{"id":229439,"date":"2025-06-08T07:40:18","date_gmt":"2025-06-08T07:40:18","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=229439"},"modified":"2025-06-08T07:40:20","modified_gmt":"2025-06-08T07:40:20","slug":"formula-of-sodium-metaaluminate-sodium-stannite-and-sodium-zincate-by-crisscross-method","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/06\/08\/formula-of-sodium-metaaluminate-sodium-stannite-and-sodium-zincate-by-crisscross-method\/","title":{"rendered":"Formula of sodium metaaluminate, sodium stannite, and sodium zincate by Crisscross method."},"content":{"rendered":"\n<p>Formula of sodium metaaluminate, sodium stannite, and sodium zincate by Crisscross method. Please answer quickly<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-1-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h6 class=\"wp-block-heading\">ChatGPT said:<\/h6>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Formulas Using the Crisscross Method<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Sodium metaaluminate<\/strong>: NaAlO\u2082<\/li>\n\n\n\n<li><strong>Sodium stannite<\/strong>: Na\u2082SnO\u2082<\/li>\n\n\n\n<li><strong>Sodium zincate<\/strong>: Na\u2082ZnO\u2082<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>The <strong>Crisscross method<\/strong> is a quick technique to determine the chemical formula of ionic compounds. It involves using the charges (oxidation states) of ions and swapping them to balance the compound&#8217;s overall charge.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Sodium metaaluminate (NaAlO\u2082)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ions involved<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Sodium ion: Na\u207a (charge +1)<\/li>\n\n\n\n<li>Metaaluminate ion: AlO\u2082\u207b (charge -1)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Since both ions have charges of equal magnitude and opposite sign, we just combine them in a 1:1 ratio:<\/p>\n\n\n\n<p><strong>\u2192 Na\u207a + AlO\u2082\u207b \u2192 NaAlO\u2082<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Sodium stannite (Na\u2082SnO\u2082)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ions involved<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Sodium ion: Na\u207a (charge +1)<\/li>\n\n\n\n<li>Stannite ion: SnO\u2082\u00b2\u207b (charge -2)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Apply the crisscross method:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The charge on sodium (1\u207a) becomes the subscript of SnO\u2082<\/li>\n\n\n\n<li>The charge on stannite (2\u207b) becomes the subscript of Na<\/li>\n<\/ul>\n\n\n\n<p><strong>\u2192 Na\u207a + SnO\u2082\u00b2\u207b \u2192 Na\u2082SnO\u2082<\/strong><\/p>\n\n\n\n<p>This balances the +2 charge from 2 Na\u207a with the \u20132 charge of one SnO\u2082\u00b2\u207b.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Sodium zincate (Na\u2082ZnO\u2082)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Ions involved<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Sodium ion: Na\u207a (charge +1)<\/li>\n\n\n\n<li>Zincate ion: ZnO\u2082\u00b2\u207b (charge -2)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Apply the crisscross method again:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The 1\u207a from Na becomes subscript for ZnO\u2082<\/li>\n\n\n\n<li>The 2\u207b from ZnO\u2082 becomes subscript for Na<\/li>\n<\/ul>\n\n\n\n<p><strong>\u2192 Na\u207a + ZnO\u2082\u00b2\u207b \u2192 Na\u2082ZnO\u2082<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<p>The crisscross method ensures the total positive and negative charges cancel each other out, giving a neutral compound. These formulas represent common forms of the oxyanions bonded with sodium in basic or industrial chemistry.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-31.jpeg\" alt=\"\" class=\"wp-image-229440\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Formula of sodium metaaluminate, sodium stannite, and sodium zincate by Crisscross method. Please answer quickly The Correct Answer and Explanation is: ChatGPT said: Formulas Using the Crisscross Method Explanation The Crisscross method is a quick technique to determine the chemical formula of ionic compounds. It involves using the charges (oxidation states) of ions and swapping [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-229439","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229439","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=229439"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/229439\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=229439"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=229439"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=229439"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}