{"id":227656,"date":"2025-06-06T10:42:45","date_gmt":"2025-06-06T10:42:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227656"},"modified":"2025-06-06T10:42:47","modified_gmt":"2025-06-06T10:42:47","slug":"give-the-abbreviated-electron-configuration-for-silver-47ag-and-underline-the-valence-electrons","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/06\/give-the-abbreviated-electron-configuration-for-silver-47ag-and-underline-the-valence-electrons\/","title":{"rendered":"Give the abbreviated electron configuration for silver, 47Ag, and underline the valence electrons."},"content":{"rendered":"\n<p>Give the abbreviated electron configuration for silver, 47Ag, and underline the valence electrons.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Abbreviated Electron Configuration for Silver (47Ag):<\/strong><br>[Kr]\u20094d10\u20095s1\u203e\\text{[Kr]} \\, 4d^{10} \\, \\underline{5s^1}[Kr]4d105s1\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation <\/strong><\/h3>\n\n\n\n<p>Silver (Ag), with atomic number 47, is a transition metal located in group 11 of the periodic table. To understand its electron configuration, we begin by noting that electron configurations describe the distribution of electrons in an atom\u2019s orbitals, following the <strong>Aufbau principle<\/strong> (electrons fill lower-energy orbitals first), <strong>Pauli exclusion principle<\/strong> (no two electrons in the same atom can have the same set of quantum numbers), and <strong>Hund\u2019s rule<\/strong> (electrons fill orbitals singly before pairing).<\/p>\n\n\n\n<p>The <strong>full electron configuration<\/strong> of silver is:<br>1s2\u20092s2\u20092p6\u20093s2\u20093p6\u20094s2\u20093d10\u20094p6\u20095s1\u20094d101s^2\\, 2s^2\\, 2p^6\\, 3s^2\\, 3p^6\\, 4s^2\\, 3d^{10}\\, 4p^6\\, 5s^1\\, 4d^{10}1s22s22p63s23p64s23d104p65s14d10<br>To simplify, we use the noble gas shorthand. The nearest noble gas before silver is <strong>krypton (Kr)<\/strong>, atomic number 36:<br>[Kr]=1s2\u20092s2\u20092p6\u20093s2\u20093p6\u20094s2\u20093d10\u20094p6\\text{[Kr]} = 1s^2\\, 2s^2\\, 2p^6\\, 3s^2\\, 3p^6\\, 4s^2\\, 3d^{10}\\, 4p^6[Kr]=1s22s22p63s23p64s23d104p6<\/p>\n\n\n\n<p>So, the <strong>abbreviated configuration<\/strong> is:<br>[Kr]\u20094d10\u20095s1\\text{[Kr]} \\, 4d^{10} \\, 5s^1[Kr]4d105s1<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Valence Electrons:<\/strong><\/h3>\n\n\n\n<p>For silver, the <strong>valence electrons<\/strong> are the outermost electrons involved in chemical bonding. These lie in the <strong>5s<\/strong> and partially in the <strong>4d<\/strong> orbitals. However, the <strong>5s^1<\/strong> electron is considered the most reactive and is the primary valence electron. The 4d electrons are more stable and less reactive due to being part of a filled subshell.<\/p>\n\n\n\n<p>Thus, the <strong>valence electron(s)<\/strong> in silver is <strong>underlined<\/strong> in the configuration:<br>[Kr]\u20094d10\u20095s1\u203e\\text{[Kr]} \\, 4d^{10} \\, \\underline{5s^1}[Kr]4d105s1\u200b<\/p>\n\n\n\n<p>This configuration is unusual because we might expect <strong>5s^2 4d^9<\/strong>, but due to extra stability from a filled 4d subshell, one electron from the 5s orbital is promoted to 4d, resulting in <strong>4d^{10} 5s^1<\/strong>. This is a common exception in transition metals to gain lower energy and greater stability.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-120.jpeg\" alt=\"\" class=\"wp-image-227658\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Give the abbreviated electron configuration for silver, 47Ag, and underline the valence electrons. The Correct Answer and Explanation is: Abbreviated Electron Configuration for Silver (47Ag):[Kr]\u20094d10\u20095s1\u203e\\text{[Kr]} \\, 4d^{10} \\, \\underline{5s^1}[Kr]4d105s1\u200b Explanation Silver (Ag), with atomic number 47, is a transition metal located in group 11 of the periodic table. To understand its electron configuration, we begin [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227656","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227656","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227656"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227656\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227656"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227656"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227656"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}