{"id":227378,"date":"2025-06-06T05:39:15","date_gmt":"2025-06-06T05:39:15","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227378"},"modified":"2025-06-06T05:39:17","modified_gmt":"2025-06-06T05:39:17","slug":"make-a-sketch-of-an-acetic-acid-molecule-ch3cooh","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/06\/make-a-sketch-of-an-acetic-acid-molecule-ch3cooh\/","title":{"rendered":"Make a sketch of an acetic acid molecule CH3COOH."},"content":{"rendered":"\n<p>Make a sketch of an acetic acid molecule CH3COOH. Draw the molecule by placing atoms on the grid and connecting them with bonds.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here&#8217;s a <strong>sketch of the acetic acid (CH\u2083COOH)<\/strong> molecule, showing atoms placed on a grid and bonds between them:<\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>     H\n     |\nH \u2013 C \u2013 C = O\n     |   \\\n     H    O \u2013 H\n<\/code><\/pre>\n\n\n\n<p><strong>Explanation (Approx. 300 words):<\/strong><\/p>\n\n\n\n<p>Acetic acid (CH\u2083COOH) is a <strong>simple carboxylic acid<\/strong> and the main component of vinegar. Its chemical formula consists of <strong>two carbon atoms, four hydrogen atoms, and two oxygen atoms<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Molecular Structure:<\/h3>\n\n\n\n<p>The structure can be divided into two parts:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Methyl Group (CH\u2083\u2013):<\/strong><br>This consists of a <strong>carbon atom<\/strong> bonded to <strong>three hydrogen atoms<\/strong> via single covalent bonds. The central carbon in this group is <strong>sp\u00b3 hybridized<\/strong>, forming a <strong>tetrahedral geometry<\/strong> with bond angles close to 109.5\u00b0.<\/li>\n\n\n\n<li><strong>Carboxylic Group (\u2013COOH):<\/strong><br>Attached to the methyl group is a <strong>carboxylic acid functional group<\/strong> (COOH), which is characteristic of organic acids. This group includes:\n<ul class=\"wp-block-list\">\n<li>A <strong>carbon atom double bonded to an oxygen atom<\/strong> (C=O), known as a <strong>carbonyl group<\/strong>.<\/li>\n\n\n\n<li>The same carbon is also <strong>single bonded to a hydroxyl group (\u2013OH)<\/strong>.<br>The carbon in the carboxylic group is <strong>sp\u00b2 hybridized<\/strong>, resulting in a <strong>trigonal planar<\/strong> geometry with bond angles close to 120\u00b0.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Bonding and Geometry:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>C\u2013C bond<\/strong> connects the methyl group and the carboxylic acid group.<\/li>\n\n\n\n<li>The <strong>carbonyl bond (C=O)<\/strong> is a <strong>strong double bond<\/strong> and imparts partial polarity to the molecule.<\/li>\n\n\n\n<li>The <strong>hydroxyl hydrogen (in \u2013OH)<\/strong> can be donated in acid-base reactions, making acetic acid a <strong>weak acid<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Polarity and Function:<\/h3>\n\n\n\n<p>Due to the presence of the polar C=O and O\u2013H groups, acetic acid is <strong>highly polar and capable of hydrogen bonding<\/strong>, which influences its <strong>solubility in water<\/strong> and <strong>boiling point<\/strong>.<\/p>\n\n\n\n<p>In conclusion, acetic acid is an essential organic compound whose molecular structure influences both its <strong>chemical reactivity<\/strong> and <strong>physical properties<\/strong>. The correct sketch and understanding of its geometry are crucial for grasping concepts in organic chemistry.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-73.jpeg\" alt=\"\" class=\"wp-image-227379\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Make a sketch of an acetic acid molecule CH3COOH. Draw the molecule by placing atoms on the grid and connecting them with bonds. The Correct Answer and Explanation is: Here&#8217;s a sketch of the acetic acid (CH\u2083COOH) molecule, showing atoms placed on a grid and bonds between them: mathematicaCopyEdit H | H \u2013 C \u2013 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227378","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227378","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227378"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227378\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227378"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227378"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227378"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}