{"id":228189,"date":"2025-06-07T06:28:53","date_gmt":"2025-06-07T06:28:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=228189"},"modified":"2025-06-07T06:28:55","modified_gmt":"2025-06-07T06:28:55","slug":"b-solubility-temperature-and-crystallization-solubilities-as-a-function-of-temperature-71-9-81-31-n-100-temperature-molarities-m-nano2-45-m-kcl-45-m-nacl","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/07\/b-solubility-temperature-and-crystallization-solubilities-as-a-function-of-temperature-71-9-81-31-n-100-temperature-molarities-m-nano2-45-m-kcl-45-m-nacl\/","title":{"rendered":"B. Solubility, Temperature, and Crystallization Solubilities as a function of temperature 71 9.81 &#8216; . 31 n 100 Temperature, Molarities M NaNO2, 45 M KCl; 45 M NaCl;"},"content":{"rendered":"\n<p>B. Solubility, Temperature, and Crystallization Solubilities as a function of temperature 71 9.81 &#8216; . 31 n 100 Temperature, Molarities M NaNO2, 45 M KCl; 45 M NaCl;<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer:<\/h3>\n\n\n\n<p>As temperature increases, the solubility of most salts <strong>increases<\/strong>, but <strong>not uniformly<\/strong> for all compounds. Here&#8217;s how solubility behaves for the three given salts:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>NaNO\u2082 (Sodium nitrite)<\/strong>: <strong>Solubility increases significantly<\/strong> with temperature.<\/li>\n\n\n\n<li><strong>KCl (Potassium chloride)<\/strong>: <strong>Solubility increases moderately<\/strong> with temperature.<\/li>\n\n\n\n<li><strong>NaCl (Sodium chloride)<\/strong>: <strong>Solubility increases slightly<\/strong> with temperature.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>Solubility is defined as the maximum amount of a solute that can dissolve in a solvent (usually water) at a given temperature to form a saturated solution. Temperature plays a key role in solubility, especially for <strong>solid solutes in liquid solvents<\/strong>. As temperature increases, <strong>most solid salts become more soluble<\/strong> due to the endothermic nature of their dissolution processes\u2014more heat allows more solute particles to escape into the solution.<\/p>\n\n\n\n<p>Let\u2019s examine the three salts in question:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>NaNO\u2082 (Sodium nitrite)<\/strong>: This salt has a <strong>strong positive temperature-solubility correlation<\/strong>. It dissolves endothermically, meaning heat absorption helps break its ionic lattice and integrate ions into the solvent. Thus, increasing temperature significantly enhances NaNO\u2082\u2019s solubility.<\/li>\n\n\n\n<li><strong>KCl (Potassium chloride)<\/strong>: Its solubility also increases with temperature, but the effect is <strong>less dramatic<\/strong> than with NaNO\u2082. Potassium chloride\u2019s dissolution is slightly endothermic, so increased thermal energy helps, but not as significantly.<\/li>\n\n\n\n<li><strong>NaCl (Sodium chloride)<\/strong>: NaCl is an exception among many salts. Its solubility is <strong>nearly temperature-independent<\/strong>, showing only a <strong>slight increase<\/strong> with rising temperature. This is because the dissolution of NaCl is <strong>nearly thermoneutral<\/strong>\u2014it doesn\u2019t absorb or release much heat\u2014so temperature has minimal effect.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Crystallization:<\/h3>\n\n\n\n<p>When a hot saturated solution of one of these salts cools down, the <strong>excess solute precipitates<\/strong> out as crystals. This is used in recrystallization techniques for purification. Salts like NaNO\u2082 and KCl are excellent for such processes because they show a significant solubility difference across temperatures. NaCl, however, is less suitable because its solubility barely changes with temperature.<\/p>\n\n\n\n<p>Understanding these properties is essential in industrial applications, pharmaceuticals, and laboratory recrystallization techniques.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-130.jpeg\" alt=\"\" class=\"wp-image-228190\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>B. Solubility, Temperature, and Crystallization Solubilities as a function of temperature 71 9.81 &#8216; . 31 n 100 Temperature, Molarities M NaNO2, 45 M KCl; 45 M NaCl; The Correct Answer and Explanation is: Correct Answer: As temperature increases, the solubility of most salts increases, but not uniformly for all compounds. Here&#8217;s how solubility behaves [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-228189","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228189","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=228189"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228189\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=228189"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=228189"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=228189"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}