{"id":226625,"date":"2025-06-05T12:11:06","date_gmt":"2025-06-05T12:11:06","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226625"},"modified":"2025-06-05T12:11:08","modified_gmt":"2025-06-05T12:11:08","slug":"is-ccl4-polar-or-nonpolar","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/05\/is-ccl4-polar-or-nonpolar\/","title":{"rendered":"Is CCl4\u00a0polar or nonpolar"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">A. Is CCl4&nbsp;polar or nonpolar? F B. Is NOBr polar or nonpolar? C. Is NICI2&nbsp;polar or nonpolar?<\/pre>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the correct answers and explanations for the polarity of the given molecules:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>A. Is CCl\u2084 polar or nonpolar?<\/strong><\/h3>\n\n\n\n<p><strong>Answer: Nonpolar<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Carbon tetrachloride (CCl\u2084) consists of a central carbon atom bonded to four chlorine atoms. Each C\u2013Cl bond is <strong>polar<\/strong> because chlorine is more electronegative than carbon, creating a dipole moment pointing toward the chlorine atoms. However, the molecule has a <strong>tetrahedral geometry<\/strong>, which is <strong>symmetrical<\/strong>. This symmetry causes the individual dipole moments to <strong>cancel out<\/strong> because they are equal in magnitude and point in opposite directions. As a result, despite having polar bonds, the <strong>overall molecule is nonpolar<\/strong> due to the net dipole moment being zero.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>B. Is NOBr polar or nonpolar?<\/strong><\/h3>\n\n\n\n<p><strong>Answer: Polar<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Nitrosyl bromide (NOBr) has a linear or bent molecular geometry depending on how you interpret its electron arrangement, but the key point is that the atoms (nitrogen, oxygen, and bromine) have significantly <strong>different electronegativities<\/strong>. Oxygen is the most electronegative, followed by nitrogen, then bromine. This creates an <strong>uneven distribution of electron density<\/strong> across the molecule. The N=O bond is much more polar than the N\u2013Br bond, resulting in a <strong>net dipole moment<\/strong> pointing from bromine toward oxygen. Because the dipoles <strong>do not cancel<\/strong>, <strong>NOBr is a polar molecule<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>C. Is NICl\u2082 polar or nonpolar?<\/strong><\/h3>\n\n\n\n<p><strong>Answer: Polar<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>Niodium dichloride (NICl\u2082) consists of a nitrogen (N) atom bonded to one iodine (I) and two chlorine (Cl) atoms. The molecule has a <strong>trigonal planar or bent geometry<\/strong> (depending on the bonding and lone pairs on nitrogen), but the critical aspect is that chlorine and iodine have <strong>different electronegativities<\/strong>. Chlorine is more electronegative than iodine, creating <strong>unequal dipole moments<\/strong> in the N\u2013Cl and N\u2013I bonds. The <strong>asymmetry<\/strong> of the molecular shape and the <strong>difference in electronegativity<\/strong> among the atoms causes the dipole moments not to cancel out. Therefore, <strong>NICl\u2082 is a polar molecule<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Summary:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>CCl\u2084 \u2013 Nonpolar<\/strong> (symmetrical tetrahedral, dipoles cancel)<\/li>\n\n\n\n<li><strong>NOBr \u2013 Polar<\/strong> (uneven electronegativity, dipoles don\u2019t cancel)<\/li>\n\n\n\n<li><strong>NICl\u2082 \u2013 Polar<\/strong> (asymmetrical, mixed electronegativities, net dipole)<img decoding=\"async\" src=\"file:\/\/\/C:\/Users\/Administrator\/Pictures\/learnexams%20banner5.jpeg\"><\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-105.jpeg\" alt=\"\" class=\"wp-image-226626\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>A. Is CCl4&nbsp;polar or nonpolar? F B. Is NOBr polar or nonpolar? C. Is NICI2&nbsp;polar or nonpolar? The Correct Answer and Explanation is: Here are the correct answers and explanations for the polarity of the given molecules: A. Is CCl\u2084 polar or nonpolar? Answer: Nonpolar Explanation:Carbon tetrachloride (CCl\u2084) consists of a central carbon atom bonded [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226625","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226625","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226625"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226625\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226625"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226625"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226625"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}