{"id":226708,"date":"2025-06-05T13:05:38","date_gmt":"2025-06-05T13:05:38","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226708"},"modified":"2025-06-05T13:05:40","modified_gmt":"2025-06-05T13:05:40","slug":"silver-nitrate-agno3-forms-a-yellow-precipitate-when-added-to-sodium-phosphate-na3po4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/05\/silver-nitrate-agno3-forms-a-yellow-precipitate-when-added-to-sodium-phosphate-na3po4\/","title":{"rendered":"Silver Nitrate (AgNO3) forms a yellow precipitate when added to Sodium Phosphate (Na3PO4)."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Silver Nitrate (AgNO3) forms a yellow precipitate when added to Sodium Phosphate (Na3PO4). Which is the correct Net Ionic Equation for the reaction? 3Ag+ + PO43- \u00e2\u2020\u2019 Ag3PO4(s) Ag+ + PO43- \u00e2\u2020\u2019 Ag2PO4(s) + NO3- AgNO3 + Na3PO4 \u00e2\u2020\u2019 Ag3PO4(s)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-160.png\" alt=\"\" class=\"wp-image-226709\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answer: \u2705 3Ag\u207a + PO\u2084\u00b3\u207b \u2192 Ag\u2083PO\u2084(s)<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">When two aqueous ionic compounds are mixed and a solid forms, this is known as a <strong>precipitation reaction<\/strong>. The question involves <strong>Silver Nitrate (AgNO\u2083)<\/strong> and <strong>Sodium Phosphate (Na\u2083PO\u2084)<\/strong>, both of which are soluble in water and dissociate into their respective ions:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>AgNO\u2083 \u2192 Ag\u207a + NO\u2083\u207b<\/li>\n\n\n\n<li>Na\u2083PO\u2084 \u2192 3Na\u207a + PO\u2084\u00b3\u207b<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">When <strong>Ag\u207a<\/strong> (silver ion) and <strong>PO\u2084\u00b3\u207b<\/strong> (phosphate ion) come together in solution, they form an <strong>insoluble salt<\/strong>, <strong>silver phosphate (Ag\u2083PO\u2084)<\/strong>, which precipitates out as a <strong>yellow solid<\/strong>. The net ionic equation includes <strong>only the ions that participate in forming the precipitate<\/strong>, excluding spectator ions like Na\u207a and NO\u2083\u207b, which do not change during the reaction.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The correct <strong>net ionic equation<\/strong> shows the combination of <strong>3 Ag\u207a ions<\/strong> and <strong>1 PO\u2084\u00b3\u207b ion<\/strong> to form <strong>solid Ag\u2083PO\u2084<\/strong>:<\/p>\n\n\n\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\">\n<p class=\"wp-block-paragraph\"><strong>3Ag\u207a + PO\u2084\u00b3\u207b \u2192 Ag\u2083PO\u2084(s)<\/strong><\/p>\n<\/blockquote>\n\n\n\n<p class=\"wp-block-paragraph\">Let\u2019s analyze the incorrect options:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u274c <strong>Ag\u207a + PO\u2084\u00b3\u207b \u2192 Ag\u2083PO\u2084(s):<\/strong> Incorrect stoichiometry; 3 Ag\u207a ions are needed to balance the -3 charge of PO\u2084\u00b3\u207b.<\/li>\n\n\n\n<li>\u274c <strong>Ag\u207a + NO\u2083\u207b + Na\u207a + PO\u2084\u00b3\u207b \u2192 Ag\u2083PO\u2084(s):<\/strong> Includes all ions; not a net ionic equation.<\/li>\n\n\n\n<li>\u274c <strong>AgNO\u2083 + Na\u2083PO\u2084 \u2192 Ag\u2083PO\u2084(s):<\/strong> This is the <strong>molecular equation<\/strong>, not the <strong>net ionic<\/strong> one.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">The net ionic equation strips the reaction down to its <strong>essence<\/strong>, showing only the <strong>species that actually form the precipitate<\/strong>. This not only simplifies the chemistry but also emphasizes the key reaction: the formation of the insoluble <strong>Ag\u2083PO\u2084<\/strong> from free ions in solution.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-232.jpeg\" alt=\"\" class=\"wp-image-226710\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Silver Nitrate (AgNO3) forms a yellow precipitate when added to Sodium Phosphate (Na3PO4). Which is the correct Net Ionic Equation for the reaction? 3Ag+ + PO43- \u00e2\u2020\u2019 Ag3PO4(s) Ag+ + PO43- \u00e2\u2020\u2019 Ag2PO4(s) + NO3- AgNO3 + Na3PO4 \u00e2\u2020\u2019 Ag3PO4(s) The Correct Answer and Explanation is: Correct Answer: \u2705 3Ag\u207a + PO\u2084\u00b3\u207b \u2192 Ag\u2083PO\u2084(s) Explanation [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226708","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226708","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226708"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226708\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226708"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226708"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226708"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}