{"id":227006,"date":"2025-06-05T18:51:25","date_gmt":"2025-06-05T18:51:25","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227006"},"modified":"2025-06-05T18:51:28","modified_gmt":"2025-06-05T18:51:28","slug":"alexis-has-a-rectangular-piece-of-red-paper-that-is-4-cm-wide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/05\/alexis-has-a-rectangular-piece-of-red-paper-that-is-4-cm-wide\/","title":{"rendered":"Alexis has a rectangular piece of red paper that is 4 cm wide."},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">Alexis has a rectangular piece of red paper that is 4 cm wide. Its length is twice its width. She glues a rectangular piece of blue paper on top of the red piece measuring 3 cm by 7 cm. How many sq cm of red paper will be visible on top<\/pre>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Find dimensions of the red paper<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">We are told:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The red paper is <strong>4 cm wide<\/strong><\/li>\n\n\n\n<li>Its <strong>length is twice the width<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So,<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Length<\/strong> = 2 \u00d7 4 = <strong>8 cm<\/strong><\/li>\n\n\n\n<li>Therefore, the area of the red paper is:<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Areared=length\u00d7width=8\u00d74=32&nbsp;cm2\\text{Area}_{\\text{red}} = \\text{length} \\times \\text{width} = 8 \\times 4 = 32 \\text{ cm}^2Areared\u200b=length\u00d7width=8\u00d74=32&nbsp;cm2<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Find area of the blue paper<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">We are told the blue paper measures:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>3 cm by 7 cm<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, Areablue=3\u00d77=21&nbsp;cm2\\text{Area}_{\\text{blue}} = 3 \\times 7 = 21 \\text{ cm}^2Areablue\u200b=3\u00d77=21&nbsp;cm2<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Calculate the visible red area<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Assuming the blue paper is fully on top of the red paper and does not hang over any edge, the blue paper hides <strong>21 cm\u00b2<\/strong> of the red surface.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, the <strong>visible<\/strong> red area is: Visible&nbsp;red&nbsp;area=Areared\u2212Areablue=32\u221221=11&nbsp;cm2\\text{Visible red area} = \\text{Area}_{\\text{red}} &#8211; \\text{Area}_{\\text{blue}} = 32 &#8211; 21 = \\boxed{11 \\text{ cm}^2}Visible&nbsp;red&nbsp;area=Areared\u200b\u2212Areablue\u200b=32\u221221=11&nbsp;cm2\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">This problem involves basic geometry and understanding of area. Alexis starts with a red rectangular piece of paper with a width of 4 cm. Since the length is described as being \u201ctwice its width,\u201d we multiply 4 cm by 2, giving us a length of 8 cm. This gives us a red rectangle of dimensions 4 cm by 8 cm.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To find the area of a rectangle, we use the formula: Area=Length\u00d7Width\\text{Area} = \\text{Length} \\times \\text{Width}Area=Length\u00d7Width<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">So the red paper&#8217;s area is: 8&nbsp;cm\u00d74&nbsp;cm=32&nbsp;cm28 \\text{ cm} \\times 4 \\text{ cm} = 32 \\text{ cm}^28&nbsp;cm\u00d74&nbsp;cm=32&nbsp;cm2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Next, we examine the blue paper, which is also a rectangle with dimensions 3 cm by 7 cm. Its area is: 3&nbsp;cm\u00d77&nbsp;cm=21&nbsp;cm23 \\text{ cm} \\times 7 \\text{ cm} = 21 \\text{ cm}^23&nbsp;cm\u00d77&nbsp;cm=21&nbsp;cm2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now, since the blue paper is glued <strong>on top<\/strong> of the red one, it will cover part of it. Assuming the blue paper is fully contained within the red (which it is, because 3 cm &lt; 4 cm and 7 cm &lt; 8 cm), it covers <strong>exactly<\/strong> 21 cm\u00b2 of the red paper.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To find how much red paper is still visible, we subtract the blue area from the red: 32\u221221=11&nbsp;cm232 &#8211; 21 = 11 \\text{ cm}^232\u221221=11&nbsp;cm2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">So, the amount of visible red paper left is <strong>11 square centimeters<\/strong>. This is the final, correct answer.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer: <strong>11 cm\u00b2<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner6-71.jpeg\" alt=\"\" class=\"wp-image-227060\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Alexis has a rectangular piece of red paper that is 4 cm wide. Its length is twice its width. She glues a rectangular piece of blue paper on top of the red piece measuring 3 cm by 7 cm. How many sq cm of red paper will be visible on top The Correct Answer and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227006","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227006","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227006"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227006\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227006"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227006"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227006"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}