{"id":229114,"date":"2025-06-08T02:24:06","date_gmt":"2025-06-08T02:24:06","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=229114"},"modified":"2025-06-08T02:24:09","modified_gmt":"2025-06-08T02:24:09","slug":"what-is-the-molar-mass-of-carbon-monoxide-co","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/08\/what-is-the-molar-mass-of-carbon-monoxide-co\/","title":{"rendered":"What is the molar mass of carbon monoxide (CO)"},"content":{"rendered":"\n

What is the molar mass of carbon monoxide (CO)? Atomic weight of carbon is 12 and oxygen is 16. Answer: g\/mol How many moles of CO gas if its mass is 65g? Answer: moles How many CO molecules are there in 65g of CO? Answer: x1024 molecules<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Answers:<\/strong><\/h3>\n\n\n\n
    \n
  • Molar mass of CO<\/strong> = 12 (C) + 16 (O) = 28 g\/mol<\/strong><\/li>\n\n\n\n
  • Moles of CO in 65g<\/strong> = 65\u00a0g28\u00a0g\/mol\\frac{65 \\text{ g}}{28 \\text{ g\/mol}}28\u00a0g\/mol65\u00a0g\u200b = 2.32 moles<\/strong><\/li>\n\n\n\n
  • Number of molecules in 65g CO<\/strong> = 2.32\u00d76.022\u00d710232.32 \\times 6.022 \\times 10^{23}2.32\u00d76.022\u00d71023 \u2248 1.40 \u00d7 10\u00b2\u2074 molecules<\/strong><\/li>\n<\/ul>\n\n\n\n
    \n\n\n\n

    Explanation<\/strong><\/h3>\n\n\n\n

    Carbon monoxide (CO) is a compound consisting of one carbon atom and one oxygen atom. To calculate its molar mass<\/strong>, we sum the atomic weights of its elements. The atomic weight of carbon is 12 g\/mol and that of oxygen is 16 g\/mol. Therefore, the molar mass of CO is: Molar mass of CO=12+16=28 g\/mol\\text{Molar mass of CO} = 12 + 16 = 28 \\text{ g\/mol}Molar mass of CO=12+16=28 g\/mol<\/p>\n\n\n\n

    This means one mole of CO weighs 28 grams.<\/p>\n\n\n\n

    To determine how many moles<\/strong> are present in 65 grams of CO, we use the formula: Moles=Given massMolar mass=6528\u22482.32 moles\\text{Moles} = \\frac{\\text{Given mass}}{\\text{Molar mass}} = \\frac{65}{28} \\approx 2.32 \\text{ moles}Moles=Molar massGiven mass\u200b=2865\u200b\u22482.32 moles<\/p>\n\n\n\n

    Moles are a measure of the number of particles (in this case, CO molecules). One mole contains Avogadro\u2019s number<\/strong> of particles, which is approximately: 6.022\u00d71023 particles\/mole6.022 \\times 10^{23} \\text{ particles\/mole}6.022\u00d71023 particles\/mole<\/p>\n\n\n\n

    To find the number of CO molecules<\/strong> in 65 grams, we multiply the number of moles by Avogadro\u2019s number: Number of molecules=2.32\u00d76.022\u00d71023\u22481.40\u00d71024 molecules\\text{Number of molecules} = 2.32 \\times 6.022 \\times 10^{23} \\approx 1.40 \\times 10^{24} \\text{ molecules}Number of molecules=2.32\u00d76.022\u00d71023\u22481.40\u00d71024 molecules<\/p>\n\n\n\n

    This large number reflects how many individual CO molecules exist even in relatively small masses of a substance. Understanding these conversions is fundamental in chemistry for analyzing reactions, predicting yields, and working with gases under different conditions.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    What is the molar mass of carbon monoxide (CO)? Atomic weight of carbon is 12 and oxygen is 16. Answer: g\/mol How many moles of CO gas if its mass is 65g? Answer: moles How many CO molecules are there in 65g of CO? Answer: x1024 molecules The Correct Answer and Explanation is: Answers: Explanation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-229114","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229114","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=229114"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229114\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=229114"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=229114"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=229114"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}