{"id":225885,"date":"2025-06-04T17:53:41","date_gmt":"2025-06-04T17:53:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=225885"},"modified":"2025-06-04T17:53:43","modified_gmt":"2025-06-04T17:53:43","slug":"write-the-lewis-structure-for-each-molecule","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/write-the-lewis-structure-for-each-molecule\/","title":{"rendered":"write the lewis structure for each molecule"},"content":{"rendered":"\n<p>write the lewis structure for each molecule : a.CH2O b. C2Cl4<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>a. CH\u2082O (Formaldehyde)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>     H\n     |\nH \u2013 C = O\n     ||\n     O\n<\/code><\/pre>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>Formaldehyde (CH\u2082O) consists of one carbon (C), two hydrogen (H), and one oxygen (O) atom. To draw the Lewis structure, start by calculating the <strong>total number of valence electrons<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) = 4 valence electrons<\/li>\n\n\n\n<li>Hydrogen (H) = 1 each \u00d7 2 = 2<\/li>\n\n\n\n<li>Oxygen (O) = 6<br><strong>Total = 4 + 2 + 6 = 12 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Carbon is the central atom because it can form the most bonds. The two hydrogens attach to carbon with single bonds (2 electrons each), using 4 electrons. Oxygen bonds to carbon, and to fulfill the octet rule, carbon and oxygen form a double bond. That uses 4 more electrons (a total of 8 now used).<\/p>\n\n\n\n<p>Oxygen still needs to complete its octet, so we place two lone pairs (4 electrons) on oxygen. Carbon now has 4 bonds (8 electrons), and oxygen has 2 bonds and 2 lone pairs (also 8 electrons). The hydrogens have 2 electrons each, completing their duet. All atoms satisfy the octet or duet rule.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>b. C\u2082Cl\u2084 (Tetrachloroethene)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>Cl    Cl\n \\    \/\n  C = C\n \/    \\\nCl    Cl\n<\/code><\/pre>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>Tetrachloroethene (C\u2082Cl\u2084) has 2 carbon atoms and 4 chlorine atoms.<\/p>\n\n\n\n<p>Valence electrons:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon = 4 \u00d7 2 = 8<\/li>\n\n\n\n<li>Chlorine = 7 \u00d7 4 = 28<br><strong>Total = 8 + 28 = 36 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Start by connecting the two carbon atoms with a <strong>double bond<\/strong>. Each carbon is then bonded to <strong>two chlorine atoms<\/strong>. This makes 4 bonds per carbon (satisfying the octet rule). Each Cl atom forms one single bond and needs 3 lone pairs (6 electrons) to complete its octet.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>4 Cl atoms \u00d7 6 electrons = 24<\/li>\n\n\n\n<li>2 C\u2013C bonds = 4<\/li>\n\n\n\n<li>4 C\u2013Cl bonds = 8<br><strong>Total used = 24 + 4 + 8 = 36 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p>All atoms obey the octet rule. The Lewis structure is correct and shows that the carbon atoms are double-bonded and each bonded to two chlorine atoms.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-371.jpeg\" alt=\"\" class=\"wp-image-225886\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n","protected":false},"excerpt":{"rendered":"<p>write the lewis structure for each molecule : a.CH2O b. C2Cl4 The correct Answer and Explanation is: a. CH\u2082O (Formaldehyde) Lewis Structure: Explanation: Formaldehyde (CH\u2082O) consists of one carbon (C), two hydrogen (H), and one oxygen (O) atom. To draw the Lewis structure, start by calculating the total number of valence electrons: Carbon is the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-225885","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225885","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=225885"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225885\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=225885"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=225885"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=225885"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}