{"id":228958,"date":"2025-06-07T18:53:42","date_gmt":"2025-06-07T18:53:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=228958"},"modified":"2025-06-07T18:53:44","modified_gmt":"2025-06-07T18:53:44","slug":"write-the-lewis-structure-for-each-molecule-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/07\/write-the-lewis-structure-for-each-molecule-2\/","title":{"rendered":"Write the Lewis structure for each molecule."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Write the Lewis structure for each molecule. a. CH2O b. C2Cl4<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>a. CH\u2082O (Formaldehyde)<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>   H\n   |\nH\u2013C=O\n     ||\n     O\n<\/code><\/pre>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Explanation:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Formaldehyde (CH\u2082O) consists of one carbon (C), two hydrogen (H), and one oxygen (O) atom. Here&#8217;s how we draw its Lewis structure:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count total valence electrons:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon (Group 14): 4 electrons<\/li>\n\n\n\n<li>Hydrogen (Group 1): 1 electron \u00d7 2 = 2 electrons<\/li>\n\n\n\n<li>Oxygen (Group 16): 6 electrons<\/li>\n\n\n\n<li><strong>Total = 4 + 2 + 6 = 12 valence electrons<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Determine the central atom:<\/strong><br>Carbon is the central atom because it can form 4 bonds, while H and O typically form 1 and 2 bonds respectively.<\/li>\n\n\n\n<li><strong>Create single bonds between C and H, and C and O:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Each bond uses 2 electrons: 3 single bonds = 6 electrons used.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Distribute remaining electrons:<\/strong>\n<ul class=\"wp-block-list\">\n<li>6 electrons remain. Place them as lone pairs on oxygen.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Check octet rule:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon has only 6 electrons; to complete its octet, form a double bond with oxygen.<\/li>\n\n\n\n<li>Final bonding: 2 single bonds (C\u2013H), 1 double bond (C=O).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Final structure:<\/strong> Carbon forms two single bonds with H and a double bond with O. Oxygen has two lone pairs, satisfying the octet rule.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>b. C\u2082Cl\u2084 (Tetrachloroethylene)<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>   Cl     Cl\n    \\     \/\n     C = C\n    \/     \\\n  Cl       Cl\n<\/code><\/pre>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Explanation:<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Tetrachloroethylene has two carbon (C) atoms and four chlorine (Cl) atoms.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count total valence electrons:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon: 4 \u00d7 2 = 8 electrons<\/li>\n\n\n\n<li>Chlorine: 7 \u00d7 4 = 28 electrons<\/li>\n\n\n\n<li><strong>Total = 36 valence electrons<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Determine structure:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Carbon atoms form a double bond (C=C) in the center.<\/li>\n\n\n\n<li>Each carbon is also bonded to two chlorine atoms (4 single bonds total).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Assign lone pairs:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Chlorine atoms get 3 lone pairs each (6 electrons \u00d7 4 = 24 electrons).<\/li>\n\n\n\n<li>The double bond and single bonds account for 12 electrons (6 bonds \u00d7 2 electrons).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Octet rule:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Each atom satisfies the octet. Carbon atoms have 4 bonds each (8 electrons), chlorine has 1 bond and 3 lone pairs (also 8 electrons).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Final structure:<\/strong> Two central carbon atoms form a double bond, each bonded to two chlorine atoms.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">These Lewis structures illustrate correct electron pairing and bonding based on valence electron rules and the octet principle.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner4-663.jpeg\" alt=\"\" class=\"wp-image-228959\"\/><\/figure>\n\n\n","protected":false},"excerpt":{"rendered":"<p>Write the Lewis structure for each molecule. a. CH2O b. C2Cl4 The Correct Answer and Explanation is: a. CH\u2082O (Formaldehyde) Lewis Structure: mathematicaCopyEdit H | H\u2013C=O || O Explanation: Formaldehyde (CH\u2082O) consists of one carbon (C), two hydrogen (H), and one oxygen (O) atom. Here&#8217;s how we draw its Lewis structure: b. C\u2082Cl\u2084 (Tetrachloroethylene) Lewis [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-228958","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228958","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=228958"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/228958\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=228958"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=228958"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=228958"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}