{"id":225949,"date":"2025-06-04T18:51:37","date_gmt":"2025-06-04T18:51:37","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=225949"},"modified":"2025-06-04T18:51:39","modified_gmt":"2025-06-04T18:51:39","slug":"which-molecule-is-most-polar","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/which-molecule-is-most-polar\/","title":{"rendered":"Which molecule is most polar"},"content":{"rendered":"\n<p>Which molecule is most polar? CHF3, CF4, CClF3, CCl4<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The most polar molecule among <strong>CHF\u2083, CF\u2084, CClF\u2083, and CCl\u2084<\/strong> is <strong>CHF\u2083 (fluoroform)<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>To determine which molecule is most polar, we need to understand <strong>molecular polarity<\/strong>, which is influenced by two main factors:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Electronegativity differences<\/strong> between atoms in a bond.<\/li>\n\n\n\n<li><strong>Molecular geometry<\/strong>, which affects how individual bond dipoles add or cancel out.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Molecular Shapes and Symmetry<\/strong><\/h3>\n\n\n\n<p>All four molecules are <strong>tetrahedral<\/strong> in geometry since the central atom (carbon) forms four single bonds with surrounding atoms.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CF\u2084 (carbon tetrafluoride)<\/strong> and <strong>CCl\u2084 (carbon tetrachloride)<\/strong> are <strong>symmetrical<\/strong> molecules. All four substituents are the same, so the individual bond dipoles cancel out. Thus, both are <strong>non-polar<\/strong>.<\/li>\n\n\n\n<li><strong>CHF\u2083<\/strong> and <strong>CClF\u2083<\/strong> are <strong>asymmetrical<\/strong>, with one different atom among the four substituents. This asymmetry leads to a <strong>net dipole moment<\/strong>, making them <strong>polar molecules<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Electronegativity Considerations<\/strong><\/h3>\n\n\n\n<p>Electronegativity values:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>F (fluorine): 3.98<\/li>\n\n\n\n<li>Cl (chlorine): 3.16<\/li>\n\n\n\n<li>H (hydrogen): 2.20<\/li>\n\n\n\n<li>C (carbon): 2.55<\/li>\n<\/ul>\n\n\n\n<p>In <strong>CHF\u2083<\/strong>, the C\u2013F bonds are highly polar due to the large electronegativity difference. The single C\u2013H bond is much less polar and does <strong>not cancel<\/strong> the strong C\u2013F dipoles, resulting in a <strong>strong net dipole<\/strong>.<\/p>\n\n\n\n<p>In <strong>CClF\u2083<\/strong>, the dipole of the lone C\u2013Cl bond partially cancels the dipoles from the three C\u2013F bonds, but because Cl is more electronegative than H, the cancellation is more effective compared to CHF\u2083, making CClF\u2083 <strong>less polar<\/strong> than CHF\u2083.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Most polar<\/strong>: <strong>CHF\u2083<\/strong>, due to its strong C\u2013F dipoles and the low polarity of the C\u2013H bond, which fails to cancel out the fluorine&#8217;s pull.<\/li>\n\n\n\n<li><strong>Least polar (non-polar)<\/strong>: <strong>CF\u2084<\/strong> and <strong>CCl\u2084<\/strong>, due to their perfect symmetry.<\/li>\n\n\n\n<li><strong>Intermediate<\/strong>: <strong>CClF\u2083<\/strong>, polar but less than CHF\u2083.<\/li>\n<\/ul>\n\n\n\n<p>Thus, <strong>CHF\u2083 is the most polar molecule<\/strong> among the four.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-379.jpeg\" alt=\"\" class=\"wp-image-225950\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which molecule is most polar? CHF3, CF4, CClF3, CCl4 The Correct Answer and Explanation is: The most polar molecule among CHF\u2083, CF\u2084, CClF\u2083, and CCl\u2084 is CHF\u2083 (fluoroform). Explanation To determine which molecule is most polar, we need to understand molecular polarity, which is influenced by two main factors: 1. Molecular Shapes and Symmetry All [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-225949","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225949","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=225949"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/225949\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=225949"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=225949"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=225949"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}