{"id":228833,"date":"2025-06-07T16:23:31","date_gmt":"2025-06-07T16:23:31","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=228833"},"modified":"2025-06-07T16:23:34","modified_gmt":"2025-06-07T16:23:34","slug":"determine-the-point-group-for-the-ideal-molecular-geometry-of-each-of-the-following-pcl4-pcl6-pcis-cos-14-dichlorobenzene-13-dichlorobenzene-and-a-tennis-ball-ignoring-printing-just-the-se","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/07\/determine-the-point-group-for-the-ideal-molecular-geometry-of-each-of-the-following-pcl4-pcl6-pcis-cos-14-dichlorobenzene-13-dichlorobenzene-and-a-tennis-ball-ignoring-printing-just-the-se\/","title":{"rendered":"Determine the point group for the ideal molecular geometry of each of the following: PCl4+, PCl6, PCIs, COS, 1,4-dichlorobenzene, 1,3-dichlorobenzene, and a tennis ball (ignoring printing, just the seams)"},"content":{"rendered":"\n

Determine the point group for the ideal molecular geometry of each of the following: PCl4+, PCl6, PCIs, COS, 1,4-dichlorobenzene, 1,3-dichlorobenzene, and a tennis ball (ignoring printing, just the seams)<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Here are the point groups<\/strong> for each molecule\/object followed by an explanation:<\/p>\n\n\n\n

    \n
  1. PCl\u2084\u207a<\/strong> \u2192 T_d<\/strong><\/li>\n\n\n\n
  2. PCl\u2086<\/strong> (assumed to be PCl\u2086\u207b) \u2192 O_h<\/strong><\/li>\n\n\n\n
  3. PCl\u2085<\/strong> \u2192 D\u2083h<\/strong><\/li>\n\n\n\n
  4. COS<\/strong> \u2192 C_\u221ev<\/strong><\/li>\n\n\n\n
  5. 1,4-dichlorobenzene<\/strong> \u2192 D\u2082h<\/strong><\/li>\n\n\n\n
  6. 1,3-dichlorobenzene<\/strong> \u2192 C\u2082v<\/strong><\/li>\n\n\n\n
  7. Tennis ball (ignoring print, just the seam)<\/strong> \u2192 D\u2082d<\/strong><\/li>\n<\/ol>\n\n\n\n
    \n\n\n\n

    Explanation:<\/h3>\n\n\n\n

    PCl\u2084\u207a<\/strong>: This ion has a tetrahedral<\/strong> geometry similar to CH\u2084, where phosphorus forms four bonds in a symmetric 3D shape. Tetrahedral structures belong to the T_d<\/strong> point group, which has high symmetry with multiple C\u2083 and C\u2082 axes and mirror planes.<\/p>\n\n\n\n

    PCl\u2086\u207b<\/strong>: Assuming the negative ion form (PCl\u2086\u207b), it adopts an octahedral<\/strong> geometry where phosphorus is surrounded by six chlorine atoms. Octahedral molecules belong to the O_h<\/strong> point group, the highest order point group for non-linear molecules, with several symmetry elements including inversion, multiple rotational axes, and mirror planes.<\/p>\n\n\n\n

    PCl\u2085<\/strong>: This molecule has a trigonal bipyramidal<\/strong> geometry. It has a C\u2083 axis along with three vertical mirror planes, classifying it under the D\u2083h<\/strong> point group.<\/p>\n\n\n\n

    COS<\/strong>: This linear molecule (Carbonyl Sulfide) is analogous to CO\u2082 in shape and symmetry. Linear molecules with different terminal atoms and a center of mass at one point belong to the C_\u221ev<\/strong> point group, which includes infinite rotation symmetry and an infinite number of mirror planes.<\/p>\n\n\n\n

    1,4-dichlorobenzene<\/strong>: The para-disubstituted benzene has a center of symmetry and multiple perpendicular mirror planes, fitting the D\u2082h<\/strong> point group.<\/p>\n\n\n\n

    1,3-dichlorobenzene<\/strong>: The meta isomer has less symmetry than the para form. It retains a single C\u2082 axis and vertical mirror planes, placing it in the C\u2082v<\/strong> point group.<\/p>\n\n\n\n

    Tennis ball<\/strong>: Ignoring print and focusing only on the seam, the tennis ball has D\u2082d<\/strong> symmetry \u2014 it has two perpendicular C\u2082 axes, a C\u2082 axis perpendicular to them, and diagonal mirror planes, matching the twisted D\u2082d group, often used to describe symmetric but chiral-like objects.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    Determine the point group for the ideal molecular geometry of each of the following: PCl4+, PCl6, PCIs, COS, 1,4-dichlorobenzene, 1,3-dichlorobenzene, and a tennis ball (ignoring printing, just the seams) The Correct Answer and Explanation is: Here are the point groups for each molecule\/object followed by an explanation: Explanation: PCl\u2084\u207a: This ion has a tetrahedral geometry […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-228833","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228833","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=228833"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228833\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=228833"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=228833"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=228833"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}