{"id":227229,"date":"2025-06-06T03:33:43","date_gmt":"2025-06-06T03:33:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227229"},"modified":"2025-06-06T03:33:45","modified_gmt":"2025-06-06T03:33:45","slug":"in-the-molecule-bri-which-atom-is-the-negative-pole","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/06\/in-the-molecule-bri-which-atom-is-the-negative-pole\/","title":{"rendered":"In the molecule BrI, which atom is the negative pole"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">In the molecule BrI, which atom is the negative pole? In the molecule BrI, which atom is the negative pole? I Br<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">A molecule like <strong>BrI<\/strong> is made up of two different halogen atoms: <strong>bromine (Br)<\/strong> and <strong>iodine (I)<\/strong>. These atoms are covalently bonded, meaning they share electrons. However, the electrons are not always shared equally between two atoms. The distribution of electrons depends on a property known as <strong>electronegativity<\/strong>, which is the tendency of an atom to attract shared electrons in a chemical bond.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the <strong>negative pole<\/strong> in a diatomic molecule like BrI, we compare the electronegativities of bromine and iodine:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Electronegativity of Br (bromine)<\/strong>: approximately <strong>2.96<\/strong><\/li>\n\n\n\n<li><strong>Electronegativity of I (iodine)<\/strong>: approximately <strong>2.66<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Since bromine has a <strong>higher electronegativity<\/strong> than iodine, it attracts the shared electrons <strong>more strongly<\/strong>. This makes the <strong>electron cloud shift slightly towards bromine<\/strong>, giving it a <strong>partial negative charge (\u03b4\u2013)<\/strong>. In contrast, iodine becomes slightly <strong>electron-deficient<\/strong>, giving it a <strong>partial positive charge (\u03b4+)<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">However, in terms of <strong>dipole notation<\/strong> and <strong>which atom is the negative pole<\/strong>, the atom with the <strong>higher electron density<\/strong> is considered the <strong>negative pole<\/strong>. So in <strong>BrI<\/strong>, <strong>bromine (Br)<\/strong> is the <strong>negative pole<\/strong>, <strong>not iodine<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Corrected Answer:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">In the molecule <strong>BrI<\/strong>, the <strong>bromine (Br)<\/strong> atom is the <strong>negative pole<\/strong>, because it is <strong>more electronegative<\/strong> than iodine and thus attracts the bonding electrons more strongly.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Br: Electronegativity = 2.96<\/li>\n\n\n\n<li>I: Electronegativity = 2.66<\/li>\n\n\n\n<li>Electrons are drawn more toward <strong>Br<\/strong><\/li>\n\n\n\n<li>Br becomes <strong>\u03b4\u2013<\/strong> (negative pole)<\/li>\n\n\n\n<li>I becomes <strong>\u03b4+<\/strong> (positive pole)<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Final Answer: Bromine (Br) is the negative pole in BrI.<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner6-75.jpeg\" alt=\"\" class=\"wp-image-227230\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>In the molecule BrI, which atom is the negative pole? In the molecule BrI, which atom is the negative pole? I Br The Correct Answer and Explanation is: Explanation A molecule like BrI is made up of two different halogen atoms: bromine (Br) and iodine (I). These atoms are covalently bonded, meaning they share electrons. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227229","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227229","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227229"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227229\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227229"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227229"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227229"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}