{"id":225393,"date":"2025-06-04T07:54:03","date_gmt":"2025-06-04T07:54:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=225393"},"modified":"2025-06-04T07:54:05","modified_gmt":"2025-06-04T07:54:05","slug":"the-typical-temperature-in-a-hospital-room-is-set-at-23-5-c","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/the-typical-temperature-in-a-hospital-room-is-set-at-23-5-c\/","title":{"rendered":"The typical temperature in a hospital room is set at 23.5 \u00b0C"},"content":{"rendered":"\n<p>[35] The typical temperature in a hospital room is set at 23.5 \u00b0C. What is that temperature in degrees Fahrenheit (\u00b0F)? [36] Determine the mass of Ca(HCO<br>)<br>the following substance in amu (u) [37] Consider this thermochemical equation: 2CO(g) + O<br>(g) ? 2CO<br>(g) ?H = -565 kJ Is it exothermic or endothermic? How much energy is given off or absorbed? [38] How many protons, electrons and neutrons are in<br>Fe<br>? Protons (p) electrons (e) neutrons (n) [39] Give the proper formula for each name Iron(III)Chloride Potassium sulfate Dinitrogen pentoxide [40] Give the proper name for each molecule NO CS<br>Al<br>O<br>Extra Credit: 5 points (Questions can be from any chapter, following are just examples) 1. How many joules are needed to melt 15.0 g of ice at 0 \u00b0C? (Heat of fusion = 334 J\/g) 2. Perform the following conversion: 60.0 km\/hr to m\/s<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>[35] Convert 23.5 \u00b0C to \u00b0F<\/strong><\/h3>\n\n\n\n<p>Use the formula: \u00b0F=(\u00b0C\u00d795)+32\u00b0F = (\u00b0C \\times \\frac{9}{5}) + 32 \u00b0F=(23.5\u00d795)+32=74.3\u00b0F\u00b0F = (23.5 \\times \\frac{9}{5}) + 32 = 74.3\u00b0F<\/p>\n\n\n\n<p>\u2705 <strong>Answer: 74.3 \u00b0F<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>[36] Determine the mass of Ca(HCO\u2083)\u2082 in amu (u)<\/strong><\/h3>\n\n\n\n<p>Find the molar mass by summing atomic masses (approximate values):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ca = 40.08 u<\/li>\n\n\n\n<li>H = 1.01 u<\/li>\n\n\n\n<li>C = 12.01 u<\/li>\n\n\n\n<li>O = 16.00 u<\/li>\n<\/ul>\n\n\n\n<p>Mass&nbsp;of&nbsp;Ca(HCO\u2083)\u2082=40.08+2(1.01+12.01+3\u00d716.00)=40.08+2(1.01+12.01+48.00)=40.08+2(61.02)=40.08+122.04=162.12&nbsp;u\\text{Mass of } \\text{Ca(HCO\u2083)\u2082} = 40.08 + 2(1.01 + 12.01 + 3 \\times 16.00) = 40.08 + 2(1.01 + 12.01 + 48.00) = 40.08 + 2(61.02) = 40.08 + 122.04 = 162.12\\ \\text{u}<\/p>\n\n\n\n<p>\u2705 <strong>Answer: 162.12 amu<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>[37] Thermochemical Equation:<\/strong><\/h3>\n\n\n\n<p>2CO(g)+O2(g)\u21922CO2(g)\u0394H=\u2212565&nbsp;kJ2CO(g) + O\u2082(g) \\rightarrow 2CO\u2082(g) \\quad \\Delta H = -565\\ \\text{kJ}<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Negative \u0394H \u21d2 <strong>Exothermic<\/strong> (releases heat)<\/li>\n<\/ul>\n\n\n\n<p>\u2705 <strong>Answer: Exothermic; 565 kJ is given off<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>[38] Number of Protons, Electrons, and Neutrons in Fe (Iron)<\/strong><\/h3>\n\n\n\n<p>For neutral <strong>Fe-56 (most common isotope)<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Atomic number = 26 \u21d2 <strong>26 protons<\/strong>, <strong>26 electrons<\/strong><\/li>\n\n\n\n<li>Mass number = 56 \u21d2 <strong>56 \u2013 26 = 30 neutrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p>\u2705 <strong>Answer:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Protons: 26<\/li>\n\n\n\n<li>Electrons: 26<\/li>\n\n\n\n<li>Neutrons: 30<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>[39] Give the proper formula:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Iron(III) Chloride<\/strong> \u2192 Fe\u00b3\u207a + 3Cl\u207b \u2192 <strong>FeCl\u2083<\/strong><\/li>\n\n\n\n<li><strong>Potassium sulfate<\/strong> \u2192 K\u207a and SO\u2084\u00b2\u207b \u2192 K\u2082SO\u2084<\/li>\n\n\n\n<li><strong>Dinitrogen pentoxide<\/strong> \u2192 N\u2082O\u2085<\/li>\n<\/ul>\n\n\n\n<p>\u2705 <strong>Answer:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Iron(III) Chloride: <strong>FeCl\u2083<\/strong><\/li>\n\n\n\n<li>Potassium sulfate: <strong>K\u2082SO\u2084<\/strong><\/li>\n\n\n\n<li>Dinitrogen pentoxide: <strong>N\u2082O\u2085<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>[40] Name the following molecules:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>NO<\/strong> \u2192 Nitrogen monoxide<\/li>\n\n\n\n<li><strong>CS\u2082<\/strong> \u2192 Carbon disulfide<\/li>\n\n\n\n<li><strong>Al\u2082O\u2083<\/strong> \u2192 Aluminum oxide<\/li>\n<\/ul>\n\n\n\n<p>\u2705 <strong>Answer:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>NO: <strong>Nitrogen monoxide<\/strong><\/li>\n\n\n\n<li>CS\u2082: <strong>Carbon disulfide<\/strong><\/li>\n\n\n\n<li>Al\u2082O\u2083: <strong>Aluminum oxide<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">\ud83d\udd25 Extra Credit<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. How many joules to melt 15.0 g of ice at 0 \u00b0C?<\/strong><\/h3>\n\n\n\n<p>q=m\u00d7\u0394Hfus=15.0&nbsp;g\u00d7334&nbsp;J\/g=5010&nbsp;J\\text{q} = m \\times \\Delta H_{\\text{fus}} = 15.0\\ \\text{g} \\times 334\\ \\text{J\/g} = 5010\\ \\text{J}<\/p>\n\n\n\n<p>\u2705 <strong>Answer: 5010 J<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Convert 60.0 km\/hr to m\/s<\/strong><\/h3>\n\n\n\n<p>60.0&nbsp;km\/hr=60.0\u00d71000&nbsp;m1&nbsp;km\u00d71&nbsp;hr3600&nbsp;s=600003600=16.67&nbsp;m\/s60.0\\ \\text{km\/hr} = 60.0 \\times \\frac{1000\\ \\text{m}}{1\\ \\text{km}} \\times \\frac{1\\ \\text{hr}}{3600\\ \\text{s}} = \\frac{60000}{3600} = 16.67\\ \\text{m\/s}<\/p>\n\n\n\n<p>\u2705 <strong>Answer: 16.67 m\/s<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading\">\ud83d\udcd8 Explanation of Key Concepts (Condensed Version)<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Temperature Conversion<\/h3>\n\n\n\n<p>Temperature in Celsius (\u00b0C) can be converted to Fahrenheit (\u00b0F) using: \u00b0F=(\u00b0C\u00d795)+32\u00b0F = \\left(\u00b0C \\times \\frac{9}{5}\\right) + 32<\/p>\n\n\n\n<p>This is important for comparing medical, scientific, or weather measurements across systems (metric vs imperial).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Atomic Mass \/ AMU<\/h3>\n\n\n\n<p>Atomic Mass Unit (amu or u) measures mass on the atomic scale. To calculate a compound\u2019s mass in amu:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Multiply each atom\u2019s atomic mass by how many are in the formula.<\/li>\n\n\n\n<li>Sum all components.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Thermochemistry: Endothermic vs Exothermic<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Exothermic<\/strong>: Releases energy (\u0394H &lt; 0)<\/li>\n\n\n\n<li><strong>Endothermic<\/strong>: Absorbs energy (\u0394H > 0)<br>In this question, \u0394H = -565 kJ, meaning energy is <strong>released<\/strong> during the combustion of CO.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Subatomic Particles<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Protons<\/strong> determine the element&#8217;s identity.<\/li>\n\n\n\n<li><strong>Electrons<\/strong> equal protons in a neutral atom.<\/li>\n\n\n\n<li><strong>Neutrons<\/strong> = mass number \u2212 atomic number.<\/li>\n<\/ul>\n\n\n\n<p>Fe (Iron), atomic number 26, most common isotope Fe-56:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>26 protons<\/li>\n\n\n\n<li>26 electrons<\/li>\n\n\n\n<li>30 neutrons<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Chemical Formulas<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ionic Compounds<\/strong>: Combine cations and anions in ratios that balance the charges.\n<ul class=\"wp-block-list\">\n<li>Iron(III) = Fe\u00b3\u207a, Chloride = Cl\u207b \u2192 FeCl\u2083<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Molecular Compounds<\/strong>: Use prefixes to denote atom counts.\n<ul class=\"wp-block-list\">\n<li>Dinitrogen pentoxide = N\u2082O\u2085<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Molecular Naming<\/h3>\n\n\n\n<p>Rules for molecular naming (nonmetals):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Use prefixes (mono-, di-, tri-, etc.)<\/li>\n\n\n\n<li>Second element ends in \u201c-ide\u201d<\/li>\n<\/ul>\n\n\n\n<p>Examples:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>NO \u2192 Nitrogen monoxide<\/li>\n\n\n\n<li>CS\u2082 \u2192 Carbon disulfide<\/li>\n\n\n\n<li>Al\u2082O\u2083 \u2192 Aluminum oxide (ionic compound; no prefixes)<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Phase Change Energy<\/h3>\n\n\n\n<p>To melt ice: q=m\u00d7\u0394Hfusionq = m \\times \\Delta H_{\\text{fusion}}<\/p>\n\n\n\n<p>Heat of fusion is the energy required to melt 1 gram of a substance without temperature change. For water, it&#8217;s 334 J\/g.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Unit Conversion<\/h3>\n\n\n\n<p>Use conversion factors: 60.0&nbsp;km\/hr\u00d71000&nbsp;m1&nbsp;km\u00d71&nbsp;hr3600&nbsp;s=16.67&nbsp;m\/s60.0\\ \\text{km\/hr} \\times \\frac{1000\\ \\text{m}}{1\\ \\text{km}} \\times \\frac{1\\ \\text{hr}}{3600\\ \\text{s}} = 16.67\\ \\text{m\/s}<\/p>\n\n\n\n<p>Unit analysis is crucial to solving any physics or chemistry problem involving different measurement systems.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-69.jpeg\" alt=\"\" class=\"wp-image-225394\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>[35] The typical temperature in a hospital room is set at 23.5 \u00b0C. What is that temperature in degrees Fahrenheit (\u00b0F)? [36] Determine the mass of Ca(HCO)the following substance in amu (u) [37] Consider this thermochemical equation: 2CO(g) + O(g) ? 2CO(g) ?H = -565 kJ Is it exothermic or endothermic? How much energy is [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-225393","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225393","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=225393"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225393\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=225393"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=225393"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=225393"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}