{"id":226506,"date":"2025-06-05T10:22:31","date_gmt":"2025-06-05T10:22:31","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226506"},"modified":"2025-06-05T10:22:33","modified_gmt":"2025-06-05T10:22:33","slug":"draw-the-lewis-structure-for-bromoethane-c2h5br","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/05\/draw-the-lewis-structure-for-bromoethane-c2h5br\/","title":{"rendered":"Draw the Lewis structure for bromoethane (C2H5Br)"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Draw the Lewis structure for bromoethane (C2H5Br): Be certain you include any lone pairs.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Structure for Bromoethane (C\u2082H\u2085Br)<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Here is the correct Lewis structure for <strong>bromoethane<\/strong>:<\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>      H   H   H\n      |   |   |\nH \u2013 C \u2013 C \u2013 Br\n      |   \n      H\n<\/code><\/pre>\n\n\n\n<p class=\"wp-block-paragraph\">In this structure:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each carbon (C) forms 4 bonds.<\/li>\n\n\n\n<li>Each hydrogen (H) forms 1 bond.<\/li>\n\n\n\n<li>Bromine (Br) forms 1 bond and has <strong>three lone pairs<\/strong> of electrons.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Now, let\u2019s break this down:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Bromoethane (C\u2082H\u2085Br) is an organic halide that consists of a two-carbon ethane chain with one hydrogen atom replaced by a bromine atom. To draw the Lewis structure, we follow standard rules for bonding and valence electrons.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 1: Count total valence electrons.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) has 4 valence electrons \u00d7 2 = 8<\/li>\n\n\n\n<li>Hydrogen (H) has 1 valence electron \u00d7 5 = 5<\/li>\n\n\n\n<li>Bromine (Br) has 7 valence electrons = 7<br><strong>Total = 8 + 5 + 7 = 20 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 2: Arrange atoms.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The two carbon atoms are connected in a straight chain (C\u2013C). One carbon (CH\u2083 group) is bonded to three hydrogens. The second carbon (CH\u2082 group) is bonded to two hydrogens and a bromine atom (Br).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 3: Draw single bonds.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Connect each carbon with a single bond.<\/li>\n\n\n\n<li>Attach hydrogens to fulfill each carbon&#8217;s 4 bonds.<\/li>\n\n\n\n<li>Attach Br to the CH\u2082 carbon.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">At this point, all atoms are connected, and the carbon atoms follow the octet rule (8 electrons around each). Hydrogen atoms only require 2 electrons (1 bond).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 4: Add lone pairs.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Bromine forms only one single bond but needs 8 electrons total. It already has 2 from the bond, so we add <strong>three lone pairs<\/strong> (6 electrons) to complete its octet.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Final structure:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each H has 1 bond.<\/li>\n\n\n\n<li>Each C has 4 bonds (satisfying the octet).<\/li>\n\n\n\n<li>Br has 1 bond and 3 lone pairs.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This structure is stable and reflects the correct electron configuration and bonding of all atoms in bromoethane.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-445.jpeg\" alt=\"\" class=\"wp-image-226507\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the Lewis structure for bromoethane (C2H5Br): Be certain you include any lone pairs. The Correct Answer and Explanation is: Lewis Structure for Bromoethane (C\u2082H\u2085Br) Here is the correct Lewis structure for bromoethane: In this structure: Now, let\u2019s break this down: Explanation Bromoethane (C\u2082H\u2085Br) is an organic halide that consists of a two-carbon ethane chain [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226506","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226506","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226506"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226506\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226506"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226506"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226506"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}