{"id":226893,"date":"2025-06-05T16:40:43","date_gmt":"2025-06-05T16:40:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=226893"},"modified":"2025-06-05T16:40:45","modified_gmt":"2025-06-05T16:40:45","slug":"what-is-the-product-for-the-following-three-step-reaction-sequence","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/05\/what-is-the-product-for-the-following-three-step-reaction-sequence\/","title":{"rendered":"What is the product for the following three-step reaction sequence"},"content":{"rendered":"\n

What is the product for the following three-step reaction sequence? Br2 + CH3OH \u00e2\u2020\u2019 CH3ONa + heat \u00e2\u2020\u2019 BrCCl + IBr + O<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To determine the correct product from the three-step reaction sequence provided, we need to analyze each reaction step carefully:<\/p>\n\n\n\n

Given Reaction Sequence:<\/strong><\/h3>\n\n\n\n
    \n
  1. Br\u2082, h\u03bd<\/strong>
    This is a radical bromination<\/strong> reaction, specifically allylic or benzylic bromination due to light (h\u03bd). The molecule is 1-methyl naphthalene, and the benzylic position (the CH\u2083 group) is particularly reactive. A bromine radical substitutes a benzylic hydrogen, forming 1-(bromomethyl)naphthalene<\/strong>.<\/li>\n\n\n\n
  2. CH\u2083OH, CH\u2083ONa, heat<\/strong>
    This is a nucleophilic substitution<\/strong> reaction under basic conditions<\/strong>, favoring E2 elimination<\/strong> due to heat. The CH\u2083ONa acts as a strong base, abstracting a \u03b2-hydrogen to eliminate HBr and form a double bond<\/strong> between the benzylic position and the ring \u2014 resulting in an exocyclic alkene<\/strong> (i.e., a vinyl group attached to the ring).<\/li>\n\n\n\n
  3. Br\u2082, CCl\u2084<\/strong>
    This is a halogen addition<\/strong> across a double bond. The double bond formed in step 2 reacts with Br\u2082 to form a vicinal dibromide<\/strong> (anti-addition). This leads to the addition of two Br atoms across the double bond in a trans<\/strong> (anti) fashion.<\/li>\n<\/ol>\n\n\n\n
    \n\n\n\n

    Now, let\u2019s analyze the options:<\/strong><\/h3>\n\n\n\n

    We look for a final product that:<\/p>\n\n\n\n

      \n
    • Has two Br atoms<\/strong> on the exocyclic double bond carbons,<\/li>\n\n\n\n
    • Shows anti stereochemistry<\/strong> (i.e., Br atoms on opposite faces),<\/li>\n\n\n\n
    • Retains the original naphthalene ring structure.<\/li>\n<\/ul>\n\n\n\n

      Option V<\/strong> fits this perfectly:<\/p>\n\n\n\n

        \n
      • It has two Br atoms<\/strong> on the exocyclic carbon positions,<\/li>\n\n\n\n
      • It shows correct trans stereochemistry<\/strong>,<\/li>\n\n\n\n
      • The rest of the structure is unaltered.<\/li>\n<\/ul>\n\n\n\n
        \n\n\n\n

        Correct Answer:<\/strong><\/h3>\n\n\n\n

        E) V<\/strong><\/p>\n\n\n\n

        This sequence showcases typical benzylic bromination, E2 elimination to form an alkene, and anti-addition of Br\u2082 across the resulting double bond \u2014 a classic example of multi-step synthesis in organic chemistry.<\/p>\n\n\n\n

        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        What is the product for the following three-step reaction sequence? Br2 + CH3OH \u00e2\u2020\u2019 CH3ONa + heat \u00e2\u2020\u2019 BrCCl + IBr + O The Correct Answer and Explanation is: To determine the correct product from the three-step reaction sequence provided, we need to analyze each reaction step carefully: Given Reaction Sequence: Now, let\u2019s analyze the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-226893","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226893","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=226893"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/226893\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=226893"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=226893"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=226893"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}