{"id":227817,"date":"2025-06-06T14:08:26","date_gmt":"2025-06-06T14:08:26","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227817"},"modified":"2025-06-06T14:08:28","modified_gmt":"2025-06-06T14:08:28","slug":"mmetric-centers-are-present-in-the-compound-shown-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/06\/mmetric-centers-are-present-in-the-compound-shown-below\/","title":{"rendered":"mmetric centers are present in the compound shown below"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">mmetric centers are present in the compound shown below?<br>15) Draw the enantiomer of the compound below CH 16) How many asymmetric centers are present in the compound shown below?<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-210.png\" alt=\"\" class=\"wp-image-227819\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 15: Draw the enantiomer of the compound below<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The compound in question is a chiral molecule with two stereocenters\u2014one carbon bonded to a hydroxyl group (OH), a methyl group (CH\u2083), a hydrogen, and a carbon chain, and another carbon bonded to a bromine (Br), a hydrogen, a carbon chain, and a methyl group. The original configuration shows both substituents coming <strong>out of the plane<\/strong> (wedged bonds) for the OH and Br groups.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To draw the <strong>enantiomer<\/strong>, invert the stereochemistry at <strong>both chiral centers<\/strong>. This means that groups that were on wedges (coming out of the plane) should now be shown on <strong>dashes<\/strong> (going behind the plane), and vice versa. So in the enantiomer:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The OH group should now be on a dashed bond.<\/li>\n\n\n\n<li>The Br group should also now be on a dashed bond.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This results in a <strong>non-superimposable mirror image<\/strong> of the original compound, defining an enantiomer. Enantiomers have identical physical properties (boiling point, melting point, etc.) in an achiral environment, but they differ in the direction in which they rotate plane-polarized light and in interactions with other chiral substances (such as enzymes or receptors in biological systems).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Question 16: How many asymmetric centers are present in the compound shown below?<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The second compound is a <strong>decalin derivative<\/strong> (a fused bicyclic system). Asymmetric centers (also known as chiral centers) are <strong>sp\u00b3-hybridized carbon atoms<\/strong> that are attached to <strong>four different groups<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In the given structure, we observe that:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The compound has two hydrogens explicitly shown on two different carbons using wedge and dash notation, indicating they are <strong>stereocenters<\/strong>.<\/li>\n\n\n\n<li>There are <strong>four carbon atoms<\/strong> in the fused ring system that each bond to four different groups due to ring fusion and substituent arrangement, making them chiral centers.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Answer<\/strong>: The compound has <strong>4 asymmetric centers<\/strong>.<\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Q15 Answer<\/strong>: Enantiomer is the mirror image with both chiral centers\u2019 configurations inverted (OH and Br flipped from wedge to dash).<\/li>\n\n\n\n<li><strong>Q16 Answer<\/strong>: There are <strong>4 asymmetric centers<\/strong> in the compound.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This understanding is vital in stereochemistry, which influences the behavior of molecules in biological systems and drug design.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This understanding is vital in stereochemistry, which influences the behavior of molecules in biological systems and drug design.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-147.jpeg\" alt=\"\" class=\"wp-image-227818\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>mmetric centers are present in the compound shown below?15) Draw the enantiomer of the compound below CH 16) How many asymmetric centers are present in the compound shown below? The Correct Answer and Explanation is: Question 15: Draw the enantiomer of the compound below The compound in question is a chiral molecule with two stereocenters\u2014one [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227817","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227817","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227817"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227817\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227817"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227817"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227817"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}