\n       \/      \\\n      |        |\n      |        |\n       \\______\/\n           |\nCH3-CH2-CH-CH2-CH2-CH3\n           |\n           NH\n<\/code><\/pre>\n\n\n\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\">\n<p>Note: The nitrogen (N) is <strong>bonded to<\/strong> the cyclohexyl ring and to the <strong>third carbon<\/strong> of a hexane chain. That makes it <strong>N-cyclohexyl-3-hexanamine<\/strong>.<\/p>\n<\/blockquote>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p><strong>N-cyclohexyl-3-hexanamine<\/strong> is a substituted amine, where a <strong>cyclohexyl group<\/strong> is bonded to the <strong>nitrogen atom (N)<\/strong> of a <strong>3-hexanamine<\/strong> backbone. To understand its structure, we must first break down the name according to IUPAC nomenclature.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Parent Chain: 3-hexanamine<\/strong>\n<ul class=\"wp-block-list\">\n<li>&#8220;Hexanamine&#8221; refers to a six-carbon linear alkane chain (hexane) with an amino group (-NH\u2082).<\/li>\n\n\n\n<li>The &#8220;3-&#8221; indicates that the amine group is on the <strong>third carbon<\/strong> of the chain.<\/li>\n\n\n\n<li>The structure of 3-hexanamine:<br>CH\u2083\u2013CH\u2082\u2013CH(NH\u2082)\u2013CH\u2082\u2013CH\u2082\u2013CH\u2083<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>N-cyclohexyl Substitution<\/strong>:\n<ul class=\"wp-block-list\">\n<li>The prefix &#8220;N-cyclohexyl&#8221; means the <strong>hydrogen of the amino group<\/strong> is replaced by a cyclohexyl group (a six-membered carbon ring).<\/li>\n\n\n\n<li>Instead of a primary amine (-NH\u2082), the molecule becomes a <strong>secondary amine<\/strong>, where the nitrogen is bonded to:\n<ul class=\"wp-block-list\">\n<li>The 3rd carbon of hexane<\/li>\n\n\n\n<li>A cyclohexyl ring<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Skeletal Structure<\/strong>:\n<ul class=\"wp-block-list\">\n<li>In line-bond (skeletal) structures, <strong>carbon atoms are implied<\/strong> at the ends and intersections of lines.<\/li>\n\n\n\n<li>Hydrogen atoms attached to carbons are usually omitted.<\/li>\n\n\n\n<li>Functional groups (like NH) are often shown explicitly when relevant.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>So, the structure features:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A straight six-carbon chain<\/li>\n\n\n\n<li>An NH bonded to carbon 3<\/li>\n\n\n\n<li>The N also bonded to a cyclohexyl ring<\/li>\n<\/ul>\n\n\n\n<p>This skeletal format helps chemists quickly visualize molecular shape and functional groups, crucial for understanding reactivity and physical properties.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-65.jpeg\" alt=\"\" class=\"wp-image-225130\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the skeletal (line-bond) structure of N-cyclohexyl-3-hexanamine. The Correct Answer and Explanation is: Skeletal (Line-Bond) Structure of N-cyclohexyl-3-hexanamine Here&#8217;s the skeletal structure (described in text since drawing is not possible directly in text): Or more precisely, in skeletal (line-bond) format: Note: The nitrogen (N) is bonded to the cyclohexyl ring and to the third carbon [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-225129","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225129","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=225129"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225129\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=225129"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=225129"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=225129"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}