{"id":228274,"date":"2025-06-07T07:29:28","date_gmt":"2025-06-07T07:29:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=228274"},"modified":"2025-06-07T07:29:30","modified_gmt":"2025-06-07T07:29:30","slug":"what-is-the-lewis-structure-for-the-anion-ch2cn","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/07\/what-is-the-lewis-structure-for-the-anion-ch2cn\/","title":{"rendered":"what is the lewis structure for the anion -CH2CN"},"content":{"rendered":"\n<p>what is the lewis structure for the anion -CH2CN?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Lewis Structure for the Anion \u2013CH\u2082CN\u207b:<\/h3>\n\n\n\n<p>The molecular formula of the anion is <strong>CH\u2082CN\u207b<\/strong>, which contains:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>3 carbon atoms,<\/li>\n\n\n\n<li>2 hydrogen atoms,<\/li>\n\n\n\n<li>1 nitrogen atom,<\/li>\n\n\n\n<li>and a <strong>negative charge<\/strong> (total charge = \u20131).<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Lewis Structure<\/strong>:<\/h4>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>H   H\n \\ \/\n  C \u2014 C \u2261 N:\n     |\n    [:]\n<\/code><\/pre>\n\n\n\n<p>(One lone pair on the terminal nitrogen, negative charge delocalized.)<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation <\/h3>\n\n\n\n<p>The anion \u2013CH\u2082CN\u207b, also known as the <strong>cyanomethyl anion<\/strong>, consists of a methyl group (CH\u2082) bonded to a nitrile group (C\u2261N). The total number of valence electrons must be calculated to draw the correct Lewis structure.<\/p>\n\n\n\n<p><strong>Step 1: Count valence electrons.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 4 electrons \u00d7 3 = 12<\/li>\n\n\n\n<li>Hydrogen (H): 1 electron \u00d7 2 = 2<\/li>\n\n\n\n<li>Nitrogen (N): 5 electrons<\/li>\n\n\n\n<li>Additional electron due to negative charge: 1<br><strong>Total = 12 + 2 + 5 + 1 = 20 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>Step 2: Arrange atoms.<\/strong><br>The basic structure is:<\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>H\u2082C\u2014C\u2261N\n<\/code><\/pre>\n\n\n\n<p>Here:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The leftmost carbon is bonded to two hydrogen atoms and the middle carbon.<\/li>\n\n\n\n<li>The middle carbon forms a triple bond with the nitrogen atom.<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Satisfy the octet rule.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each hydrogen has 2 electrons (satisfied).<\/li>\n\n\n\n<li>The left carbon (CH\u2082) has four bonds: 2 to H, 1 to the middle carbon, and one lone pair (due to the negative charge).<\/li>\n\n\n\n<li>The central carbon forms a single bond with the left carbon and a triple bond with nitrogen (4 bonds total).<\/li>\n\n\n\n<li>The nitrogen forms a triple bond with carbon and holds one lone pair (to satisfy its octet).<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 4: Formal charges.<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The negative charge primarily resides on the CH\u2082 carbon, making it a <strong>carbanion<\/strong>.<\/li>\n\n\n\n<li>This is supported by resonance: the lone pair on CH\u2082 can delocalize into the \u03c0-system of the nitrile.<\/li>\n<\/ul>\n\n\n\n<p>The structure is stabilized by resonance and satisfies all atoms\u2019 octet requirements, making it the most accurate Lewis representation of \u2013CH\u2082CN\u207b.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner6-93.jpeg\" alt=\"\" class=\"wp-image-228275\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>what is the lewis structure for the anion -CH2CN? The Correct Answer and Explanation is: Lewis Structure for the Anion \u2013CH\u2082CN\u207b: The molecular formula of the anion is CH\u2082CN\u207b, which contains: Lewis Structure: mathematicaCopyEditH H \\ \/ C \u2014 C \u2261 N: | [:] (One lone pair on the terminal nitrogen, negative charge delocalized.) Explanation [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-228274","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228274","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=228274"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228274\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=228274"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=228274"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=228274"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}