{"id":226184,"date":"2025-06-04T22:17:50","date_gmt":"2025-06-04T22:17:50","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226184"},"modified":"2025-06-04T22:17:52","modified_gmt":"2025-06-04T22:17:52","slug":"draw-the-lewis-structure-for-the-bromate-ion-bro3-with-minimized-formal-charges","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/04\/draw-the-lewis-structure-for-the-bromate-ion-bro3-with-minimized-formal-charges\/","title":{"rendered":"Draw the Lewis structure for the bromate ion (BrO3-) with minimized formal charges"},"content":{"rendered":"\n

Draw the Lewis structure for the bromate ion (BrO3-) with minimized formal charges. How many TOTAL likely resonance structures exist for BrO3-? A) 1 B) 2 C) 3 D) 4 E) 5<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct answer is: C) 3<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

The bromate ion (BrO\u2083\u207b)<\/strong> consists of a central bromine atom bonded to three oxygen atoms and carries an overall negative charge. To understand the number of likely resonance structures<\/strong>, we first consider its Lewis structure<\/strong> with minimized formal charges<\/strong>.<\/p>\n\n\n\n

Step-by-step Lewis Structure:<\/h4>\n\n\n\n
    \n
  1. Count valence electrons<\/strong>:\n
      \n
    • Br (Group 17): 7 valence electrons<\/li>\n\n\n\n
    • O (Group 16): 6 valence electrons \u00d7 3 = 18<\/li>\n\n\n\n
    • Extra electron (due to \u22121 charge): 1<\/li>\n\n\n\n
    • Total = 7 + 18 + 1 = 26 valence electrons<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n
    • Skeleton structure<\/strong>: Place Br in the center bonded to 3 oxygen atoms.<\/li>\n\n\n\n
    • Assign bonds and lone pairs<\/strong>:\n
        \n
      • Form single bonds from Br to each O \u2192 uses 6 electrons.<\/li>\n\n\n\n
      • Distribute remaining 20 electrons to complete octets on O atoms.<\/li>\n\n\n\n
      • This would leave Br with only 6 bonding electrons, which is insufficient because Br can expand its octet<\/strong> (period 4 element).<\/li>\n<\/ul>\n<\/li>\n\n\n\n
      • Create double bonds<\/strong>:\n
          \n
        • To minimize formal charges, convert one of the Br\u2013O single bonds into a double bond. This makes one oxygen neutral (0 formal charge) and the others carry -1 formal charges. Br now has a formal charge of 0.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
        • Resulting resonance structures<\/strong>:\n
            \n
          • The double bond between Br and O can be placed in three<\/strong> different locations (with any one of the three O atoms).<\/li>\n\n\n\n
          • Each of these forms a distinct resonance structure<\/strong> because the location of the double bond shifts while the atoms and connectivity remain the same.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n

            Conclusion:<\/h4>\n\n\n\n

            There are three equivalent resonance structures<\/strong> for BrO\u2083\u207b with minimized formal charges, each with one double bond and two single bonds, shifting among the three oxygen atoms. Hence, the total number of likely resonance structures is 3<\/strong>.<\/p>\n\n\n\n

            Correct choice: C) 3<\/strong>.<\/p>\n\n\n\n

            \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

            Draw the Lewis structure for the bromate ion (BrO3-) with minimized formal charges. How many TOTAL likely resonance structures exist for BrO3-? A) 1 B) 2 C) 3 D) 4 E) 5 The Correct Answer and Explanation is: The correct answer is: C) 3 Explanation: The bromate ion (BrO\u2083\u207b) consists of a central bromine atom […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226184","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226184","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226184"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226184\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226184"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226184"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226184"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}