{"id":228539,"date":"2025-06-07T11:00:43","date_gmt":"2025-06-07T11:00:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=228539"},"modified":"2025-06-07T11:00:45","modified_gmt":"2025-06-07T11:00:45","slug":"write-the-chemical-equation-of-formation-of-beryllium-phosphide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/07\/write-the-chemical-equation-of-formation-of-beryllium-phosphide\/","title":{"rendered":"WRITE THE CHEMICAL EQUATION OF FORMATION OF BERYLLIUM PHOSPHIDE"},"content":{"rendered":"\n<p>WRITE THE CHEMICAL EQUATION OF FORMATION OF BERYLLIUM PHOSPHIDE<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Chemical Equation of the Formation of Beryllium Phosphide:<\/h3>\n\n\n\n<p>3Be+2P\u2192Be3P23Be + 2P \\rightarrow Be_3P_23Be+2P\u2192Be3\u200bP2\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>Beryllium phosphide (Be\u2083P\u2082) is an inorganic compound formed from the elements beryllium (Be) and phosphorus (P). The chemical equation for its formation is:3Be+2P\u2192Be3P23Be + 2P \\rightarrow Be_3P_23Be+2P\u2192Be3\u200bP2\u200b<\/p>\n\n\n\n<p>This reaction involves a direct combination (synthesis) reaction between elemental beryllium and elemental phosphorus.<\/p>\n\n\n\n<p><strong>Valency and Stoichiometry:<\/strong><\/p>\n\n\n\n<p>To understand why the formula of beryllium phosphide is <strong>Be\u2083P\u2082<\/strong>, we must consider the valency of each element. Beryllium belongs to group 2 of the periodic table and typically forms <strong>Be\u00b2\u207a<\/strong> ions, as it loses two electrons to achieve a stable configuration. Phosphorus, on the other hand, belongs to group 15 and tends to form <strong>P\u00b3\u207b<\/strong> ions by gaining three electrons.<\/p>\n\n\n\n<p>To form a neutral compound, the charges must balance:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>3 Be\u00b2\u207a ions contribute a total charge of <strong>+6<\/strong><\/li>\n\n\n\n<li>2 P\u00b3\u207b ions contribute a total charge of <strong>\u22126<\/strong><\/li>\n<\/ul>\n\n\n\n<p>These charges balance perfectly, so the empirical formula is <strong>Be\u2083P\u2082<\/strong>.<\/p>\n\n\n\n<p><strong>Reaction Conditions:<\/strong><\/p>\n\n\n\n<p>The formation of beryllium phosphide generally requires high temperatures. This reaction typically occurs in a controlled environment like an inert atmosphere (e.g., argon) or under vacuum to prevent unwanted side reactions with oxygen or moisture.<\/p>\n\n\n\n<p><strong>Applications and Properties:<\/strong><\/p>\n\n\n\n<p>Be\u2083P\u2082 is a crystalline solid with semiconductor properties. It is studied for potential use in high-temperature electronics and optoelectronics, though its applications are limited due to the toxicity of beryllium compounds.<\/p>\n\n\n\n<p><strong>Safety Note:<\/strong><\/p>\n\n\n\n<p>Beryllium is highly toxic if inhaled or ingested. Proper safety precautions, including protective equipment and ventilation, are essential when handling beryllium or its compounds.<\/p>\n\n\n\n<p>In conclusion, the reaction of beryllium and phosphorus forms <strong>Be\u2083P\u2082<\/strong> through a straightforward synthesis reaction that balances the valency of the elements involved.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner7-297.jpeg\" alt=\"\" class=\"wp-image-228540\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>WRITE THE CHEMICAL EQUATION OF FORMATION OF BERYLLIUM PHOSPHIDE The Correct Answer and Explanation is: Chemical Equation of the Formation of Beryllium Phosphide: 3Be+2P\u2192Be3P23Be + 2P \\rightarrow Be_3P_23Be+2P\u2192Be3\u200bP2\u200b Explanation Beryllium phosphide (Be\u2083P\u2082) is an inorganic compound formed from the elements beryllium (Be) and phosphorus (P). The chemical equation for its formation is:3Be+2P\u2192Be3P23Be + 2P \\rightarrow [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-228539","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228539","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=228539"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228539\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=228539"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=228539"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=228539"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}