{"id":226713,"date":"2025-06-05T13:13:05","date_gmt":"2025-06-05T13:13:05","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226713"},"modified":"2025-06-05T13:13:07","modified_gmt":"2025-06-05T13:13:07","slug":"if-pqr-measures-75-what-is-the-measure-of-sqr","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/05\/if-pqr-measures-75-what-is-the-measure-of-sqr\/","title":{"rendered":"If PQR measures 75 what is the measure of SQR"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">If PQR measures 75 what is the measure of SR?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To solve for the measure of angle <strong>SQR<\/strong>, we need more information about the relationship between the angles <strong>PQR<\/strong> and <strong>SQR<\/strong>. However, since this type of question often appears in geometry involving adjacent or supplementary angles, let\u2019s assume a typical scenario:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Scenario Assumed<\/strong>:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Suppose <strong>points P, Q, R, and S<\/strong> are on a plane such that <strong>angle PQR = 75\u00b0<\/strong>, and <strong>S lies on the opposite side of line PQ<\/strong> forming a straight angle with <strong>angle SQR<\/strong>. That means angles <strong>PQR<\/strong> and <strong>SQR<\/strong> are <strong>adjacent angles<\/strong> that together form a straight line at point Q. This implies they are <strong>supplementary<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Supplementary Angles<\/strong>:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Two angles are supplementary if the sum of their measures is 180\u00b0. That is: \u2220PQR+\u2220SQR=180\u2218\\angle PQR + \\angle SQR = 180^\\circ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">We are given: \u2220PQR=75\u2218\\angle PQR = 75^\\circ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Substituting: 75\u2218+\u2220SQR=180\u221875^\\circ + \\angle SQR = 180^\\circ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Solving for <strong>\u2220SQR<\/strong>: \u2220SQR=180\u2218\u221275\u2218=105\u2218\\angle SQR = 180^\\circ &#8211; 75^\\circ = 105^\\circ<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer: \u2220SQR = 105\u00b0<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udd0d <strong>Explanation <\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Understanding how to calculate unknown angles using given information and relationships is a fundamental part of geometry. In this case, we are given the measure of angle <strong>PQR<\/strong>, which is 75 degrees, and asked to find the measure of <strong>angle SQR<\/strong>. Since the problem does not provide a diagram or explicit relationship between the angles, we assume a common geometric setup where points P, Q, R, and S lie on the same plane, and angles <strong>PQR<\/strong> and <strong>SQR<\/strong> are adjacent angles forming a straight line.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">When two angles lie on a straight line and share a common side and vertex (in this case, point Q), they are called a <strong>linear pair<\/strong>. The defining characteristic of a linear pair is that the angles are <strong>supplementary<\/strong>, meaning their measures add up to 180\u00b0. This property is due to the fact that a straight angle measures exactly 180 degrees.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Given that <strong>angle PQR is 75 degrees<\/strong>, and <strong>angle SQR<\/strong> forms the rest of the straight angle with PQR, the two together must sum to 180\u00b0. Thus, by subtracting the given 75\u00b0 from 180\u00b0, we find that <strong>angle SQR must measure 105 degrees<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This method of reasoning applies broadly in geometry and helps solve many problems involving linear pairs, supplementary angles, and adjacent angles. Understanding these relationships enables students to break down complex figures into simpler, solvable components using basic principles.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-233.jpeg\" alt=\"\" class=\"wp-image-226714\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>If PQR measures 75 what is the measure of SR? The Correct Answer and Explanation is: To solve for the measure of angle SQR, we need more information about the relationship between the angles PQR and SQR. However, since this type of question often appears in geometry involving adjacent or supplementary angles, let\u2019s assume a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226713","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226713","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226713"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226713\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226713"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226713"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226713"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}