{"id":226147,"date":"2025-06-04T21:44:00","date_gmt":"2025-06-04T21:44:00","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226147"},"modified":"2025-06-04T21:44:02","modified_gmt":"2025-06-04T21:44:02","slug":"match-each-thermodynamic-symbol-with-its-correct-definition","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/match-each-thermodynamic-symbol-with-its-correct-definition\/","title":{"rendered":"Match each thermodynamic symbol with its correct definition."},"content":{"rendered":"\n<p>Match each thermodynamic symbol with its correct definition. Drag statements on the right to match the left AH&#8221; The enthalpy change of rcaction measured at thc standard state The enthalpy change when mole of compound forms from Its elements In thelr standard states AH<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here\u2019s how to correctly match each thermodynamic symbol with its definition:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>\u0394H\u00b0<\/strong>: <em>The enthalpy change of a reaction measured at the standard state.<\/em><\/p>\n\n\n\n<p><strong>\u0394Hf\u00b0<\/strong>: <em>The enthalpy change when 1 mole of a compound forms from its elements in their standard states.<\/em><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>In thermodynamics, <strong>enthalpy change (\u0394H)<\/strong> represents the heat absorbed or released during a chemical reaction at constant pressure. Enthalpy is a state function, meaning it depends only on the initial and final states of the system, not on the path taken.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>\u0394H\u00b0 \u2013 Standard Enthalpy Change of Reaction<\/strong><\/h4>\n\n\n\n<p>The symbol <strong>\u0394H\u00b0<\/strong> specifically refers to the <strong>enthalpy change of a reaction under standard conditions<\/strong>. Standard conditions mean:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Temperature = 298 K (25\u00b0C)<\/li>\n\n\n\n<li>Pressure = 1 atm<\/li>\n\n\n\n<li>All reactants and products in their standard states (pure solids, pure liquids, or 1 M solutions)<\/li>\n<\/ul>\n\n\n\n<p>This value helps chemists understand how much heat is released or absorbed in a reaction when all substances are in a defined state, making reactions easier to compare. For example, in a combustion reaction, \u0394H\u00b0 tells us how much heat is released when a substance burns in oxygen.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>\u0394Hf\u00b0 \u2013 Standard Enthalpy of Formation<\/strong><\/h4>\n\n\n\n<p>The symbol <strong>\u0394Hf\u00b0<\/strong> stands for the <strong>standard enthalpy of formation<\/strong>, which is the enthalpy change when <strong>1 mole of a compound<\/strong> is <strong>formed from its elements<\/strong> in their most stable forms under standard conditions. For example, the formation of water from hydrogen and oxygen: H2(g)+12O2(g)\u2192H2O(l)\u0394Hf\u2218=\u2212285.8&nbsp;kJ\/mol\\text{H}_2(g) + \\frac{1}{2}\\text{O}_2(g) \\rightarrow \\text{H}_2\\text{O}(l) \\quad \\Delta H_f^\\circ = -285.8\\ \\text{kJ\/mol}<\/p>\n\n\n\n<p>This value is foundational for calculating the enthalpy changes of more complex reactions using Hess\u2019s Law.<\/p>\n\n\n\n<p>In summary, while both \u0394H\u00b0 and \u0394Hf\u00b0 deal with energy changes, <strong>\u0394H\u00b0 refers to the overall reaction<\/strong>, and <strong>\u0394Hf\u00b0 focuses on forming compounds from elements<\/strong>. Understanding the difference is crucial in thermochemistry.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-200.jpeg\" alt=\"\" class=\"wp-image-226148\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Match each thermodynamic symbol with its correct definition. Drag statements on the right to match the left AH&#8221; The enthalpy change of rcaction measured at thc standard state The enthalpy change when mole of compound forms from Its elements In thelr standard states AH The Correct Answer and Explanation is: Here\u2019s how to correctly match [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226147","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226147","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226147"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226147\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226147"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226147"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226147"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}