{"id":225191,"date":"2025-06-04T04:57:52","date_gmt":"2025-06-04T04:57:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=225191"},"modified":"2025-06-04T04:57:55","modified_gmt":"2025-06-04T04:57:55","slug":"name-the-following-compound-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/name-the-following-compound-3\/","title":{"rendered":"Name the following compound"},"content":{"rendered":"\n<p> Name the following compound: ZnCO3 a) Zinc (II) carbonate b) Zinc (I) carbonate c) Zinc carbonate d) Zinc carbide QUESTION 14 The correct name for SrO is: a) strontium(II) oxide b) strontium hydroxide c) strontium oxide d) strontium monoxide QUESTION 15 Of the choices below, which one is a molecular compound? a) FeCl2 b) KBr c) RbCl d) OF2<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>QUESTION 13<\/strong><br><strong>Name the following compound: ZnCO\u2083<\/strong><br><strong>Correct answer: a) Zinc (II) carbonate<\/strong><\/p>\n\n\n\n<p><strong>QUESTION 14<\/strong><br><strong>The correct name for SrO is:<\/strong><br><strong>Correct answer: c) strontium oxide<\/strong><\/p>\n\n\n\n<p><strong>QUESTION 15<\/strong><br><strong>Which one is a molecular compound?<\/strong><br><strong>Correct answer: d) OF\u2082<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p><strong>Question 13 \u2013 ZnCO\u2083: Zinc (II) carbonate<\/strong><br>Zinc carbonate is composed of the zinc ion (Zn\u00b2\u207a) and the carbonate ion (CO\u2083\u00b2\u207b). Since zinc commonly forms only a +2 charge, the Roman numeral II is appropriate, even though it&#8217;s often omitted for elements with fixed oxidation states like Zn. So, the correct IUPAC name is <strong>zinc (II) carbonate<\/strong>. Option <strong>a<\/strong> is correct. Options b and c are incorrect because Zn\u207a (zinc I) does not exist in stable compounds. Option d, zinc carbide, is unrelated.<\/p>\n\n\n\n<p><strong>Question 14 \u2013 SrO: strontium oxide<\/strong><br>Strontium (Sr) is an alkaline earth metal that always forms a +2 charge (Sr\u00b2\u207a). Oxygen typically has a \u22122 charge (O\u00b2\u207b). Combining them in a 1:1 ratio yields SrO. Because Sr has a fixed oxidation state, there&#8217;s no need to specify it with Roman numerals. Thus, <strong>strontium oxide<\/strong> is the correct name, making option <strong>c<\/strong> the right answer. Option a is incorrect because the Roman numeral is unnecessary. Option b refers to a different compound entirely (Sr(OH)\u2082), and option d is not a conventional or correct name.<\/p>\n\n\n\n<p><strong>Question 15 \u2013 Molecular compound: OF\u2082<\/strong><br>Molecular compounds are typically formed between two nonmetals. OF\u2082 (oxygen difluoride) consists of two nonmetals: oxygen and fluorine. These elements form covalent bonds, making it a molecular compound. In contrast:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>FeCl\u2082 is an ionic compound (metal + nonmetal),<\/li>\n\n\n\n<li>KBr is ionic (metal + nonmetal),<\/li>\n\n\n\n<li>RbCl is also ionic (metal + nonmetal).<\/li>\n<\/ul>\n\n\n\n<p>Therefore, the only molecular compound among the options is <strong>OF\u2082<\/strong>, making <strong>d<\/strong> the correct choice.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-149.jpeg\" alt=\"\" class=\"wp-image-225192\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Name the following compound: ZnCO3 a) Zinc (II) carbonate b) Zinc (I) carbonate c) Zinc carbonate d) Zinc carbide QUESTION 14 The correct name for SrO is: a) strontium(II) oxide b) strontium hydroxide c) strontium oxide d) strontium monoxide QUESTION 15 Of the choices below, which one is a molecular compound? a) FeCl2 b) KBr [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-225191","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225191","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=225191"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225191\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=225191"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=225191"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=225191"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}