{"id":227603,"date":"2025-06-06T09:05:02","date_gmt":"2025-06-06T09:05:02","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227603"},"modified":"2025-06-06T09:05:05","modified_gmt":"2025-06-06T09:05:05","slug":"what-is-the-mass-in-grams-of-1-2-moles-of-k","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/06\/what-is-the-mass-in-grams-of-1-2-moles-of-k\/","title":{"rendered":"What is the mass in grams of 1.2 moles of K"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">What is the mass in grams of 1.2 moles of K?<br>What is the mass in grams of 1.2 moles of K?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-0-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To find the <strong>mass in grams of 1.2 moles of potassium (K)<\/strong>, use the formula: Mass=Moles\u00d7Molar&nbsp;Mass\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass}Mass=Moles\u00d7Molar&nbsp;Mass<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The <strong>molar mass of potassium (K)<\/strong> is approximately <strong>39.10 g\/mol<\/strong>. Mass=1.2\u2009mol\u00d739.10\u2009g\/mol=46.92\u2009grams\\text{Mass} = 1.2 \\, \\text{mol} \\times 39.10 \\, \\text{g\/mol} = \\boxed{46.92 \\, \\text{grams}}Mass=1.2mol\u00d739.10g\/mol=46.92grams\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Detailed Explanation <\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">In chemistry, calculating the mass of a substance given its amount in moles is a basic yet essential skill. This process relies on the concept of <strong>molar mass<\/strong>, which is the mass of one mole of a given substance. Molar mass is expressed in units of grams per mole (g\/mol), and its value corresponds to the atomic or molecular weight listed on the periodic table.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In this case, the element in question is <strong>potassium (symbol K)<\/strong>, a soft, silvery metal that belongs to Group 1 of the periodic table, also known as the alkali metals. Potassium has an atomic number of 19 and an atomic mass of approximately <strong>39.10 g\/mol<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The question asks for the mass of <strong>1.2 moles<\/strong> of potassium. A mole is a quantity that represents 6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023 atoms or molecules\u2014Avogadro\u2019s number. While this number is quite large, the mole allows chemists to work with atoms and molecules on a scale that is measurable in the lab.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To find the total mass of 1.2 moles of potassium, we multiply the number of moles by potassium\u2019s molar mass: 1.2\u2009mol\u00d739.10\u2009g\/mol=46.92\u2009g1.2 \\, \\text{mol} \\times 39.10 \\, \\text{g\/mol} = 46.92 \\, \\text{g}1.2mol\u00d739.10g\/mol=46.92g<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, 1.2 moles of potassium weigh <strong>46.92 grams<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This calculation is crucial in stoichiometry, which involves measuring the reactants and products in chemical reactions. Knowing how to convert between moles and grams enables chemists to predict how much of a substance is needed or produced, ensuring accuracy in laboratory and industrial processes.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-111.jpeg\" alt=\"\" class=\"wp-image-227604\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the mass in grams of 1.2 moles of K?What is the mass in grams of 1.2 moles of K? The Correct Answer and Explanation is: To find the mass in grams of 1.2 moles of potassium (K), use the formula: Mass=Moles\u00d7Molar&nbsp;Mass\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass}Mass=Moles\u00d7Molar&nbsp;Mass The molar mass of potassium (K) is [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227603","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227603","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227603"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227603\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227603"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227603"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227603"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}