{"id":225726,"date":"2025-06-04T12:13:17","date_gmt":"2025-06-04T12:13:17","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=225726"},"modified":"2025-06-04T12:13:19","modified_gmt":"2025-06-04T12:13:19","slug":"finish-reason-code","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/finish-reason-code\/","title":{"rendered":"Finish reason code"},"content":{"rendered":"\n

Finish reason code: 3<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Let’s analyze the structure of Viagra (sildenafil citrate)<\/strong> as shown in the image and answer each part of the question:<\/p>\n\n\n\n

\n\n\n\n

A. How many sp\u00b2 hybridized atoms are there in this molecule?<\/strong><\/h3>\n\n\n\n

Answer:<\/strong> 24
Explanation: sp\u00b2 hybridization typically occurs in atoms involved in double bonds or part of aromatic rings. In Viagra, we see multiple aromatic rings and carbonyl groups (C=O), where both carbon and oxygen (the O involved in a double bond) are sp\u00b2 hybridized. Counting these atoms carefully across all aromatic rings and double-bonded structures gives 24 sp\u00b2 hybridized atoms<\/strong>.<\/p>\n\n\n\n

\n\n\n\n

B. How many sp\u00b3 carbons are there in this molecule?<\/strong><\/h3>\n\n\n\n

Answer:<\/strong> 13
Explanation: sp\u00b3 carbon atoms are tetrahedrally bonded to four other atoms (single bonds only). In the Viagra structure, you can find several such carbon atoms in the aliphatic chains and ring systems not involved in double bonds or aromaticity. A precise count gives 13 sp\u00b3 hybridized carbon atoms<\/strong>.<\/p>\n\n\n\n

\n\n\n\n

C. What is the chemical formula of Viagra?<\/strong><\/h3>\n\n\n\n

Answer:<\/strong> C22H30N6O4S<\/strong>
Explanation: Counting all atoms in the displayed skeletal structure (not including citrate), the molecular formula for sildenafil<\/strong>, the active component in Viagra, is C22H30N6O4S<\/strong>. The citrate salt form may have a different formula, but this refers to the base molecule.<\/p>\n\n\n\n

\n\n\n\n

D. How many lone pairs of electrons are in Viagra?<\/strong><\/h3>\n\n\n\n

Answer:<\/strong> 16
Explanation: Lone pairs are found on heteroatoms such as N, O, and S. Each oxygen has 2 lone pairs, each nitrogen typically has 1 lone pair, and sulfur generally has 2 lone pairs. Adding lone pairs from:<\/p>\n\n\n\n

    \n
  • 4 nitrogen atoms \u2192 4 lone pairs<\/li>\n\n\n\n
  • 4 oxygen atoms \u2192 8 lone pairs<\/li>\n\n\n\n
  • 1 sulfur atom \u2192 2 lone pairs
    Total: 4 + 8 + 2 = 14<\/strong> lone pairs
    Correction:<\/strong> After revisiting, the total lone pairs should be 14<\/strong>, not 16.<\/li>\n<\/ul>\n\n\n\n
    \n\n\n\n

    E. Functional Groups in Viagra<\/strong><\/h3>\n\n\n\n
    Functional Group<\/th>Identifying Shape Used<\/th><\/tr><\/thead>
    Aromatic rings (benzene)<\/td>Circles<\/td><\/tr>
    Sulfonamide<\/td>Triangle<\/td><\/tr>
    Secondary amine<\/td>Square<\/td><\/tr>
    Piperazine ring<\/td>Hexagon<\/td><\/tr>
    Carbonyl (ketone)<\/td>Diamond<\/td><\/tr>
    Pyrimidine ring (heterocycle)<\/td>Star<\/td><\/tr>
    Alkyl chain<\/td>Line<\/td><\/tr>
    Ether<\/td>Oval<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
    \n\n\n\n

    Summary<\/strong><\/h3>\n\n\n\n

    The molecular structure of Viagra (sildenafil) is a complex organic compound containing several functional groups and hybridized atoms. Analyzing this structure helps to understand the molecular interactions responsible for its pharmacological action.<\/p>\n\n\n\n

    The molecule has 24 sp\u00b2 hybridized atoms<\/strong>, mostly due to the presence of aromatic rings and carbonyl groups. These atoms have a trigonal planar geometry and contribute to the molecule\u2019s planarity in parts, aiding in stacking interactions with biological targets. In contrast, 13 sp\u00b3 hybridized carbon atoms<\/strong> introduce flexibility and 3D conformation to the structure, necessary for fitting into enzyme binding pockets.<\/p>\n\n\n\n

    The chemical formula, C22H30N6O4S<\/strong>, is derived by counting all atoms shown in the skeletal structure. This formula corresponds to sildenafil, the active ingredient in Viagra, excluding the citrate salt often included in pharmaceutical formulations.<\/p>\n\n\n\n

    Lone pairs play a critical role in molecular recognition and hydrogen bonding. In Viagra, lone pairs on nitrogen, oxygen, and sulfur atoms contribute to its solubility and interaction with the enzyme phosphodiesterase-5 (PDE5). There are 14 lone pairs<\/strong> in total, supporting its ability to engage in multiple non-covalent interactions.<\/p>\n\n\n\n

    Functionally, the molecule contains a variety of groups, including aromatic rings<\/strong>, sulfonamides<\/strong>, amines<\/strong>, carbonyls<\/strong>, and heterocycles like the pyrimidine ring<\/strong>. Each group contributes specific properties\u2014like hydrogen bonding, electron donation or withdrawal, and steric configuration\u2014that determine the drug\u2019s efficacy.<\/p>\n\n\n\n

    Understanding the structure-function relationship of Viagra not only provides insight into its biological role but also exemplifies how medicinal chemistry leverages structural motifs to design effective therapeutics.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    Finish reason code: 3 The Correct Answer and Explanation is: Let’s analyze the structure of Viagra (sildenafil citrate) as shown in the image and answer each part of the question: A. How many sp\u00b2 hybridized atoms are there in this molecule? Answer: 24Explanation: sp\u00b2 hybridization typically occurs in atoms involved in double bonds or part […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-225726","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225726","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=225726"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225726\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=225726"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=225726"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=225726"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}