{"id":229256,"date":"2025-06-08T04:49:15","date_gmt":"2025-06-08T04:49:15","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=229256"},"modified":"2025-06-08T04:49:17","modified_gmt":"2025-06-08T04:49:17","slug":"what-is-the-condensed-structural-formula-for-3-isopropyl-2-hexene","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/08\/what-is-the-condensed-structural-formula-for-3-isopropyl-2-hexene\/","title":{"rendered":"What is the condensed structural formula for 3-isopropyl-2-hexene"},"content":{"rendered":"\n<p>What is the condensed structural formula for 3-isopropyl-2-hexene<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Condensed Structural Formula for 3-Isopropyl-2-hexene:<\/strong><\/h3>\n\n\n\n<p><strong>CH\u2083CH=C(CH(CH\u2083)\u2082)CH\u2082CH\u2083<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>To determine the <strong>condensed structural formula<\/strong> of <strong>3-isopropyl-2-hexene<\/strong>, we must understand its name using IUPAC rules, which reveal the structure of the compound step by step.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 1: Identify the parent chain<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The base name is <strong>hexene<\/strong>, which tells us:\n<ul class=\"wp-block-list\">\n<li>The compound is an <strong>alkene<\/strong> (has a carbon-carbon double bond).<\/li>\n\n\n\n<li>It contains <strong>six carbon atoms<\/strong> in the <strong>longest continuous chain<\/strong>.<\/li>\n\n\n\n<li>The double bond starts at <strong>carbon 2<\/strong> (as indicated by \u201c2-hexene\u201d).<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>So the <strong>main carbon chain<\/strong> looks like this:<br><strong>CH\u2083\u2013CH=CH\u2013CH\u2082\u2013CH\u2082\u2013CH\u2083<\/strong> (this is 2-hexene).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 2: Add the substituent<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>There is an <strong>isopropyl<\/strong> group on <strong>carbon 3<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>An <strong>isopropyl group<\/strong> is:<br><strong>\u2013CH(CH\u2083)\u2082<\/strong><br>(It has a central carbon bonded to two methyl groups and the main chain.)<\/p>\n\n\n\n<p>We now place this group on <strong>carbon 3<\/strong> of the chain. The parent chain numbering goes from left to right to keep the double bond at carbon 2 (the lowest possible number for the double bond).<\/p>\n\n\n\n<p>The backbone with carbon numbers:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>CH\u2083<\/li>\n\n\n\n<li>CH=<\/li>\n\n\n\n<li>C(CH(CH\u2083)\u2082)<\/li>\n\n\n\n<li>CH\u2082<\/li>\n\n\n\n<li>CH\u2083<\/li>\n<\/ol>\n\n\n\n<p>So, integrating all:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon 1: CH\u2083<\/li>\n\n\n\n<li>Carbon 2: CH=<\/li>\n\n\n\n<li>Carbon 3: C with isopropyl<\/li>\n\n\n\n<li>Carbon 4: CH\u2082<\/li>\n\n\n\n<li>Carbon 5: CH\u2083<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Final condensed structure:<\/strong><\/h4>\n\n\n\n<p><strong>CH\u2083CH=C(CH(CH\u2083)\u2082)CH\u2082CH\u2083<\/strong><\/p>\n\n\n\n<p>This is a linear representation, but it captures all atoms and their connectivity. Each segment shows how hydrogens are bonded compactly to carbon atoms. The central idea is to use parentheses to indicate branches or substituents like isopropyl groups.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner9-166.jpeg\" alt=\"\" class=\"wp-image-229257\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the condensed structural formula for 3-isopropyl-2-hexene The Correct Answer and Explanation is: Condensed Structural Formula for 3-Isopropyl-2-hexene: CH\u2083CH=C(CH(CH\u2083)\u2082)CH\u2082CH\u2083 Explanation To determine the condensed structural formula of 3-isopropyl-2-hexene, we must understand its name using IUPAC rules, which reveal the structure of the compound step by step. Step 1: Identify the parent chain So the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-229256","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229256","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=229256"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229256\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=229256"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=229256"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=229256"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}