{"id":227952,"date":"2025-06-06T16:11:16","date_gmt":"2025-06-06T16:11:16","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=227952"},"modified":"2025-06-06T16:11:19","modified_gmt":"2025-06-06T16:11:19","slug":"butanol-is-likely-to-have-the-higher-normal-melting-point","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/06\/butanol-is-likely-to-have-the-higher-normal-melting-point\/","title":{"rendered":"(Butanol) is likely to have the higher normal melting point."},"content":{"rendered":"\n<p>(Butanol) is likely to have the higher normal melting point.<br>Suggest, giving reasons and using Lewis structures, whether C2H5OC2H5 (diethyl ether) or C4H9OH (butanol) is likely to have the higher normal melting point.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: Butanol (C\u2084H\u2089OH) is likely to have the higher normal melting point than diethyl ether (C\u2082H\u2085OC\u2082H\u2085).<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To determine which compound has a higher normal melting point\u2014<strong>butanol<\/strong> or <strong>diethyl ether<\/strong>\u2014we must consider the types of <strong>intermolecular forces<\/strong> present in each compound, as these directly affect melting and boiling points.<\/p>\n\n\n\n<p><strong>1. Lewis Structures:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Butanol (C\u2084H\u2089OH)<\/strong><br>Lewis structure: CH\u2083\u2013CH\u2082\u2013CH\u2082\u2013CH\u2082\u2013OH<br>It contains a hydroxyl (-OH) group, which is capable of <strong>hydrogen bonding<\/strong>.<\/li>\n\n\n\n<li><strong>Diethyl ether (C\u2082H\u2085OC\u2082H\u2085)<\/strong><br>Lewis structure: CH\u2083\u2013CH\u2082\u2013O\u2013CH\u2082\u2013CH\u2083<br>It has an ether group (R\u2013O\u2013R&#8217;), with oxygen contributing lone pairs, but <strong>cannot donate hydrogen bonds<\/strong>, only <strong>accept<\/strong> them.<\/li>\n<\/ul>\n\n\n\n<p><strong>2. Intermolecular Forces:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Butanol<\/strong> exhibits:\n<ul class=\"wp-block-list\">\n<li><strong>Hydrogen bonding<\/strong> (due to the \u2013OH group),<\/li>\n\n\n\n<li><strong>Dipole-dipole interactions<\/strong>,<\/li>\n\n\n\n<li><strong>London dispersion forces<\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Diethyl ether<\/strong> exhibits:\n<ul class=\"wp-block-list\">\n<li><strong>Dipole-dipole interactions<\/strong> (due to the oxygen atom),<\/li>\n\n\n\n<li><strong>London dispersion forces<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Hydrogen bonding is significantly stronger than dipole-dipole and dispersion forces. This allows molecules of butanol to pack more tightly and require more energy (higher temperature) to break apart from the solid structure.<\/p>\n\n\n\n<p><strong>3. Molecular Size and Shape:<\/strong><\/p>\n\n\n\n<p>Both compounds have similar molar masses (butanol \u2248 74 g\/mol, diethyl ether \u2248 74 g\/mol), but butanol has a more linear structure, aiding crystalline packing. Diethyl ether, being more branched and lacking hydrogen bonding, has weaker intermolecular cohesion.<\/p>\n\n\n\n<p><strong>4. Empirical Data Support:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Melting point of butanol:<\/strong> ~<strong>\u201389\u00b0C<\/strong><\/li>\n\n\n\n<li><strong>Melting point of diethyl ether:<\/strong> ~<strong>\u2013116\u00b0C<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Though both are low-melting substances due to weak intermolecular forces overall, <strong>butanol\u2019s hydrogen bonding<\/strong> results in a noticeably <strong>higher melting point<\/strong>.<\/p>\n\n\n\n<p><strong>Conclusion:<\/strong><br>Butanol has the higher normal melting point due to its ability to form hydrogen bonds, which significantly strengthens its intermolecular attractions compared to diethyl ether.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-552.jpeg\" alt=\"\" class=\"wp-image-227953\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>(Butanol) is likely to have the higher normal melting point.Suggest, giving reasons and using Lewis structures, whether C2H5OC2H5 (diethyl ether) or C4H9OH (butanol) is likely to have the higher normal melting point. The Correct Answer and Explanation is: Correct Answer: Butanol (C\u2084H\u2089OH) is likely to have the higher normal melting point than diethyl ether (C\u2082H\u2085OC\u2082H\u2085). [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-227952","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227952","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=227952"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/227952\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=227952"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=227952"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=227952"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}