{"id":229106,"date":"2025-06-08T02:18:43","date_gmt":"2025-06-08T02:18:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=229106"},"modified":"2025-06-08T02:18:45","modified_gmt":"2025-06-08T02:18:45","slug":"below-are-two-potential-methods-for-preparing-the-same-ether-but-only-one-of-them-successful-identify-the-successful-approach-naome-top-method-bottom-method-neither-method-it-is-a-trick-question","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/08\/below-are-two-potential-methods-for-preparing-the-same-ether-but-only-one-of-them-successful-identify-the-successful-approach-naome-top-method-bottom-method-neither-method-it-is-a-trick-question\/","title":{"rendered":"Below are two potential methods for preparing the same ether; but only one of them successful: Identify the successful approach: NaOMe Top method Bottom method Neither method, it is a trick question"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Below are two potential methods for preparing the same ether; but only one of them successful: Identify the successful approach: NaOMe Top method Bottom method Neither method, it is a trick question<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Williamson Ether Synthesis Overview:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Reagents: <strong>Alkoxide (RO\u207b)<\/strong> + <strong>Alkyl Halide (R&#8217;\u2013X)<\/strong><\/li>\n\n\n\n<li>Reaction: <strong>RO\u207b + R&#8217;\u2013X \u2192 R\u2013O\u2013R&#8217; + X\u207b<\/strong><\/li>\n\n\n\n<li>Condition: Works best when <strong>R&#8217;\u2013X<\/strong> is <strong>primary<\/strong>, because secondary or tertiary halides tend to undergo <strong>E2 elimination<\/strong> instead.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Analyzing the Options (Hypothetical Representation)<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Let\u2019s assume the question gives two reaction pathways, such as:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Top Method:<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">Reacting <strong>NaOMe<\/strong> with <strong>methyl bromide (CH\u2083Br)<\/strong><br>\u2192 Reaction: <strong>CH\u2083O\u207b + CH\u2083Br \u2192 CH\u2083OCH\u2083 (dimethyl ether)<\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Bottom Method:<\/strong><\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">Reacting <strong>NaOMe<\/strong> with <strong>tert-butyl bromide (t-BuBr)<\/strong><br>\u2192 Reaction: <strong>CH\u2083O\u207b + (CH\u2083)\u2083C\u2013Br \u2192 ?<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answer: Top Method is Successful<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Explanation<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The successful method for synthesizing ethers using sodium methoxide (NaOMe) is the <strong>top method<\/strong>, which involves reacting NaOMe with <strong>methyl bromide<\/strong>. This reaction proceeds via an <strong>SN2 mechanism<\/strong>, where the methoxide ion (CH\u2083O\u207b) acts as a nucleophile and directly displaces the bromide ion from the methyl group in a backside attack. Since methyl bromide is a <strong>primary alkyl halide<\/strong>, it is highly favorable for SN2 reactions. The result is a clean synthesis of <strong>dimethyl ether (CH\u2083OCH\u2083)<\/strong> with high yield and minimal side reactions.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In contrast, the <strong>bottom method<\/strong>, where NaOMe is reacted with <strong>tert-butyl bromide<\/strong>, fails to yield the ether product. This is because tert-butyl bromide is a <strong>tertiary alkyl halide<\/strong>, which is highly hindered and unsuitable for SN2 attack. Instead of substitution, the reaction favors <strong>E2 elimination<\/strong>, leading to the formation of <strong>isobutylene (2-methylpropene)<\/strong> rather than an ether. The bulky tert-butyl group prevents the methoxide from accessing the carbon center efficiently for nucleophilic substitution.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Therefore, the <strong>correct answer<\/strong> is: <strong>Top method<\/strong>.<br>The <strong>bottom method fails<\/strong> due to steric hindrance and competing elimination reactions.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This example underscores the importance of substrate selection in ether synthesis. Only <strong>primary alkyl halides<\/strong> should be used with strong nucleophiles like NaOMe in Williamson ether synthesis to avoid elimination and ensure high yields of the desired ether.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-125.jpeg\" alt=\"\" class=\"wp-image-229107\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Below are two potential methods for preparing the same ether; but only one of them successful: Identify the successful approach: NaOMe Top method Bottom method Neither method, it is a trick question The Correct Answer and Explanation is: Williamson Ether Synthesis Overview: Analyzing the Options (Hypothetical Representation) Let\u2019s assume the question gives two reaction pathways, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-229106","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229106","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=229106"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229106\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=229106"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=229106"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=229106"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}