{"id":228494,"date":"2025-06-07T10:17:29","date_gmt":"2025-06-07T10:17:29","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=228494"},"modified":"2025-06-07T10:17:31","modified_gmt":"2025-06-07T10:17:31","slug":"which-diagram-shows-the-equation","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/07\/which-diagram-shows-the-equation\/","title":{"rendered":"Which diagram shows the equation"},"content":{"rendered":"\n<p>Which diagram shows the equation<br>? ? View Available Hint(s)<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/image-239.png\" alt=\"\" class=\"wp-image-228495\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h6 class=\"wp-block-heading\">ChatGPT said:<\/h6>\n\n\n\n<p>The given equation is:v=2t+4v = 2t + 4v=2t+4<\/p>\n\n\n\n<p>This is a linear equation where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>vvv is the dependent variable (on the y-axis),<\/li>\n\n\n\n<li>ttt is the independent variable (on the x-axis),<\/li>\n\n\n\n<li>The slope (rate of change) is 2,<\/li>\n\n\n\n<li>The y-intercept is 4 (meaning when t=0t = 0t=0, v=4v = 4v=4).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-step Analysis:<\/h3>\n\n\n\n<p>Let\u2019s analyze each graph in the image:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Top graph:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The line starts at v=2v = 2v=2 when t=0t = 0t=0.<\/li>\n\n\n\n<li>This suggests a y-intercept of 2.<\/li>\n\n\n\n<li>Since our equation has a y-intercept of 4, this is <strong>not<\/strong> correct.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Middle graph:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The line starts at v=4v = 4v=4 when t=0t = 0t=0.<\/li>\n\n\n\n<li>Let&#8217;s test a point: When t=1t = 1t=1, v=6v = 6v=6, and when t=2t = 2t=2, v=8v = 8v=8. This shows a consistent increase of 2 units in vvv for every 1 unit in ttt.<\/li>\n\n\n\n<li>This confirms a slope of 2 and y-intercept of 4.<\/li>\n<\/ul>\n\n\n\n<p>\u2705 This matches the equation v=2t+4v = 2t + 4v=2t+4. <strong>Correct Answer: Middle graph<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Bottom graph:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The line starts at v=6v = 6v=6 when t=0t = 0t=0, so y-intercept is 6.<\/li>\n\n\n\n<li>That doesn&#8217;t match the y-intercept of 4.<\/li>\n\n\n\n<li>Also, the slope appears steeper than 2 (looks like slope = 3).<\/li>\n<\/ul>\n\n\n\n<p>This graph is incorrect for our equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To determine which graph correctly represents the equation v=2t+4v = 2t + 4v=2t+4, we analyze the graph\u2019s slope and y-intercept. A linear equation in the form y=mx+by = mx + by=mx+b has two key characteristics: the <strong>slope<\/strong> (rate of change) and the <strong>y-intercept<\/strong> (value when x=0x = 0x=0). For the equation v=2t+4v = 2t + 4v=2t+4, the slope is 2 and the y-intercept is 4. This means that when t=0t = 0t=0, vvv must equal 4. Additionally, for every increase of 1 in ttt, vvv must increase by 2.<\/p>\n\n\n\n<p>Reviewing the three graphs, the <strong>top graph<\/strong> has a line starting at v=2v = 2v=2, which does not match the y-intercept. The <strong>bottom graph<\/strong> starts at v=6v = 6v=6, again not matching the required y-intercept of 4. Only the <strong>middle graph<\/strong> correctly shows a line that begins at v=4v = 4v=4 and increases by 2 for every 1 unit increase in ttt. This accurately reflects the slope and intercept in the equation.<\/p>\n\n\n\n<p>Hence, the <strong>middle graph<\/strong> is the correct visual representation of the equation v=2t+4v = 2t + 4v=2t+4.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-291.jpeg\" alt=\"\" class=\"wp-image-228496\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which diagram shows the equation? ? View Available Hint(s) The Correct Answer and Explanation is: ChatGPT said: The given equation is:v=2t+4v = 2t + 4v=2t+4 This is a linear equation where: Step-by-step Analysis: Let\u2019s analyze each graph in the image: Top graph: Middle graph: \u2705 This matches the equation v=2t+4v = 2t + 4v=2t+4. Correct [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-228494","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228494","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=228494"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228494\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=228494"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=228494"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=228494"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}